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Object A has a kinetic energy of \(13.4\) J. Object B has a mass that is greater by a factor of \(3.77\), but is moving more slowly by a factor of \(2.34\). What is object B's kinetic energy? (solution in the pdf version of the book)

Short Answer

Expert verified
Object B's kinetic energy is approximately 9.2 J.

Step by step solution

01

Understand Kinetic Energy Formula

The formula for kinetic energy is given by \( KE = \frac{1}{2} m v^2 \), where \( KE \) is the kinetic energy, \( m \) is the mass, and \( v \) is the velocity of the object.
02

Define Object B's Mass and Velocity

Object B has a mass greater by a factor of \( 3.77 \) compared to Object A. If Object A's mass is \( m \), then Object B's mass is \( m_B = 3.77m \). Object B is moving more slowly by a factor of \( 2.34 \), so if Object A's velocity is \( v \), then Object B's velocity is \( v_B = \frac{v}{2.34} \).
03

Set Up Object B's Kinetic Energy Equation

The kinetic energy of Object B is given by the formula \( KE_B = \frac{1}{2} m_B v_B^2 \), substituting the expressions for mass and velocity, it becomes \( KE_B = \frac{1}{2} (3.77m) \left( \frac{v}{2.34} \right)^2 \).
04

Compare Object A and B's Kinetic Energy

We know that Object A's kinetic energy is \( 13.4 \) J, or \( KE = \frac{1}{2} m v^2 = 13.4 \) J. We use this to calculate Object B's kinetic energy relative to \( KE \).
05

Calculate Object B's Kinetic Energy

Substitute \( \frac{1}{2} m v^2 = 13.4 \) and simplify: \[ KE_B = 3.77 \times 13.4 \times \left( \frac{1}{2.34} \right)^2 \]. Calculate \( \left( \frac{1}{2.34} \right)^2 \approx 0.182 \). Thus, \( KE_B \approx 3.77 \times 13.4 \times 0.182 \approx 9.204 \) J.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Physics Formulas
When we talk about kinetic energy in physics, we use a specific formula to express it. This formula is written as:
  • \( KE = \frac{1}{2} m v^2 \)
Here, \( KE \) stands for kinetic energy, \( m \) represents the mass of the object, and \( v \) is the velocity at which the object is moving.
This formula shows that kinetic energy depends on both the mass of the object and its speed. Importantly, because velocity is squared in the formula, changes in speed have a dramatic effect on the kinetic energy.
Doubling the velocity will quadruple the kinetic energy, showing the non-linear relationship nature of speed to kinetic energy. Understanding this formula is the key to solving kinetic energy calculations and discerning the factors that influence an object's energy in motion.
Mass and Velocity Relationship
The relationship between mass, velocity, and kinetic energy is fascinating. Instead of acting independently, mass and velocity together determine how much kinetic energy an object will have.
  • If the mass is increased while keeping velocity constant, the kinetic energy increases proportionally:
  • \( KE \propto m \).
Similarly,
  • if the velocity increases and the mass remains constant, kinetic energy increases but at a much faster rate:
  • \( KE \propto v^2 \).
In the given exercise, object B was heavier than object A by a factor of \( 3.77 \) and moved more slowly by a factor of \( 2.34 \).
This meant that its increased mass and decreased velocity had combined effects on its kinetic energy. More mass contributed positively, whereas the slower velocity contributed negatively. However, because velocity is squared in the formula, it can have a larger impact than changes in mass. Hence, it is always essential to balance these two factors when calculating energy.
Energy Calculation
Calculating kinetic energy involves plugging the known values into the kinetic energy formula and doing some straightforward arithmetic. For object B,
  • The kinetic energy calculation utilized the known kinetic energy of object A (13.4 J) and factored in the adjustments in both mass and velocity for object B.
To find object B's kinetic energy:
  • First, substitute object B's new mass \( m_B = 3.77m \); and adjusted velocity \( v_B = \frac{v}{2.34} \) into the formula:
  • \[ KE_B = \frac{1}{2} (3.77m) \left( \frac{v}{2.34} \right)^2 \]
  • Using Object A's known kinetic energy \( KE_A = 13.4 \, J \), substitute into the equation:\[ KE_B = 3.77 \times 13.4 \times \left( \frac{1}{2.34} \right)^2 \]
  • Calculate the values to finally determine that Object B's kinetic energy is approximately \( 9.204 \, J \).
These steps show how mass and velocity interact mathematically to influence kinetic energy.

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Most popular questions from this chapter

Anya climbs to the top of a tree, while Ivan climbs half-way to the top. They both drop pennies to the ground. Compare the kinetic energies and velocities of the pennies on impact, using ratios.

The following table gives the amount of energy required in order to heat, melt, or boil a gram of water. $$\begin{array}{ll}\hline \text { heat } 1 \mathrm{~g} \text { of ice by } 1^{\circ} \mathrm{C} & 2.05 \mathrm{~J} \\ \text { melt } 1 \mathrm{~g} \text { of ice } & 333 \mathrm{~J} \\ \text { heat } 1 \mathrm{~g} \text { of liquid by } 1^{\circ} \mathrm{C} & 4.19 \mathrm{~J} \\ \text { boil } 1 \mathrm{~g} \text { of water } & 2500 \mathrm{~J} \\ \text { heat } 1 \mathrm{~g} \text { of steam by } 1^{\circ} \mathrm{C} & 2.01 \mathrm{~J} \\ \hline\end{array}$$ (a) How much energy is required in order to convert \(1.00 \mathrm{~g}\) of ice at \(-20^{\circ} \mathrm{C}\) into steam at \(137^{\circ} \mathrm{C}\) ? (answer check available at lightandmatter.com) (b) What is the minimum amount of hot water that could melt \(1.00 \mathrm{~g}\) of ice? (answer check available at lightandmatter.com)

(a) A mass \(m\) is hung from a spring whose spring constant is \(k\). Write down an expression for the total interaction energy of the system, \(U\), and find its equilibrium position. Wwhint \\{hwhint:hangfromspring\\} (b) Explain how you could use your result from part a to determine an unknown spring constant.

A projectile is moving directly away from a planet of mass \(M\) at exactly escape velocity. (a) Find \(r\), the distance from the projectile to the center of the planet, as a function of time, \(t\), and also find \(v(t)\).(answer check available at lightandmatter.com) (b) Check the units of your answer. (c) Does \(v\) show the correct behavior as \(t\) approaches infinity? Vwhint \(\\{\) hwhint:escape 2\(\\}\)

Anya and Ivan lean over a balcony side by side. Anya throws a penny downward with an initial speed of \(5 \mathrm{~m} / \mathrm{s}\). Ivan throws a penny upward with the same speed. Both pennies end up on the ground below. Compare their kinetic energies and velocities on impact.

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