/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 A plane is flown in a loop-the-l... [FREE SOLUTION] | 91Ó°ÊÓ

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A plane is flown in a loop-the-loop of radius \(1.00 \mathrm{~km}\). The plane starts out flying upside-down, straight and level, then begins curving up along the circular loop, and is right-side up when it reaches the top. (The plane may slow down somewhat on the way up.) How fast must the plane be going at the top if the pilot is to experience no force from the seat or the seatbelt while at the top of the loop? (answer check available at lightandmatter.com)

Short Answer

Expert verified
The plane must be traveling at 99 m/s at the top of the loop.

Step by step solution

01

Analyzing the Forces

At the top of the loop, the force that the pilot experiences from the seat or seatbelt must be zero. This means the only force acting on the pilot is gravitational force.
02

Applying Newton's Second Law

At the top of the loop, the gravitational force is providing the necessary centripetal force. According to Newton's second law, this can be expressed as:\[ mg = rac{mv^2}{r} \]where \(m\) is the mass of the plane, \(v\) is the velocity at the top of the loop, \(g\) is the acceleration due to gravity (approximately \(9.8 \, \text{m/s}^2\)), and \(r\) is the radius of the loop.
03

Solving for Velocity

Canceling out the mass \(m\) from both sides of the equation in Step 2, we get:\[ g = rac{v^2}{r} \]Solving for \(v\), we obtain:\[ v = \sqrt{gr} \]
04

Substituting Known Values

Substitute the known values \(g = 9.8 \, \text{m/s}^2\) and \(r = 1000 \, \text{m}\) into the expression found in Step 3:\[ v = \sqrt{9.8 \times 1000} \]
05

Calculating the Velocity

Compute the value of \(v\):\[ v = \sqrt{9800} = 99 \, \text{m/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law is a fundamental concept of physics, often summarized by the equation \( F = ma \). In this scenario, it tells us how forces affect the motion of objects. Here, \( F \) is the net force acting on an object, \( m \) is the mass, and \( a \) is the acceleration.
For a plane in a loop, the key insight is that acceleration happens towards the center of the circular path; this is called centripetal acceleration.
  • The net force causing this acceleration is the gravitational force when the pilot is at the top of the loop.
  • Newton's Second Law helps relate this gravitational force to the centripetal force needed for circular motion.
This means, at the top of the loop, gravity is responsible for keeping the airplane moving in a circular path. This is why the expression \( mg = \frac{mv^2}{r} \) was used.
It essentially shows that the gravitational pull provides the necessary force to keep the plane looped in motion. Understanding this helps explain how forces affect motion during circular paths.
Centripetal Force
Centripetal force is essential when discussing circular motion, as it acts towards the center of the circular path. It is not an individual force but results from the net force directed inward, ensuring the object travels in a circle.
  • In the context of the airplane performing a loop, the required centripetal force at any point is what maintains its circular trajectory.
  • Equation: The centripetal force needed for circular motion is given by \( F_{c} = \frac{mv^2}{r} \).
The forces that provide the centripetal force can vary; they might be tension, friction, or as in this case, gravity.
In our problem, at the loop's top, gravitational force perfectly matches the centripetal force required. This is why the pilot experiences "weightlessness" as there’s no additional force from the seat or seatbelt.
The loop's radius and velocity directly influence how strong this centripetal force must be. That's why solving for the velocity involves balancing the gravitational force with this force.
Gravitational Force
Gravitational force plays the role of providing the necessary centripetal force in this airplane loop scenario. It is the attractive force that acts between any two masses—in this case, the Earth and the airplane.
  • Gravitational force formula: \( F_{g} = mg \), where \( m \) is mass and \( g \) is the gravitational acceleration (\(9.8 \, \text{m/s}^2\)).
  • In circular motion analysis, gravity can drive the needed centripetal force required to keep the object in a loop.
During the plane's loop-the-loop, when it's at the top, this force alone must suffice to provide the centripetal force. That is why the plane's speed at the top must be such that \( F_{g} \) exactly equals \( F_{c} \).
This condition results in the pilot feeling no force from the seat, creating that sensation of "weightlessness" at the top. It's a fantastic illustration of how gravitational force can be used strategically in flight maneuvers.

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