/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Calculate the resultant of a ver... [FREE SOLUTION] | 91影视

91影视

Calculate the resultant of a vertical vector with magnitude of 6 units and a horizontal vector with a magnitude of 5 units.

Short Answer

Expert verified
The magnitude of the resultant vector is \( \sqrt{61} \) units.

Step by step solution

01

Understand the problem

The problem involves two perpendicular vectors: one vertical and one horizontal. To find the resultant vector, which is the vector sum of these two, we use the Pythagorean theorem because the vectors are at right angles to each other.
02

Apply the Pythagorean theorem

Since the vectors are perpendicular, the magnitude of the resultant vector (R) is given by the square root of the sum of the squares of the magnitudes of the two vectors. The formula is: \( R = \sqrt{V^2 + H^2} \), where V is the vertical vector's magnitude and H is the horizontal vector's magnitude.
03

Perform the calculation

Substitute the given magnitudes (V = 6 units, H = 5 units) into the formula: \( R = \sqrt{6^2 + 5^2} = \sqrt{36 + 25} = \sqrt{61} \).
04

Calculate the final result

After calculating the square root of 61, we get the magnitude of the resultant vector: \( R = \sqrt{61} \) units.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pythagorean Theorem
The Pythagorean theorem is an essential principle in mathematics, especially when dealing with right-angled triangles. It states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This relationship is expressed through the formula:
\[ c^2 = a^2 + b^2 \]
where \( c \) represents the length of the hypotenuse, and \( a \) and \( b \) represent the lengths of the triangle's other two sides.

In the context of vector addition and physics, the Pythagorean theorem allows us to calculate the magnitude of a resultant vector when we know the magnitudes of its perpendicular components. This theorem simplifies the process of finding how much one vector contributes to the direction of another when they are combined, such as in the textbook exercise we are exploring.
Resultant Vector
A resultant vector is the single vector that has the same effect as applying several vectors in succession. In physics, it's the total effect of multiple forces or velocities when applied at the same point.

To find the resultant of two vectors at right angles, we can visualize each vector as a side of a right-angled triangle, with the resultant vector being the hypotenuse. This approach brings the Pythagorean theorem into play. Once we've used it to find the magnitude of the resultant, we can then determine its direction using trigonometry. In our exercise, the resultant vector is the vector addition of a vertical and a horizontal vector. By drawing these vectors as adjacent sides of a right-angled triangle, we easily compute the hypotenuse 鈥 which is our resultant vector.
Magnitude of a Vector
The magnitude of a vector is simply the 'length' of the vector from its start to finish point. It measures how much 'force' a vector represents without regard to its direction, expressed as a distance unit, like meters or feet.

When discussing two-dimensional vectors, such as those in the exercise, we might visualize them on a graph with an x-axis (horizontal) and a y-axis (vertical). The magnitude is found by drawing a right triangle with the vector as the hypotenuse. We then use the Pythagorean theorem to solve for the vector's length.
In the given exercise, to find the magnitude of the resultant vector, we calculated the square root of the sum of the squares of the magnitudes of the vertical and horizontal vectors as detailed in the step-by-step solution, using the formula:
\[ R = \sqrt{V^2 + H^2} \]
where \( V \) is the vertical component, \( H \) is the horizontal component, and \( R \) is the resultant vector's magnitude. Understanding the relationship between the magnitudes of the components and the resultant vector is fundamental in vector addition.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

When two identical air pucks with repelling magnets are held together on an air table and then released, they end up moving in opposite directions at the same speed, \(v\) Assume the mass of one of the pucks is doubled and the procedure is repeated. a. From Newton's third law, show that the final speed of the double-mass puck is half that of the single puck. b. Calculate the speed of the double-mass puck if the single puck moves away at 0.4 \(\mathrm{m} / \mathrm{s}\) .

Which of Newton鈥檚 laws deals with action鈥搑eaction pairs?

Suppose that two carts, one twice as massive as the other, fly apart when the compressed spring that joins them is released. What is the acceleration of the heavier cart relative to that of the lighter cart as they start to move apart?

A farmer urges his horse to pull a wagon. The horse refuses, saying that to try would be futile because it would flout Newton鈥檚 third law. The horse concludes that she can鈥檛 exert a greater force on the wagon than the wagon exerts on her and, therefore, that she won鈥檛 be able to accelerate the wagon. Discuss your reasoning to convince the horse to pull.

What aspect of physics was not known by the writer of this newspaper editorial that ridiculed early experiments by Robert H. Goddard on rocket propulsion above Earth鈥檚 atmosphere? 鈥淧rofessor Goddard . . . does not know the relation of action to reaction, and of the need to have something better than a vacuum against which to react . . . he seems to lack the knowledge ladled out daily in high schools.鈥

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.