/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Potential energy in a one-dimens... [FREE SOLUTION] | 91Ó°ÊÓ

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Potential energy in a one-dimensional crystal * * Calculate the potential energy, per ion, for an infinite 1 D ionic crystal with separation \(a\); that is, a row of equally spaced charges of magnitude \(e\) and alternating sign. Hint: The power-series expansion of \(\ln (1+x)\) may be of use.

Short Answer

Expert verified
The potential energy, per ion, for an infinite 1 D ionic crystal is 0.

Step by step solution

01

Simplification and assume constants

Let's denote the number of ions as \(n\). The charge of each ion is alternating and can be written as \((-1)^ne\). Let's assume all the constants including the Coulomb constant \(k\) and the charge \(e\) are 1 for simplification since they won't affect the final solution. This simplifies our calculation.
02

Determine potential energy between ions

The potential energy \(V\) between two ions can be calculated using Coulomb's Law, multiplying by \(-1\) if the charges are the same and \(1\) if the charges are different. Hence the potential energy \(V\) between ions \(n\) and \(m\) is \((-1)^{n+m}/|n-m|\).
03

Sum the total potential energy

We then sum the potential energy for every pair of ions to get the total potential energy. This can be done by summing over all integer pairs \((n, m)\) where \(n < m\). We can use the formula for the sum of an infinite geometric series \(1 + x + x^2 + ... = 1/(1-x)\), for |x| < 1. So the sum is \(2\ln (2)\).
04

Average the potential energy per ion

The exercise asks for the potential energy per ion. Hence we need to compute the average potential energy per ion, which gives the potential energy per ion in an infinite crystal. Since the sum of potential energy is \(2\ln (2)\), the potential energy per ion would be \(2\ln (2)/n\). But here \(n\) refers to an infinite number of ions, so we get \(0\) potential energy per ion in the infinite limit.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
In the context of crystals, understanding Coulomb's Law is pivotal. This fundamental principle governs the interactions between particles with electric charge. Put simply, it states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Mathematically, Coulomb's Law can be expressed as \( F = k \frac{q_1 q_2}{r^2} \), where \(F\) is the force, \(k\) is Coulomb's constant, \(q_1\) and \(q_2\) are the charges, and \(r\) is the separation distance between the charges. While the law focuses on force, it directly relates to potential energy, \(V\), which is the energy due to the positions of the charges relative to each other: \(V = -\frac{F}{q} \cdot r\) if \(F\) and \(q\) are considered of the same sign. Understanding this law is vital for analyzing the potential energy within ionic crystals, where charged ions arrange in a regular pattern and interact electromagnetically.

Infinite Geometric Series
When calculating potential energy in an infinite crystal structure, one often encounters a summation that forms an Infinite Geometric Series. This series is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio \(r\). The series looks like \(a + ar + ar^2 + ar^3 + ...\), with \(a\) being the first term.

The sum of an infinite geometric series can be infinitely large, but under certain conditions—specifically when the absolute value of the common ratio \(|r| < 1\)—the series converges to a finite value. This sum is given by the formula \(S = \frac{a}{1-r}\). The power of this formula allows us to solve for the potential energy in the crystal lattice, even with an infinite number of ions, because it sidesteps the need to sum an infinite number of terms individually. This simplifies the analysis considerably and provides a neat, finite value for the infinite lattice as seen in the exercise provided.
Potential Energy Calculation
The calculation of potential energy in an ionic crystal brings together Coulomb's Law and the properties of an infinite geometric series. It requires understanding the interactions of an infinite array of ions with alternating charges and applying mathematical techniques to account for an infinite sum.

In the step-by-step solution provided, potential energy is first considered between two individual ions using a simplified version of Coulomb's Law. By pairing up ions and then summing up the potential energies of all possible pairs within the crystal, we can establish the total potential energy of the system. Importantly, by employing the infinite geometric series, we extract a concise expression for this total potential energy.

Finally, to find the average potential energy per ion, which the original exercise asks for, we would typically divide the total potential by the number of ions. However, as the crystal is infinitely large, when you try to average the potential energy by dividing by an infinite number, the result interestingly approaches zero. This conveys a crucial concept in physics—while individual interactions in a large system can be complex and significant, the overall effect per particle can become negligible in an infinite system.

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Most popular questions from this chapter

Field from a hemisphere ** (a) What is the electric field at the center of a hollow hemispherical shell with radius \(R\) and uniform surface charge density \(\sigma\) ? (This is a special case of Problem \(1.12\), but you can solve the present exercise much more easily from scratch, without going through all the messy integrals of Problem 1.12.) (b) Use your result to show that the electric field at the center of a solid hemisphere with radius \(R\) and uniform volume charge density \(\rho\) equals \(\rho R / 4 \epsilon_{0}\)

Thundercloud You observe that the passage of a particular thundercloud overhead causes the vertical electric field strength in the atmosphere, measured at the ground, to rise to \(3000 \mathrm{~N} / \mathrm{C}\) (or \(\mathrm{V} / \mathrm{m})\). (a) How much charge does the thundercloud contain, in coulombs per square meter of horizontal area? Assume that the width of the cloud is large compared with the height above the ground. (b) Suppose there is enough water in the thundercloud in the form of \(1 \mathrm{~mm}\) diameter drops to make \(0.25 \mathrm{~cm}\) of rainfall, and that it is those drops that carry the charge. How large is the electric field strength at the surface of one of the drops?

Stable equilibrium in electron jelly ** The task of Exercise \(1.77\) is to find the equilibrium positions of two protons located inside a sphere of electron jelly with total charge \(-2 e\). Show that the equilibria are stable. That is, show that a displacement in any direction will result in a force directed back toward the equilibrium position. (There is no need to know the exact locations of the equilibria, so you can solve this problem without solving Exercise \(1.77\) first.)

Maximum field from a ring ** A charge \(Q\) is distributed uniformly around a thin ring of radius \(b\) that lies in the \(x y\) plane with its center at the origin. Locate the point on the positive \(z\) axis where the electric field is strongest.

(a) At each corner of a square is a particle with charge \(q\). Fixed at the center of the square is a point charge of opposite sign, of magnitude \(Q .\) What value must \(Q\) have to make the total force on each of the four particles zero? (b) With \(Q\) taking on the value you just found, show that the potential energy of the system is zero, consistent with the result from Problem 1.6.

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