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Show that a wavefunction of the form \(\Psi=e^{b y} \sin a x\) is a possible solution of the Schrödinger equation in two dimensions, with a constant potential. Can we tell whether it would apply to a classically allowed region, or a classically forbidden one?

Short Answer

Expert verified
\(\Psi = e^{b y} \sin a x\) is a solution, describing classically allowed or forbidden regions based on \(E\) relative to \(V\).

Step by step solution

01

Write the Schrödinger Equation in Two Dimensions

The time-independent Schrödinger equation for a particle with mass \(m\) in two dimensions, subject to a potential energy \(V(x, y)\), is given by:\[-\frac{{\hbar^2}}{2m} \left( \frac{{\partial^2 \Psi}}{{\partial x^2}} + \frac{{\partial^2 \Psi}}{{\partial y^2}} \right) + V(x, y)\Psi = E\Psi\]where \(\hbar\) is the reduced Planck's constant. We will proceed by calculating the second derivatives needed to substitute into this equation.
02

Find Second Derivative with Respect to x

The second partial derivative of \(\Psi(x, y) = e^{b y} \sin(a x)\) with respect to \(x\) is:\[\frac{{\partial \Psi}}{{\partial x}} = e^{b y} a \cos(a x)\]\[\frac{{\partial^2 \Psi}}{{\partial x^2}} = e^{b y} (-a^2) \sin(a x)\]
03

Find Second Derivative with Respect to y

The second partial derivative of \(\Psi(x, y) = e^{b y} \sin(a x)\) with respect to \(y\) is:\[\frac{{\partial \Psi}}{{\partial y}} = b e^{b y} \sin(a x)\]\[\frac{{\partial^2 \Psi}}{{\partial y^2}} = b^2 e^{b y} \sin(a x)\]
04

Substitute Derivatives into Schrödinger Equation

Substitute the second derivatives back into the Schrödinger equation:\[-\frac{{\hbar^2}}{2m} \left( -a^2 e^{b y} \sin(a x) + b^2 e^{b y} \sin(a x) \right) + V e^{b y} \sin(a x) = E e^{b y} \sin(a x)\]Simplify:\[\frac{{\hbar^2}}{2m} (a^2 + b^2) e^{b y} \sin(a x) + V e^{b y} \sin(a x) = E e^{b y} \sin(a x)\]
05

Equate and Simplify

Since the terms \(e^{b y} \sin(a x)\) are common factors in each term of the equation, we can cancel them out, leading to:\[\frac{{\hbar^2}}{2m} (a^2 + b^2) + V = E\]This provides a condition for \(E\) in terms of \(a\), \(b\), and the potential energy \(V\).
06

Determine the Nature of the Region

Based on \(E = \frac{{\hbar^2}}{2m} (a^2 + b^2) + V\), we see:- If \(E > V\), the wavefunction describes a classically allowed region.- If \(E < V\), it describes a classically forbidden region.Since the exact energies and potentials are not provided, we cannot definitively categorize \(\Psi\) as describing one region or the other.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavefunction
In quantum mechanics, the wavefunction is a fundamental concept that provides a description of the quantum state of a system. It is typically denoted by the Greek letter \(\Psi\). The wavefunction is a mathematical function that includes all the information about a particle’s position, momentum, and other physical properties.

In a two-dimensional system, like the problem, the wavefunction \(\Psi(x, y) = e^{b y} \sin(a x)\) describes how the amplitude of a particle's probability density behaves in space. It’s a complex-valued function, meaning it often involves imaginary numbers, and its square's magnitude gives the probability density of finding a particle in a specific place.

Key points to remember about wavefunctions:
  • Wavefunctions represent probability amplitudes, not probabilities directly.
  • The squared absolute value of the wavefunction gives the probability density.
  • Boundary conditions and normalizations often shape the wavefunction’s form.
The Schrödinger equation uses wavefunctions to determine how quantum systems evolve over time.
Quantum Potential
Quantum potential, denoted by \(V(x,y)\) in the Schrödinger equation, represents the potential energy landscape that a quantum particle experiences. In quantum mechanics, potential energy influences a particle’s behavior, similarly to classical physics, but uniquely affects how a wavefunction can exist.

The potential acts as an external force field, modifying the kinetic energy part of the Schrödinger equation. In simpler exercises, like ours, the potential is often constant, which implies a uniform potential energy everywhere. In the context of the wavefunction \(\Psi(x, y) = e^{b y} \sin(a x)\), the potential \(V\) remains constant across the plane.

Important aspects of quantum potentials include:
  • They determine the regions where particles can exist or tunnel through classically forbidden areas.
  • In a constant potential, determining the wavefunction behavior is more straightforward.
The relationship \(E = \frac{\hbar^2}{2m} (a^2 + b^2) + V\) shows how the potential contributes to the total energy \(E\) of the system.
Classically Allowed Region
A classically allowed region corresponds to the area where a particle, according to classical mechanics, has enough energy to exist. In these regions, a particle's energy \(E\) is greater than the potential energy \(V\). Classically, this would mean that a particle can move freely without any barriers restricting its motion.

In terms of the wavefunction solution, when \(E > V\), it implies that the particle’s energy is sufficient to be in that area. Therefore, the wavefunction’s form allows for oscillating solutions, representing realistic, freely-moving particle trajectories.

Key characteristics of these regions include:
  • A particle behaves similarly to classical expectations, moving freely without confinement.
  • The region supports wave-like behavior in the form of oscillations in the wavefunction.
This concept illustrates the convergence between classical physics predictions and quantum mechanics outcomes in certain energy regimes.
Classically Forbidden Region
Classically forbidden regions are areas where a particle does not have enough energy to be present according to classical mechanics—meaning \(E < V\). In classical terms, this is like a hill too high for a particle to climb without extra energy. However, in quantum mechanics, due to phenomena like tunneling, particles can sometimes be found in these regions.

In our exercise, when \(E < V\), the wavefunction describes non-oscillatory, exponentially decaying behavior. This indicates regions where the probability of finding a particle rapidly drops off.

Characteristics of classically forbidden regions in a quantum context:
  • Particles are not expected to exist, yet quantum mechanics allows for occasional presence through tunneling.
  • The wavefunction exhibits exponential decay, showing diminishing probability as it penetrates the region.
Understanding forbidden regions helps illustrate quantum mechanics' unique capabilities to describe behaviors not allowed in classical physics.

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Most popular questions from this chapter

In the photoelectric effect, electrons are observed with virtually no time delay \((\sim 10 \mathrm{~ns})\), even when the light source is very weak. (A weak light source does however only produce a small number of ejected electrons.) The purpose of this problem is to show that the lack of a significant time delay contradicted the classical wave theory of light, so throughout this problem you should put yourself in the shoes of a classical physicist and pretend you don't know about photons at all. At that time, it was thought that the electron might have a radius on the order of \(10^{-15} \mathrm{~m}\). (Recent experiments have shown that if the electron has any finite size at all, it is far smaller.) (a) Estimate the power that would be soaked up by a single electron in a beam of light with an intensity of \(1 \mathrm{~mW} / \mathrm{m}^{2}\).(answer check available at lightandmatter.com) (b) The energy, \(E_{s}\), required for the electron to escape through the surface of the cathode is on the order of \(10^{-19} \mathrm{~J}\). Find how long it would take the electron to absorb this amount of energy, and explain why your result constitutes strong evidence that there is something wrong with the classical theory.(answer check available at lightandmatter.com)

All helium on earth is from the decay of naturally occurring heavy radioactive elements such as uranium. Each alpha particle that is emitted ends up claiming two electrons, which makes it a helium atom. If the original \({ }^{238} \mathrm{U}\) atom is in solid rock (as opposed to the earth's molten regions), the He atoms are unable to diffuse out of the rock. This problem involves dating a rock using the known decay properties of uranium 238 . Suppose a geologist finds a sample of hardened lava, melts it in a furnace, and finds that it contains \(1230 \mathrm{mg}\) of uranium and \(2.3 \mathrm{mg}\) of helium. \({ }^{238} \mathrm{U}\) decays by alpha emission, with a half-life of \(4.5 \times 10^{9}\) years. The subsequent chain of alpha and electron (beta) decays involves much shorter half-lives, and terminates in the stable nucleus \({ }^{206} \mathrm{~Pb}\). Almost all natural uranium is \({ }^{238} \mathrm{U}\), and the chemical composition of this rock indicates that there were no decay chains involved other than that of \({ }^{238} \mathrm{U}\). (a) How many alphas are emitted per decay chain? [Hint: Use conservation of mass.] (b) How many electrons are emitted per decay chain? [Hint: Use conservation of charge.] (c) How long has it been since the lava originally hardened?(answer check available at lightandmatter.com)

Assume that the kinetic energy of an electron the \(n=1\) state of a hydrogen atom is on the same order of magnitude as the absolute value of its total energy, and estimate a typical speed at which it would be moving. (It cannot really have a single, definite speed, because its kinetic and interaction energy trade off at different distances from the proton, but this is just a rough estimate of a typical speed.) Based on this speed, were we justified in assuming that the electron could be described nonrelativistically?

Devise a method for testing experimentally the hypothesis that a gambler's chance of winning at craps is independent of her previous record of wins and losses. If you don't invoke the definition of statistical independence, then you haven't proposed a test.

The wavefunction of the electron in the ground state of a hydrogen atom is $$\Psi=\pi^{-1 / 2} a^{-3 / 2} e^{-r / a}$$ where \(r\) is the distance from the proton, and \(a=5.3 \times 10^{-11} \mathrm{~m}\) is a constant that sets the size of the wave. (a) Calculate symbolically, without plugging in numbers, the probability that at any moment, the electron is inside the proton. Assume the proton is a sphere with a radius of \(b=0.5 \mathrm{fm}\). [Hint: Does it matter if you plug in \(r=0\) or \(r=b\) in the equation for the wavefunction?](answer check available at lightandmatter.com) (b) Calculate the probability numerically.(answer check available at lightandmatter.com) (c) Based on the equation for the wavefunction, is it valid to think of a hydrogen atom as having a finite size? Can \(a\) be interpreted as the size of the atom, beyond which there is nothing? Or is there any limit on how far the electron can be from the proton?

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