/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 A 2 \(\mathrm{kg}\) mass is atta... [FREE SOLUTION] | 91Ó°ÊÓ

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A 2 \(\mathrm{kg}\) mass is attached to a massless, 0.5 \(\mathrm{m}\) string and is used as a simple pendulum by extending it to an angle \(\theta=5^{\circ}\) and allowing it to oscilate. Which of the following changes will change the period of the pendulum? Select two answers. (A) Replacing the mass with a 1 kg mass (B) Changing the initial extension of the pendulum to a \(10^{\circ}\) angle (C) Replacing the string with a 0.25 \(\mathrm{m}\) string (D) Moving the pendulum to the surface of the Moon

Short Answer

Expert verified
The changes that will alter the period of the pendulum are (C) replacing the string with a 0.25 m string and (D) moving the pendulum to the surface of the Moon.

Step by step solution

01

Evaluate Option A

Option (A) suggests replacing the mass with a 1 kg mass. But looking at the formula for the period of a pendulum, you will notice that mass is not a factor. The mass of the pendulum does not affect its period. Thus, this change will not alter the period.
02

Evaluate Option B

Option (B) speaks of changing the initial extension of the pendulum to a \(10^{\circ}\) angle. However, as long as the angle is small, the period of the pendulum is independent of the initial angle (this is an approximation called the small-angle approximation). Therefore, this change will also not affect the period.
03

Evaluate Option C

Option (C) proposes replacing the string with a 0.25 m string. Referring back to the formula for the period, \(T = 2\pi\sqrt{\frac{L}{g}}\), it can be seen that the length \(L\) of the string significantly influences the period of the pendulum. So, changing the length of the string will indeed change the period of the pendulum. Therefore, this option is correct.
04

Evaluate Option D

Option (D) suggests moving the pendulum to the surface of the Moon. As seen in the formula, the period is influenced by the gravitational acceleration \(g\). The value of \(g\) on the Moon is different from its value on Earth. So, changing the location from Earth to the Moon would alter the gravitational force acting on the pendulum, and thus the period of the pendulum will change. This option is also correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simple Pendulum
Imagine a mass hanging from a string and swinging back and forth, like a child on a swing set. This is a classic example of a simple pendulum. A simple pendulum consists of a heavy point mass (called a 'bob') suspended by a massless and unstretchable string or rod. When pulled to one side and released, it swings back and forth in a regular, repetitive motion known as harmonic motion.

One of the most important characteristics of a simple pendulum is its period, which is the time it takes to complete one full swing, from one side to the other and back again. The period does not depend on the mass of the bob or the amplitude of the swing if it's a small angle, but it is directly affected by the length of the pendulum and the gravitational acceleration of the environment in which it is swinging. A crucial point for students to remember is that regardless of whether the pendulum holds a 2 kg mass or a 1 kg mass, the period will remain constant, shedding light on why option A does not affect the pendulum's period.
Gravitational Acceleration
Gravity is the force that pulls objects towards each other, and gravitational acceleration is the rate at which objects accelerate towards the Earth due to gravity. On Earth, this value is approximately 9.81 meters per second squared (9.81 m/s^2). However, this value is not a universal constant; it varies on other planets and celestial bodies. For instance, the Moon has a much smaller gravitational acceleration, at about 1.62 m/s^2.

The effect of gravitational acceleration on the period of a simple pendulum is outlined in the formula T = 2pisqrt{frac{L}{g}}, where T is the period, L is the length of the pendulum, and g is the gravitational acceleration. When students consider moving the pendulum to the Moon's surface (option D), they need to be aware that this change significantly alters the gravitational acceleration, impacting the period. That's the reason why relocating a pendulum to the Moon would change its period, providing a practical context for understanding how gravitational forces influence pendulum motion.
Small-Angle Approximation
The small-angle approximation is a crucial simplification used in physics when dealing with pendulums. It states that for angles of less than approximately 10 degrees, the sine of the angle in radians is roughly equal to the angle itself when measured in radians. This is mathematically represented as sin theta ~ theta (for theta in radians).

The small-angle approximation allows us to simplify the formulas that describe a pendulum's behavior because the motion's complexity at larger angles requires more complicated mathematics to accurately model. For instance, when evaluating option B – whether changing the initial extension of the pendulum to a 10 degrees angle alters the period – the small-angle approximation tells us this change should not affect the period. This theoretical assumption underlines the applicability of the small-angle approximation for simple harmonic motion and elucidates why option B in the exercise does not impact the pendulum's periodicity.

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