Chapter 4: Problem 18
Show that, if a battery of fixed emf \(\mathscr{E}\) and internal resistance \(R_{i}\) is connected to a variable external resistance \(R\), the maximum power is delivered to the external resistor when \(R=R_{i}\)
Short Answer
Expert verified
Maximum power is delivered when \( R = R_i \).
Step by step solution
01
Write the expression for power
The power delivered to the external resistor, \( R \), is given by \( P = I^2 R \), where \( I \) is the current. The current \( I \) in the circuit is given by Ohm's law: \( I = \frac{\mathscr{E}}{R + R_i} \). Therefore, the power can be written as: \[ P = \left(\frac{\mathscr{E}}{R + R_i}\right)^2 R. \]
02
Rewrite the power expression
Substitute the expression for current from Step 1 into the power formula: \[ P = \frac{\mathscr{E}^2 R}{(R + R_i)^2} \]. This formula relates the power delivered to the external resistance \( R \) to the EMF of the battery and both resistances.
03
Differentiate the power expression
To find the maximum power, differentiate \( P \) with respect to \( R \) and set the derivative equal to zero: \[ \frac{dP}{dR} = \frac{\mathscr{E}^2 (R_i - R)}{(R + R_i)^3} = 0. \]
04
Solve for the condition of maximum power
Solving \( \frac{\mathscr{E}^2 (R_i - R)}{(R + R_i)^3} = 0 \) gives \( R_i - R = 0 \), which implies \( R = R_i \).
05
Verify that this condition gives a maximum
To confirm that \( R = R_i \) gives a maximum, consider the second derivative \( \frac{d^2P}{dR^2} \). Calculating the second derivative, we check that it is negative when \( R = R_i \), indicating a maximum. The second derivative simplifies to \( \frac{d^2P}{dR^2} = \frac{-2\mathscr{E}^2}{(R + R_i)^3} \), which is negative.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ohm's Law
Ohm's Law is a fundamental principle used in the study of electric circuits. It defines the relationship between voltage, current, and resistance. The law is usually expressed in the form of the equation \( V = IR \), where:
- \( V \) represents voltage or electric potential difference measured in volts (V).
- \( I \) represents current, which is the flow of electric charge, measured in amperes (A).
- \( R \) represents resistance, which is a measure of how much a material opposes the flow of electric current, measured in ohms (Ω).
Electric Circuits
An electric circuit is a closed loop that allows electric current to flow from a voltage source to an electrical device and back. It typically consists of several key elements including:
- A power source, such as a battery or generator, that provides the electrical energy.
- Conductors, like wires, that connect different parts of the circuit and allow current to flow.
- Resistors or other components that control or use the electric current.
Power in Resistors
The power in resistors is a measure of how much energy is being converted into heat as electric current flows through them. Power is related to current and resistance by the formula \( P = I^2 R \), where \( P \) is the power in watts (W). This formula can also be expanded using Ohm's Law, giving the expression \( P = V^2 / R \) or \( P = VI \), depending on which circuit parameters are known.
- \( P = I^2 R \) shows how power increases with the square of the current, emphasizing why current is a critical factor in power calculations.
- \( P = V^2 / R \) demonstrates how power relates to voltage and resistance, useful for analyzing circuits where voltage is controlled.
- \( P = VI \) is often used when both voltage and current measurements are taken.