/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 Draw the circuit diagram of a fi... [FREE SOLUTION] | 91Ó°ÊÓ

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Draw the circuit diagram of a first-order \(R C\) highpass filter and give the expression for the half-power frequency in terms of the circuit components.

Short Answer

Expert verified
An RC highpass filter has a resistor first, followed by a capacitor to ground; its cutoff frequency is \( f_c = \frac{1}{2 \pi R C} \).

Step by step solution

01

Understanding the Components of the Circuit

A first-order RC highpass filter consists of a resistor (R) and a capacitor (C). The key is to understand how they are interconnected. The highpass filter allows signals with a frequency higher than the cutoff frequency to pass, while attenuating signals with lower frequencies.
02

Drawing the Circuit Diagram

To draw the circuit diagram for a first-order RC highpass filter, place the resistor first (R) connected to the input voltage source. Connect the capacitor (C) after the resistor, with the other end of the capacitor grounded. The output voltage is taken across the capacitor, between the junction of the resistor and the capacitor.
03

Determining the Half-Power Frequency

The half-power frequency, also known as the cutoff frequency, is determined by the formula: \[ f_c = \frac{1}{2 \pi R C} \]This frequency is where the output power drops to half of the maximum power.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First-order Circuit
A first-order circuit is one of the simplest types of electrical circuits. It is called "first-order" because it involves a single energy storage element, whether it is a capacitor or an inductor, resulting in a first-order differential equation that describes the circuit's behavior. In the context of an RC highpass filter, the circuit consists of one resistor (R) and one capacitor (C). The behavior of a first-order circuit can be easily analyzed using basic circuit analysis techniques.
  • The resistor limits the flow of current, while the capacitor stores and releases electrical energy.
  • This combination creates a circuit capable of filtering out particular frequencies of signals.
Understanding first-order circuits is crucial for analyzing more complex systems and serves as a foundation for further study in electrical engineering.
Circuit Diagram
A circuit diagram is a visual representation of an electrical circuit. For a first-order RC highpass filter, the layout of the components is quite simple. Here's how you can visualize it:
  • Connect a resistor (R) to one branch from the input voltage source.
  • From the other end of the resistor, connect a capacitor (C).
  • The other end of the capacitor is grounded, completing the path for current flow.
  • The output voltage is measured across the capacitor, drawing a connection to the junction between the resistor and the capacitor.
This diagram highlights the pathway through which the signal travels, demonstrating which components are responsible for processing the signal in the circuit. It helps in understanding the role each component plays in allowing higher frequencies to pass through, while impeding lower frequencies.
Cutoff Frequency
The cutoff frequency is a crucial parameter in the study of frequency response in circuits. For an RC highpass filter, it marks the frequency at which the output power drops to half of its maximum level. This frequency is crucial as it determines the point beyond which signals begin to pass through more freely. The formula for the cutoff frequency \( f_c \) is given by:\[ f_c = \frac{1}{2 \pi R C} \]
  • Here, \( R \) represents the resistance in ohms.
  • \( C \) represents the capacitance in farads.
  • \( \pi \) is a constant, approximately equal to 3.14159.
Understanding the cutoff frequency helps in designing circuits for specific applications, allowing engineers to tailor the circuit's response appropriately for filtering desired signals. This understanding is a key part of harnessing the power of RC circuits in real-world applications.
Electrical Engineering Education
Studying electrical engineering involves learning how to analyze and design a multitude of different circuits. It starts with fundamental concepts like the first-order circuit and gradually builds toward more complex subjects. By understanding simple circuits such as the RC highpass filter, students gain insight into the mechanisms of signal processing and filtering, which are vital in all forms of communications and signal processing applications.
  • Students learn to build, test, and evaluate circuits using theoretical knowledge and practical skills.
  • Critical thinking and problem-solving are enhanced by working through exercises and real-world applications.
  • Building a strong foundation in these concepts serves as the starting point for advanced studies in topics like digital signal processing, control systems, and telecommunications.
Electrical engineering education aims to provide a systematic approach to understanding how electrical systems work and prepare students for innovation and skilled practice in the field.

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Most popular questions from this chapter

Define the resonant frequency of a parallel \(R L C\) circuit. Explain why the impedance of a parallel \(R L C\) circuit is maximum at the resonant frequency. How does the quality factor for a parallel resonant circuit differ from that for a series resonant circuit?

Consider a system for which the output voltage is \(v_{o}(t)=v_{\text {in }}(t)+v_{\text {in }}\left(t-2 \times 10^{-3}\right)\). (In other words, the output equals the input plus the input delayed by \(2 \mathrm{~ms}\).) Given that the input voltage is \(v_{\text {in }}(t)=V_{\max } \cos (2 \pi f t)\), find an expression for the output voltage as a function of time. Then, find an expression for the transfer function of the system. Use MATLAB to plot the magnitude of the transfer function versus frequency for the range from 0 to \(2000 \mathrm{~Hz}\). Explain in terms of the phasors for \(v_{\text {in }}(t)\) and for \(v_{\text {in }}\left(t-2 \times 10^{-3}\right)\) why the transfer function has the magnitude it does for \(f=250 \mathrm{~Hz} .\) Repeat for \(f=500 \mathrm{~Hz}\)

Suppose we have a circuit for which the output voltage is the time derivative of the input voltage, as illustrated in Figure P6.16. For an input voltage given by \(v_{\text {in }}(t)=\) \(V_{\max } \cos \left(2 \pi f t+60^{\circ}\right)\), find an expression for the output voltage as a function of time. Then, find an expression for the transfer function of the differentiator. Plot the magnitude and phase of the transfer function versus frequency.

Define the resonant frequency and the quality factor of a series \(R L C\) circuit. Explain why the current in a series \(R L C\) circuit is maximum at the resonant frequency.

Suppose that four filters, having identical first-order lowpass transfer functions, are cascaded, what will be the rate at which the overall transfer function magnitude asymptote declines above the break frequency? Explain.

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