Chapter 4: Problem 8
A soccer ball, at rest on the ground, is kicked with an initial velocity of \(10 \mathrm{~m} / \mathrm{s}\) at a launch angle of \(30^{\circ} .\) Calculate its total flight time, assuming that air resistance is negligible. (A) \(0.5 \mathrm{~s}\) (B) \(1 \mathrm{~s}\) (C) \(2 \mathrm{~s}\) (D) \(4 \mathrm{~s}\)
Short Answer
Step by step solution
Identify given values
Calculate vertical velocity
Calculate time of flight
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Kinematics
- Horizontal Motion: It maintains a constant velocity, as there is no acceleration in this direction (ignoring air resistance).
- Vertical Motion: It is influenced by gravity, causing the ball to accelerate downwards at a rate of approximately -9.8 m/s².
Initial Velocity
- Horizontal Component: It affects how far the ball will travel. It is calculated by using the cosine of the launch angle: \(v_{0x} = v_0 \cos(\theta)\).
- Vertical Component: It determines how high the ball will go and helps in finding the time of flight. We calculate it using the sine of the launch angle: \(v_{0y} = v_0 \sin(\theta)\). In our case, \(v_{0y} = 10 \cdot \sin(30^{\circ}) = 5 \text{ m/s}\).
Launch Angle
- A larger angle (closer to 90°) increases the time the object spends in the air, allowing it to reach a higher altitude.
- A smaller angle increases the range, meaning the object will travel further horizontally if initial velocity is kept constant.