/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 (solution in the pdf version of ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(solution in the pdf version of the book) How many \(\mathrm{cm}^{2}\) is \(1 \mathrm{~mm}^{2}\) ?

Short Answer

Expert verified
1 \(\mathrm{mm}^2\) is 0.01 \(\mathrm{cm}^2\).

Step by step solution

01

Understand Units of Measurement

To solve this exercise, you need to understand that "cm" stands for centimeters and "mm" stands for millimeters. The goal is to convert from square millimeters (\(\mathrm{mm}^2\)) to square centimeters (\(\mathrm{cm}^2\)).
02

Convert Linear Measurements

Since 1 cm is equal to 10 mm, the conversion factor from millimeters to centimeters is 10. This means that 1 mm equals \( \frac{1}{10} \) cm or 0.1 cm.
03

Apply Area Conversion

To convert \(\mathrm{mm}^2\) to \(\mathrm{cm}^2\), you square the linear conversion factor. So, \((0.1 \, \mathrm{cm})^2 = 0.01 \, \mathrm{cm}^2\).
04

Complete Conversion

Therefore, 1 \(\mathrm{mm}^2\) can be converted to \(0.01 \, \mathrm{cm}^2\). This tells us how many square centimeters there are in one square millimeter.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Area Conversion
When dealing with area conversion, it's essential to understand that you are not just converting from one unit to another but dealing with units squared. Area is always measured in square units, like \(\text{cm}^2\) for square centimeters or \(\text{mm}^2\) for square millimeters. This makes the conversion slightly different from linear conversion.

To convert an area from one unit to another, you must square the linear conversion factor. For instance, in our example, to convert 1 square millimeter (\(\text{mm}^2\)) to square centimeters (\(\text{cm}^2\)), we must first understand the conversion between millimeters and centimeters. Since 1 centimeter equals 10 millimeters, the linear conversion factor is \(\frac{1}{10}\) or 0.1.

Now, since the area is squared, you have to take the square of the linear conversion factor: \((0.1)^2 = 0.01\). This means that \(1\, \text{mm}^2\) is equivalent to \(0.01\, \text{cm}^2\). Recognizing this extra step is crucial for precise conversions between area measurements.
Metric System
The Metric System is an international system of measurement that is used globally. It is based on multiples of ten, making it very intuitive and straightforward for conversions. In this system, the basic unit for length is the meter, and other units like centimeters and millimeters are derived by dividing or multiplying by powers of ten.

For example:
  • 1 meter (m) = 100 centimeters (cm)
  • 1 centimeter (cm) = 10 millimeters (mm)

This decimal-based structure greatly simplifies the process of conversion across various metric units. When converting between units in the metric system, like from millimeters to centimeters, you either multiply or divide by powers of ten. This is particularly useful when performing area and volume conversions, as there are no complex conversions or fractions to deal with, unlike some other measurement systems used around the world.
Units of Measurement
Units of Measurement allow us to quantify and communicate about the physical aspects of the world. Each unit represents a standard quantity of a physical property, making comparisons and calculations possible in everyday life and scientific practices.

The metric system is one of the most widely used systems, but understanding the units and how they relate is vital regardless of the system. In area measurement, such as square centimeters (\(\text{cm}^2\)) and square millimeters (\(\text{mm}^2\)), knowing the relationship between the units aids in accurate conversions and effective communication.

Key concepts:
  • A length or distance measurement is one-dimensional, while area is two-dimensional, involving squaring that length.
  • For area conversions, remember to multiply the conversion factor by itself because areas deal with two dimensions.
  • Accurate unit conversion helps in fields like science, engineering, and daily life."

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The central portion of a CD is taken up by the hole and some surrounding clear plastic, and this area is unavailable for storing data. The radius of the central circle is about \(35 \%\) of the outer radius of the data-storing area. What percentage of the CD's area is therefore lost? (answer check available at lightandmatter.com)

Compute the following things. If they don't make sense because of units, say so. (a) \(3 \mathrm{~cm}+5 \mathrm{~cm}\) (b) \(1.11 \mathrm{~m}+22 \mathrm{~cm}\) (c) 120 miles \(+2.0\) hours (d) 120 miles \(/ 2.0\) hours

. The one-liter cube in the photo has been marked off into smaller cubes, with linear dimensions one tenth those of the big one. What is the volume of each of the small cubes?(solution in the pdf version of the book)

Your backyard has brick walls on both ends. You measure a distance of \(23.4 \mathrm{~m}\) from the inside of one wall to the inside of the other. Each wall is \(29.4 \mathrm{~cm}\) thick. How far is it from the outside of one wall to the outside of the other? Pay attention to significant figures.

A person is parachute jumping. During the time between when she leaps out of the plane and when she opens her chute, her altitude is given by an equation of the form \(y=b-c\left(t+k e^{-t / k}\right)\) where \(e\) is the base of natural logarithms, and \(b, c\), and \(k\) are constants. Because of air resistance, her velocity does not increase at a steady rate as it would for an object falling in vacuum. (a) What units would \(b, c\), and \(k\) have to have for the equation to make sense? (b) Find the person's velocity, \(v\), as a function of time. [You will need to use the chain rule, and the fact that \(\left.d\left(e^{x}\right) / d x=e^{x} .\right]\) (answer check available at lightandmatter.com) (c) Use your answer from part (b) to get an interpretation of the constant \(c\). [Hint: \(e^{-x}\) approaches zero for large values of \(\left.x .\right]\) (d) Find the person's acceleration, \(a\), as a function of time.(answer check available at lightandmatter.com) (e) Use your answer from part (d) to show that if she waits long enough to open her chute, her acceleration will become very small.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.