/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Find the inductance of two ident... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the inductance of two identical inductors in parallel.

Short Answer

Expert verified
The inductance of two identical inductors in parallel is \( \frac{L}{2} \).

Step by step solution

01

Understand the Concept

When two inductors are connected in parallel, the total (or equivalent) inductance can be found using a formula similar to that for resistors in parallel. The formula is derived from the property that the voltage across each inductor is the same, and the total current is the sum of the currents through each inductor.
02

Apply the Parallel Inductor Formula

For two inductors, each with inductance \( L \), connected in parallel, the formula to find the total inductance \( L_{ ext{total}} \) is:\[ \frac{1}{L_{ ext{total}}} = \frac{1}{L_1} + \frac{1}{L_2} \]Since both inductors have the same inductance, \( L_1 = L_2 = L \), the formula becomes:\[ \frac{1}{L_{ ext{total}}} = \frac{1}{L} + \frac{1}{L} \]
03

Simplify the Equation

Simplify the equation from Step 2:\[ \frac{1}{L_{ ext{total}}} = \frac{2}{L} \]To find \( L_{ ext{total}} \), take the reciprocal of both sides:\[ L_{ ext{total}} = \frac{L}{2} \]
04

Conclusion

Thus, the inductance of two identical inductors in parallel is half of the inductance of one inductor. This means if each inductor has an inductance \( L \), their equivalent inductance when connected in parallel is \( \frac{L}{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parallel Circuits
When dealing with circuits, understanding parallel circuits is essential. In parallel circuits, components are connected along multiple paths, so the current can split and flow through multiple components simultaneously. This is different from series circuits, where components are connected end to end, and the same current flows through each component sequentially.

A common characteristic of parallel circuits is that they share the same voltage across all components. For inductors connected in parallel, it means the voltage across each one is the same. However, the current is divided between the inductors.

In practical terms, parallel circuits allow for flexibility in controlling loads and can reduce the overall impedance in a circuit. This concept is crucial when calculating the total inductance or resistance of components in a circuit.
Inductors
Inductors are fundamental components used in electrical circuits, characterized by their ability to store energy in a magnetic field when electrical current flows through them. Their primary function is to oppose changes in current. The unit of inductance is the henry (H).

Key features of inductors include:
  • Energy Storage: Inductors store energy in their magnetic field, useful in applications like filters and transformers.

  • Phase Shift: They cause a phase shift between voltage and current, crucial in AC circuits.

  • Reaction to Changes: Inductors resist changes in the current flow, a property known as inductive reactance.

Understanding these features helps in designing circuits and ensures components function as required in power supplies, signal processing, and tuning circuits.
Equivalent Inductance Formula
Finding the equivalent inductance for inductors in parallel requires using a specific formula. This formula is somewhat analogous to calculating total resistance for resistors in parallel, given by:\[ \frac{1}{L_{\text{total}}} = \frac{1}{L_1} + \frac{1}{L_2} + \cdots + \frac{1}{L_n} \]Here, \(L_{\text{total}}\) represents the total inductance, and \(L_1, L_2, \ldots, L_n\) are the individual inductances of inductors in parallel.

For two identical inductors, each with inductance \( L \), this formula simplifies to:\[ \frac{1}{L_{\text{total}}} = \frac{1}{L} + \frac{1}{L} = \frac{2}{L} \]This allows us to solve for the equivalent inductance as:\[ L_{\text{total}} = \frac{L}{2} \]

This formula is important for electronics, as it allows engineers and students to understand how combining inductors in a circuit affects overall inductance. Knowing how to manipulate and apply this formula is crucial for effective circuit analysis and design.

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Most popular questions from this chapter

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Light is a wave made of electric and magnetic fields, and the fields are perpendicular to the direction of the wave's motion, i.e., they're transverse. An example would be the electric field given by \(\mathbf{E}=b \hat{\mathbf{x}} \sin c z\), where \(b\) and \(c\) are constants. (There would also be an associated magnetic field.) We observe that light can travel through a vacuum, so we expect that this wave pattern is consistent with the nonexistence of any charge in the space it's currently occupying. Use Gauss's law to prove that this is true.

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