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\(50 \mathrm{~m}^{3}\) of saturated vapour is cooled down from \(30^{\circ} \mathrm{C}\) to \(20^{\circ} \mathrm{C}\). Find the mass of the water condensed. The absolute humidity of saturated water vapour is \(30 \mathrm{~g} \mathrm{~m}^{-3}\) at \(30^{\circ} \mathrm{C}\) and \(16 \mathrm{~g} \mathrm{~m}^{-3}\) at \(20^{\circ} \mathrm{C}\).

Short Answer

Expert verified
700 g of water is condensed.

Step by step solution

01

Calculate Mass at Initial Temperature

First, calculate the mass of water vapor present in the air at the initial temperature of \(30^{\circ} \mathrm{C}\). Use the formula for calculating mass from absolute humidity:\[m_{initial} = \text{Volume} \times \text{Absolute Humidity at } 30^{\circ} \mathrm{C}\]Inserting the given values:\[m_{initial} = 50 \, \mathrm{m}^3 \times 30 \, \mathrm{g/m}^3 = 1500 \, \mathrm{g}\]
02

Calculate Mass at Final Temperature

Next, determine the mass of water vapor the air can hold at the final temperature of \(20^{\circ} \mathrm{C}\) using a similar formula:\[m_{final} = \text{Volume} \times \text{Absolute Humidity at } 20^{\circ} \mathrm{C}\]Insert the values:\[m_{final} = 50 \, \mathrm{m}^3 \times 16 \, \mathrm{g/m}^3 = 800 \, \mathrm{g}\]
03

Calculate the Mass Condensed

Finally, find the mass of water that has condensed by finding the difference between the initial and final mass of water vapor:\[m_{condensed} = m_{initial} - m_{final}\]Substitute the previously calculated values:\[m_{condensed} = 1500 \, \mathrm{g} - 800 \, \mathrm{g} = 700 \, \mathrm{g}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Absolute Humidity
Absolute humidity is a measure of the actual amount of water vapor present in the air, expressed as the mass of water vapor per unit volume of air. In this context, it is described in grams per cubic meter (\[\text{g/m}^3\]). When you look at absolute humidity, it tells you how much moisture is in the air at a given moment, regardless of temperature.

To understand this better, consider the initial condition in the exercise. The air at \[30^{\circ} \text{C}\] can hold a moisture content of \[30 \, \text{g/m}^3\]. This means every cubic meter of that air contains 30 grams of water vapor. As the temperature drops to \[20^{\circ} \text{C}\], absolute humidity decreases to \[16 \, \text{g/m}^3\] because cooler air can hold less water vapor. This decrease in humidity is important because it leads to the process of condensation.
Saturated Vapour
Saturated vapour is a state where the air contains the maximum possible amount of water vapor for a given temperature. Beyond this point, any additional water vapor will start to condense into liquid water. In other words, the air has reached its capacity to hold moisture at that temperature. Saturated vapor pressure rises with temperature, meaning warm air can hold more water vapor than cold air.

In the provided exercise, initially, the air at \[30^{\circ} \text{C}\] is saturated with water vapor. As the temperature decreases to \[20^{\circ} \text{C}\], the capacity of the air to hold water vapor decreases, and any excess moisture will condense as liquid water. This is the principle behind cloud formation and precipitation in weather systems.
Temperature Change
Temperature change plays a crucial role in determining the ability of air to hold water vapor. As temperature increases, air can hold more water vapor, and as temperature decreases, this capacity lessens. This relationship is depicted through the concept of saturation, where, at a certain temperature, air can no longer hold additional water vapor, resulting in condensation.

In the exercise, cooling the air from \[30^{\circ} \text{C}\] to \[20^{\circ} \text{C}\] causes a reduction in the amount of water vapor the air can hold. Since the initial amount of vapor was at the saturation limit for \[30^{\circ} \text{C}\], decreasing the temperature leads to condensation; the air at \[20^{\circ} \text{C}\] can only retain a smaller amount of vapor (as determined by the new absolute humidity), and the surplus is released as liquid water. This process is crucial in understanding not only atmospheric processes but also how humidity affects our daily weather.

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Most popular questions from this chapter

A vertical cylinder of height \(100 \mathrm{~cm}\) contains air at a constant temperature. The top is closed by a frictionless light piston. The atmospheric pressure is equal to \(75 \mathrm{~cm}\) of mercury. Mercury is slowly poured over the piston. Find the maximum height of the mercury column that can be put on the piston.

The temperature and relative humidity in a room are \(300 \mathrm{~K}\) and \(20 \%\) respectively. The volume of the room is \(50 \mathrm{~m}^{3}\). The saturation vapour pressure at \(300 \mathrm{~K}\) is \(3.3 \mathrm{kPa}\). Calculate the mass of the water vapour present in the room.

Oxygen is filled in a closed metal jar of volume \(1 \cdot 0 \times 10^{-3} \mathrm{~m}^{3}\) at a pressure of \(1.5 \times 10^{5} \mathrm{~Pa}\) and temperature \(400 \mathrm{~K}\). The jar has a small leak in it. The atmospheric pressure is \(1.0 \times 10{ }^{5} \mathrm{~Pa}\) and the atmospheric temperature is \(300 \mathrm{~K}\). Find the mass of the gas that leaks out by the time the pressure and the temperature inside the jar equalise with the surrounding.

Hydrogen gas is contained in a closed vessel at 1 atm \((100 \mathrm{kPa})\) and \(300 \mathrm{~K}\). (a) Calculate the mean speed of the molecules. (b) Suppose the molecules strike the wall with this speed making an average angle of \(45^{\circ}\) with it. How many molecules strike each square metre of the wall per second?

Figure (24-E1) shows a cylindrical tube with adiabatic walls and fitted with a diathermic separator. The separator can be slid in the tube by an external mechanism. An ideal gas is injected into the two sides at equal pressures and equal temperatures. The separator remains in equilibrium at the middle. It is now slid to a position where it divides the tube in the ratio of \(1: 3\). Find the ratio of the pressures in the two parts of the vessel.

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