Chapter 3: Problem 45
At \(t=0,\) the current flowing in a 0.5 -H induc tance is 4 A. What constant voltage must be applied to reduce the current to 0 at \(t=0.2 \mathrm{s}\) ?
Short Answer
Expert verified
The constant voltage required is \(-10 \text{V}\).
Step by step solution
01
Understand the Relationship Between Voltage, Inductance, and Current
In an inductor, the voltage across it, \( V \), the inductance, \( L \), and the rate of change of current, \( \frac{di}{dt} \), are related by the formula: \[ V = L \frac{di}{dt} \] where \( V \) is the voltage applied across the inductor, \( L \) is the inductance, and \( \frac{di}{dt} \) is the change in current with respect to time.
02
Calculate the Rate of Change of Current
We know the current changes from 4 A to 0 A over a period of \( 0.2 \) s. The rate of change of current, \( \frac{di}{dt} \), can be calculated using: \[ \frac{di}{dt} = \frac{\Delta i}{\Delta t} = \frac{0 - 4 \, \text{A}}{0.2 \, \text{s}} = -20 \, \text{A/s} \]
03
Apply the Voltage Formula to Find the Required Voltage
With \( L = 0.5 \, \text{H} \) and \( \frac{di}{dt} = -20 \, \text{A/s} \), we can substitute these into the formula \( V = L \frac{di}{dt} \), giving: \[ V = 0.5 \times (-20) = -10 \, \text{V} \]. The negative sign indicates that the voltage is applied in the direction to decrease the current.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inductance
Inductance is a fundamental property of an electrical component known as an inductor. It measures the ability of an inductor to store energy in a magnetic field when electric current flows through it. The SI unit of inductance is the henry (H). Inductors resist changes in current; thus, when the current flowing through an inductor changes, it generates a potential difference (voltage) across its terminals.
This opposes the change in current according to Lenz's Law. The equation describing this behavior is given by:
Understanding inductance is key to analyzing circuits where inductors are used, especially in filtering applications where they block high-frequency AC signals while allowing DC signals to pass.
This opposes the change in current according to Lenz's Law. The equation describing this behavior is given by:
- \[ V = L \frac{di}{dt} \]
- \( V \) is the voltage across the inductor,
- \( L \) is the inductance, and
- \( \frac{di}{dt} \) is the rate of change of current over time.
Understanding inductance is key to analyzing circuits where inductors are used, especially in filtering applications where they block high-frequency AC signals while allowing DC signals to pass.
Rate of Change of Current
The rate of change of current is a crucial concept when dealing with inductors because it directly influences the voltage across the inductor. It describes how quickly the current in a circuit is increasing or decreasing, expressed mathematically as \( \frac{di}{dt} \).
In our original exercise, we observed that the current dropped from 4 A to 0 A in 0.2 seconds. Here is how we calculate it:
In our original exercise, we observed that the current dropped from 4 A to 0 A in 0.2 seconds. Here is how we calculate it:
- Initial current, \( i_i \): 4 A
- Final current, \( i_f \): 0 A
- Time interval, \( \Delta t \): 0.2 s
- Using the formula: \( \frac{di}{dt} = \frac{\Delta i}{\Delta t} \)
- \( \Delta i = i_f - i_i = 0 - 4 = -4 \) A
- Thus, \( \frac{di}{dt} = \frac{-4}{0.2} = -20 \) A/s
Current Reduction in Inductor
Reducing the current in an inductor requires applying a voltage such that it opposes the current flow, effectively inducing a decay in the current. This process is guided by the formula:
In our scenario, we needed the current to change from 4 A to 0 A over 0.2 seconds. Through our calculations:
This aligns with the operational principle of inductors in AC and transient circuits, where managing the current flow is fundamental.
- \[ V = L \frac{di}{dt} \]
In our scenario, we needed the current to change from 4 A to 0 A over 0.2 seconds. Through our calculations:
- With \( L = 0.5 \) H and \( \frac{di}{dt} = -20 \) A/s, the required voltage was calculated as:
- \( V = 0.5 \times (-20) = -10 \) V
This aligns with the operational principle of inductors in AC and transient circuits, where managing the current flow is fundamental.