/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 A box of mass \(m\) slides down ... [FREE SOLUTION] | 91影视

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Chapter 6: Problem 3

A box of mass \(m\) slides down a frictionless inclined plane of length \(L\) and vertical height \(h .\) What is the change in its gravitational potential energy? (A) \(-m g L\) (B) \(-m g h\) (C) \(-m g L / h\) (D) \(-m g h / L\)

Short Answer

Expert verified
(B) \(-m g h\)

Step by step solution

01

Identify the formula for gravitational potential energy

Firstly, it's important to know that the formula for gravitational potential energy (\(PE\) or \(U\)) is given by \( PE = mgh \), where: - \(m\) is the mass of the object - \(g\) is the acceleration due to gravity - \(h\) is the height above the reference point
02

Apply the formula to calculate the change in gravitational potential energy

By substituting the given values into the formula we get that \( PE = mgh \). The question asks for the change in gravitational potential energy. Since the box is sliding downwards, it's losing potential energy. Therefore, the change will be negative, making the final equation \( \Delta PE = -mgh \).

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Most popular questions from this chapter

A force of \(200 \mathrm{~N}\) is required to keep an object sliding at a constant speed of \(2 \mathrm{~m} / \mathrm{s}\) across a rough floor. How much power is being expended to maintain this motion? (A) \(50 \mathrm{~W}\) (B) \(100 \mathrm{~W}\) (C) \(200 \mathrm{~W}\) (D) \(400 \mathrm{~W}\)

While a person lifts a book of mass \(2 \mathrm{~kg}\) from the floor to a tabletop, \(1.5 \mathrm{~m}\) above the floor, how much work does the gravitational force do on the book? (A) \(-30 \mathrm{~J}\) (B) \(-15 J\) (C) \(\mathrm{OJ}\) (D) \(15 \mathrm{~J}\)

A block of mass 3.5 kg slides down a frictionless inclined plane of length \(6.4 \mathrm{~m}\) that makes an angle of \(30^{\circ}\) with the horizontal. If the block is released from rest at the top of the incline, what is its speed at the bottom? (A) \(5.0 \mathrm{~m} / \mathrm{s}\) (B) \(6.4 \mathrm{~m} / \mathrm{s}\) (C) \(8.0 \mathrm{~m} / \mathrm{s}\) (D) \(10 \mathrm{~m} / \mathrm{s}\)

A force \(\mathbf{F}\) of strength \(20 \mathrm{~N}\) acts on an object of mass \(3 \mathrm{~kg}\) as it moves a distance of \(4 \mathrm{~m}\). If \(\mathbf{F}\) is perpendicular to the \(4 \mathrm{~m}\) displacement, the work it does is equal to (A) \(0 \mathrm{~J}\) (B) \(60 \mathrm{~J}\) (C) \(80 \mathrm{~J}\) (D) \(600 \mathrm{~J}\)

Under the influence of a force, an object of mass \(4 \mathrm{~kg}\) accelerates from \(3 \mathrm{~m} / \mathrm{s}\) to \(6 \mathrm{~m} / \mathrm{s}\) in \(8 \mathrm{~s}\). How much work was done on the object during this time? (A) \(27 \mathrm{~J}\) (B) \(54 J\) (C) \(72 \mathrm{~J}\) (D) \(96 \mathrm{~J}\)
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