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The element shown in Figure \(P 1.25\) has \(v(t)=\) \(10 \mathrm{V},\) and \(i(t)=3 e^{-t}\) A. Compute the power for the circuit element. Find the energy transferred between \(t-0\) and \(t-\infty\). Is this energy absorbed by the element or supplied by it?

Short Answer

Expert verified
The element absorbs 30 J of energy.

Step by step solution

01

Compute Power

To find the power, we use the formula for power, which is the product of voltage and current: \[ p(t) = v(t) \times i(t) \] Substituting the given values, \( v(t) = 10 \text{ V} \) and \( i(t) = 3e^{-t} \text{ A} \): \[ p(t) = 10 \times 3e^{-t} = 30e^{-t} \text{ W} \] Thus, the power at any time \( t \) is \( 30e^{-t} \text{ W}.\)
02

Set Up the Integral for Energy

Energy transferred over a time period is given by the integral of power with respect to time: \[ W = \int_{0}^{\infty} p(t) \, dt \] Substitute the expression for power obtained earlier: \[ W = \int_{0}^{\infty} 30e^{-t} \, dt \] This integral represents the energy transferred from \( t = 0 \) to \( t = \infty \).
03

Compute the Integral for Energy

Calculate the integral: \[ W = 30 \int_{0}^{\infty} e^{-t} \, dt \] The integral of \( e^{-t} \) is \( -e^{-t} \), evaluated from 0 to \( \infty \): \[ W = 30 \left[ -e^{-t} \right]_{0}^{\infty} \] Evaluating the limits: \[ W = 30 \left( 0 - (-1) \right) = 30 \text{ J} \] Thus, the energy transferred is 30 J.
04

Determine Energy Absorption or Supply

Since the power calculated in Step 1 is positive, the element is absorbing energy. Thus, the energy of 30 J is absorbed by the element.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Voltage and Current
Voltage and current are fundamental concepts in circuits and are integral to understanding power and energy transfer. Voltage, denoted as \( v(t) \), is the electric potential difference between two points in a circuit. It is what "pushes" the electric charge through the circuit, measured in volts (V).
Current, represented as \( i(t) \), is the rate at which charge flows through a circuit and is measured in amperes (A). In this exercise, we have a constant voltage of 10 V, and a current that changes over time, given by \( i(t) = 3e^{-t} \). This exponential function indicates that the current decreases as time progresses, reflecting a common behavior in circuits where some form of dissipation or discharge occurs.

Power in a circuit is the product of voltage and current. It signifies how much energy is being transferred per unit time. The calculation \( p(t) = v(t) \times i(t) \) demonstrates this relationship by combining the voltage and current at any instant to compute the power. Here, substituting the given values gives \( p(t) = 30e^{-t} \text{ W} \), meaning the power also decreases over time, just like the current.
Exponential Functions in Circuits
Exponential functions are essential in modeling how current and voltage behave in specific electrical components, particularly those involving capacitors or inductors. Such functions describe processes that are not uniform over time, like charging and discharging or adding and removing energy from an element.

The term \( 3e^{-t} \) in the current function tells us that the current is an exponentially decaying function. This decay suggests the presence of an element, like a resistor-capacitor (RC) circuit, which naturally causes exponential behavior as it reacts to changes over time.
In our scenario, as time \( t \) goes to infinity, the current approaches zero, reflecting how capacitors discharge over time while resistive elements dissipate energy from the circuit.

This exponential current influences the power as well, driving the expression \( p(t) = 30e^{-t} \text{ W} \), which shows an exponential decay in power transfer.
Energy Transfer in Electrical Elements
Energy transfer in circuits is a pivotal concept, bridging the gap between theoretical concepts like voltage and current, and tangible outcomes such as energy absorption or supply. The energy transferred, represented by \( W \), is calculated by integrating the power function over time.

The integral \( W = \int_{0}^{\infty} 30e^{-t} \, dt \) captures the continuous transfer of energy from time \( t = 0 \) to \( t = \infty \). Solving it provided a result of 30 joules (J), representing the total energy absorbed by the circuit element.

This absorbed energy occurs because the power calculated in the initial step, \( 30e^{-t} \text{ W} \), is positive. Positive power indicates that energy is going from the circuit to the element. Therefore, the element is absorbing the energy rather than supplying it, reflecting the inherent loss or storage aspect common to real-world circuits.

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Most popular questions from this chapter

A power of \(100 \mathrm{W}\) is delivered to a certain resistor when the applied voltage is \(100 \mathrm{V}\) Find the resistance. Suppose that the voltage is reduced by 10 percent (to \(90 \mathrm{V}\) ). By what percentage is the power reduced? Assume that the resistance remains constant.

Sketch the diagram of a circuit that contains a \(5-\Omega\) resistor, a \(10-V\) voltage source, and a voltage-controlled voltage source having a gain constant of \(0.5 \mathrm{V} / \mathrm{V}\), Assume that the voltage across the resistor is the control voltage for the controlled source. Place all three elements in series. Several answers are possible, depending on the polarities chosen for the sources and the control voltage.

The ends of a length of wire are labeled a and b. If the current in the wire is \(i_{0 b}=-3 A\), are electrons moving toward a or \(b\) ? How much charge passes through a cross section of the wire in 3 seconds?

We have a circuit element with terminals \(a\) and \(b\). Furthermore, the element has \(v_{a b}=\) \(5 \mathrm{V}\) and \(i_{a b}=2 \mathrm{A}\). Over a period of \(10 \mathrm{sec}\)onds, how much charge moves through the element? If electrons carry the charge, which terminal do they enter? How much energy is transferred? Is it delivered to the clement or taken from it?

Suppose that, in the fluid-flow analogy for an electrical circuit, the analog of electrical current is volumetric flow rate with units of \(\mathrm{cm}^{3} / \mathrm{s}\). For a proper analogy to electrical circuits, must the fluid be compressible or incompressible? Must the walls of the pipes be elastic or inelastic? Explain your answers.

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