Chapter 4: Problem 15
A capacitance \(C\) is charged to an initial voltage \(V_{i}\). At \(t=0\), a resistance \(R\) is connected across the capacitance. Write an expression for the current. Then, integrate the current from \(t=0\) to \(t=\infty\), and show that the result is equal to the initial charge stored on the capacitance.
Short Answer
Step by step solution
Express the current
Set up the integral
Integrate the current
Evaluate the integral
Multiply to find total charge
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Capacitance
- \( Q \) is the charge stored on the capacitor, measured in Coulombs (C).
- \( C \) is the capacitance.
- \( V \) is the voltage across the capacitor.
Resistance
Exponential Decay
- \( V_{i} \) is the initial voltage.
- \( t \) is time.
- \( RC \) is the time constant of the circuit.
Ohm's Law
- \( I \) is the current through the resistor, measured in amperes (A).
- \( V \) is the voltage across the resistor.
- \( R \) is the resistance.