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A block attached to an ideal spring undergoes simple harmonic motion about its equilibrium position \((x=0)\) with amplitude \(A .\) What fraction of the total energy is in the form of potential energy when the block is at position \(x=\frac{1}{4}\) ? (A) \(\frac{1}{16}\) (B) \(\frac{1}{4}\) (C) \(\frac{3}{4}\) (D) \(\frac{15}{16}\)

Short Answer

Expert verified
The fraction of the total energy that is in the form of potential energy when the block is at position \(x = \frac{A}{4}\) is \(\frac{1}{16}\) . Thus, the correct choice is (A) \(\frac{1}{16}\).

Step by step solution

01

Determine the total energy

The total energy of the system in simple harmonic motion is constant and is given by the potential energy at the point of maximum displacement or amplitude \(A\). That is, \[ E_{total} = PE_{max} = \frac{1}{2}kA^2 \]
02

Calculate the potential energy at \(x = \frac{A}{4}\)

Substitute \(x\) with \(\frac{A}{4}\) in the formula for potential energy: \[PE = \frac{1}{2}k\left(\frac{A}{4}\right)^2 = \frac{1}{2}k\frac{A^2}{16} = \frac{1}{32}kA^2 \]
03

Find the ratio of potential energy at \(x = \frac{A}{4}\) to the total energy

The fraction of the total energy that is in the form of potential energy when the block is at position \(x = \frac{A}{4}\) is the ratio of \(PE\) at \(x = \frac{A}{4}\) to the total energy. So, \[ Fraction = \frac{PE}{E_{total}} =\frac{\frac{1}{32}kA^2}{\frac{1}{2}kA^2} =\frac{1}{16}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simple Harmonic Motion Energy
Understanding the energy in simple harmonic motion (SHM) is crucial for grasping the dynamics of oscillating systems such as springs and pendulums. In SHM, energy constantly transforms between kinetic and potential forms, but the total mechanical energy remains constant if we ignore external forces like friction.

In the context of a mass-spring system, when the oscillating object moves through its equilibrium position, the energy is purely kinetic (\( KE = \frac{1}{2}mv^2 \) where m is the mass and v is the velocity at equilibrium). At this point, there’s no potential energy because the spring is neither compressed nor stretched.

Conversely, at the amplitude of motion (\( x = A \) or \( x = -A \)), the kinetic energy is zero because the mass momentarily stops before reversing direction. Here, all the system's energy is stored as potential energy in the spring (\( PE = \frac{1}{2}kx^2 \), with k being the spring constant and x the displacement). By conserving energy, we can relate the potential energy at any other point to this maximum potential energy and thereby to the total energy of the system.
Potential Energy in Simple Harmonic Motion
Potential energy in simple harmonic motion is determined by the position of the oscillating object relative to its equilibrium. For a spring-mass system, this is governed by Hooke's law, which states that the force exerted by the spring is proportional to the displacement from equilibrium and acts in the opposite direction (\( F = -kx \)).

The potential energy at a displacement x is given by the equation \( PE = \frac{1}{2}kx^2 \). At the maximum displacement (\( x = A \) or \( x = -A \) where A is the amplitude), the potential energy is also at a maximum, \( PE_{max} = \frac{1}{2}kA^2 \).

It's important to note that \(the potential energy is proportional to the square of the displacement\). This relationship means that when the block in our problem is at \( x = \frac{A}{4} \), the potential energy is not \( \frac{1}{4} \), but \( \frac{1}{16} \), of the maximum potential energy; indicating how the relation is non-linear and how the potential energy portion of the total energy decreases rapidly as the block moves towards the equilibrium.
AP Physics 1 Exam Preparation
Preparing for the AP Physics 1 exam involves a solid understanding of fundamental physics concepts, including simple harmonic motion and energy conservation. Students should focus on mastering the qualitative and quantitative aspects of physics principles to tackle both conceptual questions and numerical problems efficiently.

To excel in this subject area, students should:
  • Deeply understand the core concepts and recognize the characteristics of simple harmonic motion, such as the periodic nature, restoration forces, and energy transformations.
  • Develop problem-solving strategies, like identifying knowns and unknowns, visualizing the problem through diagrams, and applying relevant physics equations systematically.
  • Practice extensively with a variety of problems, especially those that blend multiple concepts together.
  • Engage in active revision by going over practice problems, using flashcards, and participating in study groups to discuss challenging topics.
  • Simulate test conditions by doing full-length timed practice exams and reviewing AP-exam specific strategies to manage time and approach multiple-choice and free-response questions effectively.
By combining these strategies with a healthy study routine and seeking help when needed, students can enhance their physics skills, build confidence, and increase their chances of performing well on the AP Physics 1 exam.

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