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91Ó°ÊÓ

A metal ball is barely able to pass through a metal ring. When Anette Zetterberg heats the ball, it does not pass through the ring. What happens if she instead heats the ring (as shown)? Does the size of the hole increase, stay the same, or decrease?

Short Answer

Expert verified
When Anette heats the ring, the size of the hole increases due to thermal expansion.

Step by step solution

01

Understanding Thermal Expansion

When a metal object is heated, it undergoes thermal expansion as the particles within the metal move more and take up more space. This leads to an overall increase in the volume of the metal.
02

Applying Thermal Expansion to the Ball

Initially, the ball can just pass through the ring. When the ball is heated, thermal expansion causes it to increase in size, making it too large to pass through the ring.
03

Applying Thermal Expansion to the Ring

When the ring is heated, it also undergoes thermal expansion. The material of the ring expands in all directions, which includes the metal around the hole, causing the hole to become larger. Therefore, if Anette heats the ring, the size of the hole will also increase, allowing a larger ball to pass through than before the ring was heated.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Expansion in Solids
When we think about solids, we might consider them as stable, unchanging objects. But in the physical world, solids are in constant motion on a molecular level.
Thermal expansion in solids is a fascinating phenomenon where materials expand upon heating. The kinetic theory of matter tells us that molecules move faster as they gain more thermal energy. As a consequence, the average distance between molecules increases, leading to an observable change in size of a solid object.

This behavior is crucial to understanding many aspects of engineering and design, such as fitting parts together, constructing buildings, and manufacturing mechanical components. Materials with high coefficients of thermal expansion can undergo significant changes in dimensions, which can cause structural problems if not properly accounted for.
Linear Expansion
Imagine a metal rod lying in the sun. As the temperature rises, the rod gets longer. This is linear expansion – a type of thermal expansion where the change in length is most prominent.
Mathematically, this change can be predicted by the formula: \( L = L_0 \times \alpha \times \Delta T \), where \( L_0 \) is the original length, \( \alpha \) is the coefficient of linear expansion, and \( \Delta T \) is the change in temperature.

Materials with higher coefficients will expand more for a given temperature increase. This makes such measurements a vital part of material science and engineering practices, especially when constructing railways, bridges, or using metallic parts that must fit together precisely.
Volume Expansion
Volume expansion can be seen as the 'big picture' of thermal expansion. When we heat an object, not only does it expand in length, but it also expands in width and height.
The change in volume can be calculated with the equation: \( V = V_0 \times \beta \times \Delta T \) where \( V_0 \) is the original volume, \( \beta \) is the coefficient of volume expansion, and \( \Delta T \) is the temperature change.

Most substances expand upon heating and contract upon cooling, but the rate of expansion or contraction can vary significantly from one material to another. Understanding volume expansion is particularly important for applications involving fluids or gases, as they tend to have higher coefficients compared to solids, making their volume changes more dramatic with temperature variations.
Physical Science Education
Promoting a strong foundation in physical science education is fundamental to developing critical thinkers who can tackle real-world problems. Concepts such as thermal expansion are not just textbook material; they are observable, measurable, and have a direct impact on everything from household plumbing to aerospace engineering.

Providing interactive and practical learning experiences, such as the metal ball and ring example, helps students visualize and understand these concepts better. It shapes their ability to reason scientifically and apply theoretical knowledge to physical phenomena. Furthermore, an understanding of physical science paves the way for future innovations and a technically skilled workforce, which is invaluable in our increasingly technology-driven world.

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Most popular questions from this chapter

In which direction does thermal energy flow between hot and cold objects?

If you wish to warm 50 kg of water by 20°C for your bath, show that the amount of heat needed is 1000 kcal (1000 Cal). Then show that this rounds off to be about 4200 kJ.

The precise volume of 200 grams of water in a beaker depends on the temperature of the water. Rank the following temperatures from greatest volume of 200 grams of water to least volume of 200 grams of water: (a) 0°C. (b) 4°C. (c) 10°C.

How much energy is in a nut? Burn it and find out. The heat from the flame is energy released when carbon and hydrogen in the nut combine with oxygen in the air (oxidation reactions) to produce CO2 and H2O. Pierce a nut (pecan or walnut halves work best) with a bent paper clip that holds the nut above the table surface. Above this, secure a can of water so that you can measure its temperature change when the nut burns. Use about 103 cm (10 mL) of water and a Celsius thermometer. As soon as you ignite the nut with a match, place the can of water above it, and record the increase in water temperature once the flame burns out. The number of calories released by the burning nut can be calculated by the formula Q = cm?T , where c is the water’s specific heat (1 cal/g # °C), m is the mass of water, and ?T is the change in temperature. The energy in food is expressed in terms of the Calorie, which is 1000 of the calories you’ll measure. So to find the number of Calories, divide your result by 1000. (See Think and Solve

How many joules are needed to change the temperature of 1 gram of water by 1°C?

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