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A spherical ball of surface area \(20 \mathrm{~cm}^{2}\) absorbs any radiation that falls on it. It is suspended in a closed box maintained at \(57^{\circ} \mathrm{C}\). (a) Find the amount of radiation falling on the ball per second. (b) Find the net rate of heat flow to or from the ball at an instant when its temperature is \(200^{\circ} \mathrm{C}\). Stefan constant \(=6.0 \times 10^{-8}\) \(\mathrm{W} \mathrm{m}^{-2} \mathrm{~K}^{-4}\)

Short Answer

Expert verified
(a) 1.4231 x 10鈦烩伌 W falls on the ball per second. (b) Heat flows from the ball at -4.5772 x 10鈦烩伌 W.

Step by step solution

01

Convert Given Units

Convert the given surface area from cm虏 to m虏 for compatibility with the Stefan-Boltzmann constant. We have:\[ 1 ext{ cm}^2 = 10^{-4} ext{ m}^2 \]Therefore,\[ 20 ext{ cm}^2 = 20 imes 10^{-4} ext{ m}^2 = 0.002 ext{ m}^2 \]
02

Calculate Radiation Falling on the Ball Using Stefan-Boltzmann Law

The radiation falling on the ball per second is calculated using the Stefan-Boltzmann Law:\[ P = ext{Area} imes ext{Stefan constant} imes T^4 \]where \( T \) is the absolute temperature of the surroundings in Kelvin. Convert the temperature of the box:\[ T_{ ext{box}} = 57^{ ext{掳}C} + 273 = 330 ext{ K} \]Now calculate the radiation:\[ P = 0.002 ext{ m}^2 imes 6 imes 10^{-8} ext{ W m}^{-2} ext{ K}^{-4} imes (330 ext{ K})^4 \]\[ P = 0.002 imes 6 imes 10^{-8} imes 1.185921\times 10^{10} \]\[ P = 1.4231 imes 10^{-4} ext{ W} \]
03

Calculate Radiation Emitted by the Ball

Now calculate the power radiated by the ball since it has its own temperature of 200掳C:\[ T_{ ext{ball}} = 200^{ ext{掳}C} + 273 = 473 ext{ K} \]\[ P_{ ext{emitted}} = 0.002 imes 6 imes 10^{-8} imes (473)^4 \]\[ P_{ ext{emitted}} = 0.002 imes 6 imes 10^{-8} \times 5.0003\times 10^{10} \]\[ P_{ ext{emitted}} = 6.0003 imes 10^{-4} ext{ W} \]
04

Find Net Rate of Heat Flow

The net rate of heat flow to or from the ball is the difference between the energy the ball receives and emits. \[ P_{ ext{net}} = P_{ ext{received}} - P_{ ext{emitted}} \]Substitute the values we found:\[ P_{ ext{net}} = 1.4231 imes 10^{-4} ext{ W} - 6.0003 imes 10^{-4} ext{ W} \]\[ P_{ ext{net}} = -4.5772 imes 10^{-4} ext{ W} \]This shows the direction of heat flow is out of the ball.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radiation Heat Transfer
Radiation heat transfer is a core concept in the study of thermodynamics, particularly when dealing with how energy is exchanged through electromagnetic waves. Unlike conduction or convection, radiation does not require any medium, which means energy can be transferred even through a vacuum. This principle is a vital aspect of understanding how objects emit and absorb thermal energy. For example, in the exercise involving the spherical ball, radiation heat transfer is key to determining how much energy is falling on or leaving the ball.

The Stefan-Boltzmann Law comes into play here by providing a formula to calculate the amount of energy radiated per second by an object, based on its surface area and temperature. The formula is given by:
  • \[P = A imes ext{Stefan constant} imes T^4 \] where
    • \(P\) is the power in watts,
    • \(A\) is the surface area,
    • \(T\) is the absolute temperature in Kelvin.
This law provides a quantitative understanding of radiation heat transfer, illustrating the relationship between energy radiated and temperature. By grasping this concept, students can apply it to various real-world thermal situations, including heating systems, climate models, and even astrophysics.

The Stefan-Boltzmann Law is foundational knowledge for anyone studying physics, as it allows us to predict how and when heat will be transferred between different objects and environments.
Thermal Equilibrium
Thermal equilibrium occurs when two or more objects at different temperatures come into contact and exchange heat until they reach a common temperature. At this point, there is no net flow of energy between them. This concept is essential for solving problems involving energy exchange, such as the one discussed in the exercise.

In the context of our spherical ball experiment, thermal equilibrium would be reached when the power emitted by the ball equals the power it receives from its surroundings. According to the Stefan-Boltzmann Law, this can be expressed by setting the received power equal to the power emitted, essentially meaning:
  • When \[ P_{\text{received}} = P_{\text{emitted}} \]there is no more net heat flow.
This condition implies that the temperatures of surrounding areas and the ball are now balanced.

In practical terms, achieving thermal equilibrium is vital in applications such as environmental controls within buildings, designing electronic cooling systems, and even comforting climate management in vehicles. Understanding equilibrium helps engineers design systems that efficiently manage energy, emphasizing the importance of knowing when and how objects exchange or stop exchanging heat.
Blackbody Radiation
Blackbody radiation refers to the theoretical model of an ideal body that absorbs all incident electromagnetic radiation, regardless of frequency or angle of incidence. This concept helps us understand how objects emit radiation. A perfect blackbody is considered a perfect emitter as well, making it an essential model in physics.

The notion of blackbody radiation can be applied to any object that is a good absorber and emitter of radiation, much like the spherical ball in our problem. The concept is described by the Stefan-Boltzmann Law, as it helps quantify the total energy radiated per unit time:
  • The formula \[ P = ext{Stefan constant} imes A imes T^4 \]applies, emphasizing how emissivity directly relates to temperature and surface area.
The ability to approximate objects as blackbodies allows scientists and engineers to predict real-world thermal behavior more accurately.

Beyond theoretical approaches, understanding blackbody radiation is crucial in the study of thermal energy in stars, including our Sun, the efficiency of furnaces, and in measuring accurate temperatures using infrared radiation. By applying the principles of blackbody radiation, students can make profound connections between theoretical physics and practical technology.

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Most popular questions from this chapter

One end of a rod of length \(20 \mathrm{~cm}\) is inserted in a furnace at \(800 \mathrm{~K}\). The sides of the rod are covered with an insulating material and the other end emits radiation like a blackbody. The temperature of this end is \(750 \mathrm{~K}\) in the steady state. The temperature of the surrounding air is \(300 \mathrm{~K}\). Assuming radiation to be the only important mode of energy transfer between the surrounding and the open end of the rod, find the thermal conduetivity of the rod. Stefan constant \(\sigma=6 \cdot 0 \times 10^{-8} \mathrm{~W} \mathrm{~m}^{-2} \mathrm{~K}^{-4}\).

A spherical ball \(A\) of surface area \(20 \mathrm{~cm}^{2}\) is kept at the centre of a hollow spherical shell \(B\) of area \(80 \mathrm{~cm}^{2}\). The surface of \(A\) and the inner surface of \(B\) emit as blackbodies. Both \(A\) and \(B\) are at \(300 \mathrm{~K}\). (a) How much is the radiation energy emitted per second by the ball \(A ?\) (b) How much is the radiation energy emitted per second by the inner surface of \(B\) ? (c) How much of the energy emitted by the inner surface of \(B\) falls back on this surface itself ?

Water at \(50^{\circ} \mathrm{C}\) is filled in a closed cylindrical vessel of height \(10 \mathrm{~cm}\) and cross sectional area \(10 \mathrm{~cm}^{2}\). The walls of the vessel are adiabatic but the flat parts are made of \(1-\mathrm{mm} \quad\) thick \(\quad\) aluminium \(\quad\left(K=200 \mathrm{~J} \mathrm{~s}^{-1} \mathrm{~m}^{-1}{ }^{-1} \mathrm{C}^{-1}\right)\). Assume that the outside temperature is \(20^{\circ} \mathrm{C}\). The density of water is \(1000 \mathrm{~kg} \mathrm{~m}^{-5}\), and the specific heat capacity of water \(=4200 \mathrm{~J} \mathrm{k} \stackrel{-\mathrm{l}}{\mathrm{g}} \mathrm{C}^{-1}\). Estimate the time taken for the temperature to fall by \(1 \cdot 0^{\circ} \mathrm{C}\). Make any simplifying assumptions you need but specify them.

A cubical block of mass \(1 \cdot 0 \mathrm{~kg}\) and edge \(5 \cdot 0 \mathrm{~cm}\) is heated to \(227^{\circ} \mathrm{C}\). It is kept in an evacuated chamber maintained at \(27^{\circ} \mathrm{C}\). Assuming that the block emits radiation like a blackbody, find the rate at which the temperature of the block will decrease. Specific heat capacity of the material of the block is \(400 \mathrm{~J} \mathrm{~kg}^{-1} \mathrm{~K}^{-1}\).

An amount \(n\) (in moles) of a monatomic gas at an initial temperature \(T_{0}\) is enclosed in a cylindrical vessel fitted with a light piston. The surrounding air has a temperature \(T_{s}\left(>T_{0}\right)\) and the atmospheric pressure is \(p_{a} .\) Heat may be conducted between the surrounding and the gas through the bottom of the cylinder. The bottom has a surface area \(A\), thickness \(x\) and thermal conductivity \(K\). Assuming all changes to be slow, find the distance moved by the piston in time \(t\).

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