Chapter 6: Problem 8
A wire carrying current \(I\) runs down the \(y\) axis to the origin, thence out to infinity along the positive \(x\) axis. Show that the magnetic field in the quadrant \(x>0, y>0\) of the \(x y\) plane is given by $$ B_{z}=\frac{I}{c}\left(\frac{1}{x}+\frac{1}{y}+\frac{x}{y \sqrt{x^{2}+y^{2}}}+\frac{y}{x \sqrt{x^{2}+y^{2}}}\right) $$
Short Answer
Step by step solution
Understand the Setup
Biot-Savart Law Use
Analyze Current at \( y \)-Axis
Integrate for \( y \)-Axis Contribution
Analyze Current at \( x \)-Axis
Integrate for \( x \)-Axis Contribution
Combine Contributions and Simplify
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Biot-Savart Law
The law is expressed mathematically as:\[d\mathbf{B} = \frac{\mu_0}{4\pi} \frac{Id\mathbf{l} \times \mathbf{r}}{r^3},\]where:
- \( d\mathbf{B} \): Infinitesimal magnetic field contribution at the point.
- \( I \): Current through the wire.
- \( d\mathbf{l} \): Infinitesimal length of the wire in the direction of current.
- \( \mathbf{r} \): Distance vector from the wire segment to the point of consideration.
- \( r \): The magnitude of the distance vector \( \mathbf{r} \).
- \( \mu_0 \): The permeability of free space, a constant.
Current-carrying wire
There are several key points about the magnetic field created by a wire:
- The strength of the magnetic field is directly proportional to the current. More current means a stronger field.
- The field's intensity decreases as the distance from the wire increases.
- The configuration of the wire affects the field. For instance, the field lines are circular around a long straight wire, while they create loops in a coil.
Cross product in electromagnetism
In context of the Biot-Savart Law, we use the cross product to find the direction of the magnetic field created by a current element. The cross product is written as \( \mathbf{A} \times \mathbf{B} \) and its magnitude is given by \( |\mathbf{A}| |\mathbf{B}| \sin(\theta) \), where \( \theta \) is the angle between \( \mathbf{A} \) and \( \mathbf{B} \).
Some key characteristics of the cross product are:
- It is not commutative, meaning \( \mathbf{A} \times \mathbf{B} eq \mathbf{B} \times \mathbf{A} \).
- The result is zero if the vectors are parallel or one is zero, as they would not span a plane.
- It provides a vector that is orthogonal to the initial vectors, useful in three-dimensional vector analysis.