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Work for a rectangle ** Two protons and two electrons are located at the corners of a rectangle with side lengths \(a\) and \(b\). There are two essentially different arrangements. Consider the work required to assemble the system, starting with the particles very far apart. Is it possible for the work to be positive for either of the arrangements? If so, how must \(a\) and \(b\) be related? You will need to solve something numerically.

Short Answer

Expert verified
Yes, the work can be positive for the vertical arrangement. For the work done to be positive, the distance \(a\) between like-charges must be less than the distance \(b\) between unlike-charges. This is because the work done is equal to the change in potential energy, and the potential energy is positive when like charges are brought close to each other.

Step by step solution

01

Calculate the work required for the Horizontal Arrangement

Consider the first arrangement where protons and electrons are alternately arranged on longer side (which is \(a\)). The work done in assembling this configuration is the amount of potential energy in this system. The potential energy \(PE_1\) between two charges is given by the formula \(k*Q*Q'/r\), where \(Q\) and \(Q'\) are the charges, \(r\) is the distance between them, and \(k\) is Coulomb's constant. Here, each pair of charges (proton-electron) contributes a potential energy of \(-k*|e|^2/a\) since the charges are opposite and the total potential energy is twice this amount or \(-2k*|e|^2/a\).
02

Calculate the work required for the Vertical Arrangement

Now consider the second arrangement where two protons are at one end and two electrons at the other end of the longer side (\(b\)) of the rectangle. The potential energy \(PE_2\) for this system includes contributions from pairs with unlike and like charges. The potential energy contribution from the unlike pairs is \(-k*|e|^2/b\) while that from the like pairs is \(k*|e|^2/a\). So, the total potential energy of the system is \(-2k*|e|^2/b + 2k*|e|^2/a\).
03

Compare the Work Done in Both Arrangements

Now, if the work done in the second arrangement is to be more than the first one, \(PE_2\) must be more than \(PE_1\). Equating the two and simplifying we get \(a>b\). Hence for the work or potential energy to be higher in the second arrangement, the distance between like charges must be shorter than that between unlike charges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is fundamental in understanding electrostatic interactions. It describes the force between two charges in space. According to the law, the electrostatic force \(F\) between two point charges is proportional to the product of their magnitudes \(Q\) and inversely proportional to the square of the distance \(r\) between them. Mathematically, this is represented as:\[F = k \frac{{|Q \, Q'|}}{{r^2}}\]where \(k\) is Coulomb's constant, approximately \(8.99 \times 10^9 \, N \, m^2/C^2\). The force is attractive if the charges are of opposite types (positive and negative) and repulsive if they are of the same type.
Understanding this concept is crucial for calculating potential energy in systems with multiple charges, such as protons and electrons in a rectangle, as outlined in the original exercise.
Proton-Electron Interactions
In a system involving protons and electrons, interactions are central to determining the total energy. A proton, being positively charged, and an electron, being negatively charged, will attract each other. This attraction is described by Coulomb's law and results in a potential energy that is negative, indicating a stable, bound state.
In the exercise, when arranging a proton and electron alternately along the rectangle's side, the system's energy is largely influenced by these negative potential energies. Each proton-electron pair contributes a negative amount to the total potential energy of the system, causing a net stabilization.
Charge Configuration
Charge configuration in an electric field refers to the particular arrangement of charges. The exercise provides two configurations: horizontal and vertical, determined by how protons and electrons are arranged at opposite corners of a rectangle.
  • In the horizontal configuration, each proton-electron pair along the longer side \(a\) contributes to a lower potential energy due to increased attraction, minimizing repulsion by ensuring that like charges (protons and protons or electrons and electrons) are further apart.
  • In the vertical setup, like charges are closer on the longer side \(b\), potentially increasing energy due to repulsive forces.
Choosing the ideal configuration depends on balancing these attractions and repulsions to achieve lower or higher potential energy, which relates to the work required to assemble the system.
Work Energy Theorem
The work-energy theorem connects the work done by forces on a system to its energy change. In an electrostatic context, the work required to assemble charges in a configuration is equal to the change in their electric potential energy.
In the provided exercise, calculating the work involves determining the total potential energy for different charge configurations and comparing these values:
  • The horizontal arrangement yields a certain negative potential energy, showing lesser work required due to more favorable proton-electron interactions.
  • The vertical arrangement increases potential energy, thus more work or energy input may be required to bring charges into the configuration, especially if \(a > b\).
For some configurations, depending on the distances \(a\) and \(b\), the work done can be positive, implying energy must be added to assemble the system. Using these concepts helps analyze and predict outcomes in various charge distributions.

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Most popular questions from this chapter

Oscillating on a line ** Two positive point charges \(Q\) are located at points \((\pm \ell, 0) .\) A particle with positive charge \(q\) and mass \(m\) is initially located midway between them and is then given a tiny kick. If it is constrained to move along the line joining the two charges \(Q\), show that it undergoes simple harmonic motion (for small oscillations), and find the frequency.

Potential energy of a cylinder A cylindrical volume of radius \(a\) is filled with charge of uniform density \(\rho\). We want to know the potential energy per unit length of this cylinder of charge, that is, the work done per unit length in assembling it. Calculate this by building up the cylinder layer by layer, making use of the fact that the field outside a cylindrical distribution of charge is the same as if all the charge were located on the axis. You will find that the energy per unit length is infinite if the charges are brought in from infinity, so instead assume that they are initially distributed uniformly over a hollow cylinder with large radius \(R\). Write your answer in terms of the charge per unit length of the cylinder, which is \(\lambda=\rho \pi a^{2}\). (See Exercise \(1.83\) for a different method of solving this problem.)

Gravity vs. electricity (a) In the domain of elementary particles, a natural unit of mass is the mass of a nucleon, that is, a proton or a neutron, the basic massive building blocks of ordinary matter. Given the nucleon mass as \(1.67 \cdot 10^{-27} \mathrm{~kg}\) and the gravitational constant G as \(6.67 \cdot 10^{-11} \mathrm{~m}^{3} /\left(\mathrm{kg} \mathrm{s}^{2}\right)\), compare the gravitational attraction of two protons with their electrostatic repulsion. This shows why we call gravitation a very weak force. (b) The distance between the two protons in the helium nucleus could be at one instant as much as \(10^{-15} \mathrm{~m}\). How large is the force of electrical repulsion between two protons at that distance? Express it in newtons, and in pounds. Even stronger is the nuclear force that acts between any pair of hadrons (including neutrons and protons) when they are that close together.

Concurrent field lines A semicircular wire with radius \(R\) has uniform charge density \(-\lambda\). Show that at all points along the "axis" of the semicircle (the line through the center, perpendicular to the plane of the semicircle, as shown in Fig. 1.43), the vectors of the electric field all point toward a common point in the plane of the semicircle. Where is this point?

Field from a semicircle * A thin plastic rod bent into a semicircle of radius \(R\) has a charge \(Q\) distributed uniformly over its length. Find the electric field at the center of the semicircle.

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