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A person on a bicycle is to coast down a ramp of height \(h\) and then pass through a circular loop of radius \(r\). What is the smallest value of \(h\) for which the cyclist will complete the loop without falling? (Ignore the kinetic energy of the spinning wheels.)(answer check available at lightandmatter.com)

Short Answer

Expert verified
The smallest height \( h \) is \( \frac{5}{2}r \).

Step by step solution

01

Understanding the Problem

We're tasked with finding the minimum height \( h \) from which a cyclist can coast down and successfully complete a loop of radius \( r \). The cyclist should have enough gravitational potential energy at height \( h \) to overcome the loop's gravitational force at the top.
02

Analyzing Physical Principles

For the cyclist to complete the loop, they must have enough speed at the top to maintain contact with the loop. The minimum speed for this is when the gravitational force equals the necessary centripetal force: \( \frac{mv^2}{r} = mg \), simplifying to \( v = \sqrt{rg} \).
03

Applying Energy Conservation

Initially, the cyclist has gravitational potential energy \( E_p = mgh \). At the top of the loop, this is converted into kinetic energy \( E_k = \frac{1}{2}mv^2 \) and potential energy \( 2mgr \) (since the cyclist is at height \( 2r \)). By conservation of energy, \( mgh = \frac{1}{2}mv^2 + 2mgr \).
04

Solving for Minimum Height

Substitute \( v = \sqrt{rg} \) from the centripetal condition into the energy equation: \( mgh = \frac{1}{2}m(rg) + 2mgr \). Simplifying, \( mgh = \frac{1}{2}mgr + 2mgr = \frac{5}{2}mgr \). Solving for \( h \), we get \( h = \frac{5}{2}r \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Energy
In physics, the principle of conservation of energy is a crucial concept explaining how energy is neither created nor destroyed in an isolated system. Instead, energy can only change forms. This idea is essential to understand the motion of objects, like a cyclist coasting down a ramp and through a loop.

When the cyclist is at the top of the ramp, they possess gravitational potential energy due to their height. As they roll down the ramp, this potential energy converts into kinetic energy, providing the speed needed to complete the loop. At any point in their path, the total energy - the sum of kinetic and potential energy - remains constant.
  • The initial energy at the top of the ramp is purely potential, given by the formula: \( E_p = mgh \).
  • At the top of the loop, their energy is a mix of kinetic \( E_k = \frac{1}{2}mv^2 \) and potential energy, due to the loop's height \( E_p = 2mgr \).
The key takeaway is that at every point from the ramp to the loop, energy transforms but its total value stays the same.
Centripetal Force
A cyclist navigating a loop faces centripetal force, which is the inward force required to keep them moving along a circular path. This force is vital to ensure the cyclist completes the loop without falling. The need for centripetal force arises because any object traveling along a curve experiences a change in direction that constitutes acceleration.

For the cyclist to remain on track through the loop, the gravitational force at the very top must match the required centripetal force. This condition ensures that the cyclist doesn't simply fall off due to gravity. Mathematically, this is expressed as:
  • The centripetal force required is: \( \frac{mv^2}{r} \)
  • Equating this to gravitational force gives: \( mg = \frac{mv^2}{r} \)
Solving provides the minimum speed at the top: \( v = \sqrt{rg} \). This speed ensures the cyclist has just enough force to stay in contact with the loop.
Gravitational Potential Energy
Gravitational potential energy refers to the energy an object possesses because of its position in a gravitational field, typically relative to the Earth's surface. This form of energy is a function of three key factors: mass, gravitational pull, and height.

In our scenario, the cyclist perched atop the ramp possesses maximum potential energy given by \( E_p = mgh \). This height \( h \) determines how much energy is available to convert into kinetic energy to power through the loop.
  • Initially: Potential energy is \( mgh \).
  • At the top of the loop, at a height \( 2r \), potential energy becomes \( 2mgr \).
The conversion efficiency of this potential energy into kinetic energy is what dictates the speed and success of the cyclist's loop maneuver. It illustrates the remarkable interplay of energy forms that underlie classic mechanics problems.

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