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Express the following decimal numbers in binary form and in binary-coded- decimal form: a \(17 ;\) b. \(8.5 ; c ^{*}9.75 ;\) d. \(73.03125\) \(e .67 .375\).

Short Answer

Expert verified
17: binary \(10001_2\), BCD \(0001\,0111\); 8.5: binary \(1000.1_2\), BCD \(1000\,0101\); 9.75: binary \(1001.11_2\), BCD \(1001\,0111\,0101\); 73.03125: binary \(1001001.00001_2\), BCD \(0111\,0011\,0000\,0011\,0001\,0010\,0101\); 67.375: binary \(1000011.011_2\), BCD \(0110\,0111\,0011\).

Step by step solution

01

Understanding Binary Representation

A binary number consists only of 0s and 1s and is based on powers of 2. To convert a decimal number to binary, we need to express the integer and the fractional parts separately as a sum of powers of 2.
02

Convert 17 to Binary

For the integer 17:1. Find the highest power of 2 less than or equal to 17, which is 16 (i.e., \(2^4\)).2. Subtracting 16 from 17 gives 1, which corresponds to \(2^0\).3. Therefore, 17 in binary is \(10001_2\).
03

Convert 8.5 to Binary

Convert the integer part 8:1. The highest power of 2 less than or equal to 8 is 8 itself (i.e., \(2^3\)).2. No subtraction necessary, so 8 in binary is \(1000_2\).Convert the fractional part 0.5:1. 0.5 equals \(2^{-1}\).2. Therefore, 8.5 in binary is \(1000.1_2\).
04

Convert 9.75 to Binary

Convert the integer part 9:1. 9 can be expressed as \(8 + 1\), which is \(2^3 + 2^0\).2. Hence, 9 in binary is \(1001_2\).Convert the fractional part 0.75:1. 0.75 can be expressed as 0.5 + 0.25 which are \(2^{-1}\) and \(2^{-2}\).2. Therefore, 0.75 in binary is \(.11_2\).Thus, 9.75 in binary is \(1001.11_2\).
05

Convert 73.03125 to Binary

Convert the integer part 73:1. 73 can be expressed as \(64 + 8 + 1\), which is \(2^6 + 2^3 + 2^0\).2. Hence, 73 in binary is \(1001001_2\).Convert the fractional part 0.03125:1. The fraction 0.03125 equals \(2^{-5}\).2. Therefore, 0.03125 in binary is \(.00001_2\).Thus, 73.03125 in binary is \(1001001.00001_2\).
06

Convert 67.375 to Binary

Convert the integer part 67:1. 67 can be expressed as \(64 + 3\), which is \(2^6 + 2^1 + 2^0\).2. Hence, 67 in binary is \(1000011_2\).Convert the fractional part 0.375:1. The fraction 0.375 can be expressed as 0.25 + 0.125 which are \(2^{-2}\) and \(2^{-3}\).2. Therefore, 0.375 in binary is \(.011_2\).Thus, 67.375 in binary is \(1000011.011_2\).
07

Understanding Binary-Coded Decimal (BCD)

In Binary-Coded Decimal, each decimal digit is represented as a four-bit binary number. For example, the decimal digit 2 is represented as \(0010\) in BCD.
08

Convert Decimal to BCD for 17

The decimal number 17 has digits 1 and 7.1. In BCD, 1 is \(0001\) and 7 is \(0111\).2. Therefore, 17 in BCD is \(0001\ 0111\).
09

Convert Decimal to BCD for 8.5

The decimal number 8.5 has digits 8 and 5.1. In BCD, 8 is \(1000\) and 5 is \(0101\).2. Therefore, 8.5 in BCD is \(1000\,0101\).
10

Convert Decimal to BCD for 9.75

The decimal number 9.75 has digits 9, 7, and 5.1. In BCD, 9 is \(1001\), 7 is \(0111\), and 5 is \(0101\).2. Therefore, 9.75 in BCD is \(1001\,0111\,0101\).
11

Convert Decimal to BCD for 73.03125

The decimal number 73.03125 has digits 7, 3, 0, 3, 1, 2, and 5.1. In BCD, 7 is \(0111\), 3 is \(0011\), 0 is \(0000\), 1 is \(0001\), 2 is \(0010\), and 5 is \(0101\).2. Therefore, 73.03125 in BCD is \(0111\,0011\,0000\,0011\,0001\,0010\,0101\).
12

Convert Decimal to BCD for 67.375

The decimal number 67.375 has digits 6, 7, 3, and 7.1. In BCD, 6 is \(0110\), 7 is \(0111\), and 3 is \(0011\).2. Therefore, 67.375 in BCD is \(0110\,0111\,0011\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

decimal to binary
Converting a decimal number to binary involves expressing the number in terms of powers of 2, using only the digits 0 and 1. It requires handling both the integer and fractional parts separately. Here's a simple breakdown:
  • For the **integer part**, identify the largest power of 2 less than or equal to the number. Subtract it, and repeat this process with the remainder until you reach zero.
  • For example, with the integer 17, the largest power of 2 is 16, or \(2^4\). Subtracting 16 from 17 leaves you with 1, which is \(2^0\). Therefore, 17 is represented as \(10001_2\) in binary.
  • For the **fractional part**, multiply by 2 and observe the integer portion. Record each step and continue the process with the remaining fraction.
  • As an illustration, converting 8.5 involves writing 8 as \(2^3\), resulting in \(1000_2\), and the fractional .5 is \(2^{-1}\), resulting in .1. Combined, 8.5 becomes \(1000.1_2\).
This method separates a decimal number neatly into binary notation, crucial for digital computing.
binary-coded decimal
Binary-Coded Decimal, or BCD, provides a method to represent decimal numbers where each digit is separately portrayed in binary.
  • Each decimal digit transforms into a 4-bit binary equivalent.
  • For instance, the digit 2 translates into \(0010\) in BCD format.
  • A decimal number like 17 is split into its digits 1 and 7, which become \(0001\) and \(0111\) respectively in BCD. Hence, 17 is represented as \(0001\,0111\) in BCD.
  • For numbers with a fractional component, such as 8.5, treat each digit separately again: 8 becomes \(1000\) and 5 becomes \(0101\), so in BCD it is \(1000\,0101\).
BCD is beneficial as it aligns with human-readable decimal numbers more intuitively while maintaining binary simplicity for computing applications.
fractional binary conversion
Converting a fractional decimal to binary requires a separate approach where the fractional part is handled distinctly from the integer part. Here’s how to manage fractional conversions:
  • The fractional component is converted by multiplying by 2 and observing the whole number part of the result, which becomes the next digit.
  • For example, to convert 0.75, multiply by 2 to get 1.5. The integer part, 1, becomes the next binary digit. Continue with the remaining .5; multiply by 2 again to achieve 1.0, stopping there since there's no remainder.
  • So, 0.75 in binary is represented as \(.11_2\).
  • By using this technique, you can convert decimals with complex fractional parts to binary, such as seen in the conversion of .375, where the steps lead to \(.011_2\).
This approach allows for a precise conversion of fractional parts, requisite in precise digital calculations and representations.

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Most popular questions from this chapter

A city council has four members, \(A, B, C,\) and \(D .\) Each member votes on a proposition (1 for yes, 0 for no). Find a minimized SOP logic expression having inputs \(A, B, C,\) and \(D\) and output \(X\) that is high when the vote is tied and low otherwise.

Use a truth table to prove the identity $$A+\bar{A} B=A+B$$

State three advantages of digital technology compared with analog technology.

Design a logic circuit to control electrical power to the engine ignition of a speed boat. Logic output \(I\) is to become high if ignition power is to be applied and is to remain low otherwise, Gasoline fumes in the engine compartment present a serious hazard of explosion. A sensor provides a logic input \(F\) that is high if fumes are present. Ignition power should not be applied if fumes are present. To help prevent accidents, ignition power should not be applied while the out drive is in gear. Logic signal \(G\) is high if the out drive is in gear and is low otherwise. A blower is provided to clear fumes from the engine compartment and is to be operated for five minutes before applying ignition power. Logic signal \(B\) becomes high after the blower has been in operation for five minutes. Finally. an emergency override signal \(E\) is provided so that the operator can choose to apply ignition power even if the blower has not operated for five minutes and if the out drive is in gear. but not if gasoline fumes are present. a. Prepare a truth table listing all combinations of the input signals \(B, E, F,\) and \(G .\) Also, show the desired value of \(I\) for each row in the table. b. Using the SOP approach, write a Boolean expression for \(I\). c. Using the POS approach, write a Boolean expression for \(I\) d. Try to manipulate the expressions of parts (b) and (c) to obtain a logic circuit having the least number of gates and inverters Use AND gates, OR gates, and inverters.

Why are NAND gates said to be sufficient for combinatorial logic? What other type of gate is sufficient?

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