/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 A block of mass \(100 \mathrm{~g... [FREE SOLUTION] | 91Ó°ÊÓ

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A block of mass \(100 \mathrm{~g}\) slides on a rough horizontal surface. If the speed of the block decreases from \(10 \mathrm{~m} \mathrm{~s}^{-1}\) to \(5 \mathrm{~m} \mathrm{~s}^{-1}\), find the thermal energy developed in the process.

Short Answer

Expert verified
The thermal energy developed is 3.75 J.

Step by step solution

01

Convert Mass to Kilograms

The mass is given in grams, and we usually work with kilograms in physics. Convert the mass of the block from grams to kilograms:\[ 100 \text{ g} = 0.1 \text{ kg} \]
02

Calculate Initial Kinetic Energy

The initial kinetic energy (KE) can be calculated using the formula \( KE = \frac{1}{2}mv^2 \). Given the initial speed is \(10 \text{ m/s}\), calculate:\[ KE_{initial} = \frac{1}{2} \times 0.1 \, \text{kg} \times (10 \text{ m/s})^2 = 5 \text{ J} \]
03

Calculate Final Kinetic Energy

Now calculate the kinetic energy when the speed is \(5 \text{ m/s}\) using the same formula:\[ KE_{final} = \frac{1}{2} \times 0.1 \, \text{kg} \times (5 \text{ m/s})^2 = 1.25 \text{ J} \]
04

Determine Thermal Energy Developed

The decrease in kinetic energy is converted to thermal energy due to friction. Find this thermal energy by subtracting the final kinetic energy from the initial kinetic energy:\[ \text{Thermal Energy} = KE_{initial} - KE_{final} = 5 \text{ J} - 1.25 \text{ J} = 3.75 \text{ J} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. This kind of energy can be calculated using the formula \( KE = \frac{1}{2}mv^2 \), where \( m \) is the mass of the object and \( v \) is its velocity. This formula tells us that kinetic energy depends on both the mass and the velocity of the object. The greater the mass and speed, the more kinetic energy the object has.
To put it simply, whenever an object moves, it carries energy with it. For example:
  • When you throw a ball, it has kinetic energy because it's moving through the air.
  • A car driving down the street has kinetic energy due to its motion along the road.
When performing calculations, like the one in the exercise, it is important to use consistent units, usually kilograms for mass and meters per second for velocity. This ensures accurate and meaningful results in terms of energy units, which are joules in the International System of Units.
Energy Conversion
Energy conversion is a process where energy changes from one form to another. It is based on the law of conservation of energy, which states that energy cannot be created or destroyed, only transformed. In many everyday processes, energy conversion is constant and crucial. In the problem given, the decrease in kinetic energy due to the block slowing down is converted into thermal energy. Here's what happens:
  • The block starts with a specific amount of kinetic energy.
  • Due to friction, as the block slides across a rough surface, some of this kinetic energy is transformed into heat (thermal energy).
  • This thermal energy is what makes the block and the surface warmer as a result of the energy conversion.
Understanding energy conversion is essential in various fields, from engineering to environmental science, as it helps in designing systems that use energy more efficiently and sustainably.
Frictional Force
Frictional force is the resistance force that acts opposite to the direction of motion of an object. It's one of the main forces responsible for the conversion of kinetic energy into thermal energy. When a block slides across a rough surface, friction is at play.
Let's break down how it works:
  • Friction occurs because microscopic bumps and grooves on both surfaces interact.
  • This interaction opposes the motion, causing the object to slow down over time.
  • As the object loses speed due to friction, its kinetic energy decreases.
  • The "lost" kinetic energy doesn't vanish but instead is transformed into thermal energy, heating the surfaces in contact.
Friction is an important concept not only in physics but also in practical applications like braking in vehicles, sports, and machinery, where controlling or reducing friction is often necessary. In our exercise, the frictional force allowed us to find the thermal energy developed when the block's speed decreased.

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Most popular questions from this chapter

A brick weighing \(4-0 \mathrm{~kg}\) is dropped into a \(1 \cdot 0 \mathrm{~m}\) deep river from a height of \(2 \cdot 0 \mathrm{~m}\). Assuming that \(80 \%\) of the gravitational potential energy is finally converted into thermal energy, find this thermal energy in calorie.

Indian style of cooling drinking water is to keep it in a pitcher having porous walls. Water comes to the outer surface very slowly and evaporates. Most of the energy needed for evaporation is taken from the water itself and the water is cooled down. Assume that a pitcher contains \(10 \mathrm{~kg}\) of water and \(0.2 \mathrm{~g}\) of water comes out per second. Assuming no backward heat transfer from the atmosphere to the water, calculate the time in which the temperature decreases by \(5^{\circ} \mathrm{C}\). Specific heat capacity of water \(=4200 \mathrm{~J} \mathrm{~kg}^{-1}{ }^{\circ} \mathrm{C}^{-1}\) and latent heat of vaporization of water \(=2 \cdot 27 \times 10^{6} \mathrm{~J} \mathrm{~kg}^{-1}\).

A ball is dropped on a floor from a height of \(2 \cdot 0 \mathrm{~m}\). After the collision it rises up to a height of \(1 \cdot 5 \mathrm{~m}\). Assume that \(40 \%\) of the mechanical energy lost goes as thermal energy into the ball. Calculate the rise in the temperature of the ball in the collision. Heat capacity of the ball is \(800 \mathrm{~J} \mathrm{~K}^{-1}\).

A bullet of mass \(20 \mathrm{~g}\) enters into a fixed wooden bloek with a speed of \(40 \mathrm{~m} \mathrm{~s}^{-1}\) and stops in it. Find the change in internal energy during the process.

Four \(2 \mathrm{~cm} \times 2 \mathrm{~cm} \times 2 \mathrm{~cm}\) cubes of ice are taken out from a refrigerator and are put in \(200 \mathrm{ml}\) of a drink at \(10^{\circ} \mathrm{C}\). (a) Find the temperature of the drink when thermal equilibrium is attained in it. (b) If the ice cubes do not melt completely, find the amount melted. Assume that no heat is lost to the outside of the drink and that the container has negligible heat capacity. Density of ice \(=900 \mathrm{~kg} \mathrm{~m}^{-3}\), density of the drink \(=1000 \mathrm{~kg} \mathrm{~m}^{-3}\) specific heat capacity of the drink \(=4200 \mathrm{~J} \mathrm{~kg}^{-1} \mathrm{~K}^{-1}\), latent heat of fusion of ice \(=3 \cdot 4 \times 10^{8} \mathrm{~J} \mathrm{~kg}^{-1}\).

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