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(solution in the pdf version of the book) In each case, identify the force that causes the acceleration, and give its Newton'sthird-law partner. Describe the effect of the partner force. (a) A swimmer speeds up. (b) A golfer hits the ball off of the tee. (c) An archer fires an arrow. (d) A locomotive slows down.

Short Answer

Expert verified
Forces: swimmer vs. water, golf club vs. ball, string vs. arrow, friction vs. train; each acts with equal opposite reaction.

Step by step solution

01

Analyze the Swimmer (a)

When a swimmer speeds up, the force causing acceleration is the swimmer pushing against the water with their arms and legs. According to Newton's third law, the water exerts an equal and opposite force on the swimmer, which propels them forward. The partner force is the swimmer's push on the water, causing it to move backward.
02

Understand the Golfer (b)

In the case of the golfer hitting the ball off of the tee, the force causing the ball's acceleration is the club striking the ball. The Newton's third-law partner is the ball pressing back against the club with equal force in the opposite direction. This reaction force impacts the golfer's hands through the club.
03

Examine the Archer (c)

For the archer firing an arrow, the force providing acceleration is the string pushing against the arrow. The partner force is the arrow pushing back on the string with equal force, pulling the string forward as the arrow is released.
04

Consider the Locomotive (d)

When a locomotive slows down, the force causing deceleration is friction between the train's wheels and the track. The Newton's third-law partner is the train exerting an equal and opposite force on the track. This partner force slightly pushes the track backward.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force and Acceleration
When we talk about force and acceleration, we refer to a relationship rooted in Newton's Second Law of Motion. This law states that the acceleration (\( a \)) of an object is directly proportional to the net force (\( F \)) acting on it and inversely proportional to its mass (\( m \)), formulated as: \[ F = m \cdot a \] In simpler terms, the more force you apply to an object, the greater its acceleration, provided its mass remains constant. Let's visualize it: a swimmer pushes against water to accelerate forward.
  • The force applied by the swimmer's arms and legs propels them in the direction they want to go.
  • The greater the force applied, the quicker the swimmer speeds up.
Next time you're at the pool, remember that more powerful strokes will increase your speed. Similarly, when a golfer strikes a ball, the force from the club causes the ball to speed off the tee. Understanding force and acceleration helps us realize how forces change motion, whether accelerating forward, like a swimmer, or slowing down, like a train.
Partner Forces
Newton’s Third Law of Motion is best known for its statement that "for every action, there's an equal and opposite reaction." In other words, forces always come in pairs, known as "partner forces". When one object exerts a force on another, the second object exerts a force back on the first:
  • This happens when a swimmer pushes against water. The water pushes back with an equal force propelling the swimmer forward.
  • Similarly, when a golfer hits a ball, the ball pushes back equally on the club.
These partner forces are always present but don’t cancel out because they act on different objects.
Understanding partner forces helps us recognize that interaction is a two-way street, as seen when you use a bow to fire an arrow. The string exerts force on the arrow, and the arrow reciprocates. These concepts explain many real-life interactions and emphasize that forces in nature are reciprocal.
Action and Reaction Forces
Newton’s third law tells us about action and reaction forces, happening in every interaction. When it comes to an archer releasing an arrow:
  • The action force is the string pushing the arrow.
  • The reaction is the arrow pushing back on the string as it begins its flight forward.
In the context of a locomotive slowing down, the train experiences friction as the action force. The track, in turn, experiences a reaction force from the train in the opposite direction. These forces are crucial because they help us understand interactions in various scenarios, from sports to machinery. By applying this knowledge, we learn the importance of equal and opposite forces, not just in the realms of physics but in practical, everyday moments.

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Most popular questions from this chapter

The earth is attracted to an object with a force equal and opposite to the force of the earth on the object. If this is true, why is it that when you drop an object, the earth does not have an acceleration equal and opposite to that of the object?

Today's tallest buildings are really not that much taller than the tallest buildings of the \(1940^{\prime}\). One big problem with making an even taller skyscraper is that every elevator needs its own shaft running the whole height of the building. So many elevators are needed to serve the building's thousands of occupants that the elevator shafts start taking up too much of the space within the building. An alternative is to have elevators that can move both horizontally and vertically: with such a design, many elevator cars can share a few shafts, and they don't get in each other's way too much because they can detour around each other. In this design, it becomes impossible to hang the cars from cables, so they would instead have to ride on rails which they grab onto with wheels. Friction would keep them from slipping. The figure shows such a frictional elevator in its vertical travel mode. (The wheels on the bottom are for when it needs to switch to horizontal motion.) (a) If the coefficient of static friction between rubber and steel is \(\mu_{s}\), and the maximum mass of the car plus its passengers is \(M\), how much force must there be pressing each wheel against the rail in order to keep the car from slipping? (Assume the car is not accelerating.)(answer check available at lightandmatter.com) (b) Show that your result has physically reasonable behavior with respect to \(\mu_{s} .\) In other words, if there was less friction, would the wheels need to be pressed more firmly or less firmly? Does your equation behave that way?

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