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In a factory it is desired to lift \(2000 \mathrm{~kg}\) of metal through a distance of \(12 \mathrm{~m}\) in 1 minute. Find the minimum horsepower of the engine to be used.

Short Answer

Expert verified
The engine should have a minimum of 5.25 horsepower.

Step by step solution

01

Calculate the Work Done

The first step is to calculate the work done to lift the metal. Work done (W) is given by the formula: \( W = F \times d \), where \( F \) is the force and \( d \) is the distance. The force needed to lift the metal is its weight, which is given by \( F = m \times g \), where \( m \) is the mass (2000 kg) and \( g \) is the acceleration due to gravity (approximately \( 9.8 \ \mathrm{m/s}^2 \)). Thus, \( F = 2000 \times 9.8 = 19600 \ \mathrm{N} \). The work done is then \( 19600 \ \mathrm{N} \times 12 \ \mathrm{m} = 235200 \ \mathrm{J} \).
02

Convert Work Done to Power

Power is the rate of doing work, given by \( P = \frac{W}{t} \), where \( t \) is the time. Here, the time is 1 minute, which is 60 seconds. Hence, the power needed is \( P = \frac{235200 \ \mathrm{J}}{60 \ \mathrm{s}} = 3920 \ \mathrm{W} \).
03

Convert Power from Watts to Horsepower

Since power in the question needs to be in horsepower (hp), we need to convert watts to horsepower. 1 horsepower is equivalent to approximately 746 watts. Therefore, \( \text{power in horsepower} = \frac{3920}{746} \approx 5.25 \ \mathrm{hp} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Work Done
To comprehend the concept of **work done**, imagine you want to lift an object to a certain height. The effort you put in to move it against gravity is what we refer to as work done. In physics, work is calculated using the formula:
  • \( W = F \times d \)
where \( W \) is the work done, \( F \) is the force applied, and \( d \) is the distance over which the force is applied.

When lifting an object, the force needed is equal to its weight, which is the product of its mass and the gravitational pull. For example, lifting a metal block with a mass of \( 2000 \ \mathrm{kg} \) involves overcoming a force of \( 2000 \times 9.8 = 19600 \ \mathrm{N} \). If you lift it through a distance of \( 12 \ \mathrm{m} \), the work done becomes \( 19600 \ \mathrm{N} \times 12 \ \mathrm{m} = 235200 \ \mathrm{J} \) (Joules). Understanding this calculation is vital as it forms the basis for calculating further requirements, such as power.
Force and Motion in Power Calculation
Once you have determined the **work done**, converting this into power is essential to comprehend how swiftly the task is performed. Power is essentially the rate at which work is done. Mathematically, power is expressed as:
  • \( P = \frac{W}{t} \)
where \( P \) is power, \( W \) is work done, and \( t \) is time.

In our example, lifting the metal in \( 1 \mathrm{~minute} \) (\( 60 \seconds \)) means spreading the 235200 Joules of work over 60 seconds, resulting in a power requirement of \( \frac{235200 \ \mathrm{J}}{60 \ \mathrm{s}} = 3920 \ \mathrm{W} \) (Watts). This tells us the efficiency of force usage over time. Furthermore, understanding this helps address practical design decisions, such as selecting machinery that can sustain desired outputs over time. Power directly relates to how quickly motion, via applied force, achieves the intended effect.
Horsepower Conversion Made Simple
In real-world applications, especially involving engines and machinery, power is often measured in **horsepower** (hp). Converting between Watts and horsepower is crucial for tasks such as machinery selection and evaluation, particularly for those familiar only with horsepower ratings. The conversion is straightforward:
  • 1 horsepower ≈ 746 watts
To convert power from Watts to horsepower:
  • Divide the power in Watts by 746.
For example, the power required to lift the metal in our example is originally calculated as \( 3920 \ \mathrm{W} \). Converting this to horsepower involves:
  • \( \frac{3920}{746} \approx 5.25 \ \mathrm{hp} \)
This is the minimum horsepower needed for the engine in our scenario. Understanding this conversion is essential when dealing with specifications and making informed decisions based on familiar units.

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Most popular questions from this chapter

A uniform chain of mass \(m\) and length \(l\) overhangs a table with its two third part on the table. Find the work to be done by a person to put the hanging part back on the table.

A small block of mass \(100 \mathrm{~g}\) is pressed against a horizontal spring fixed at one end to compress the spring through \(5 \cdot 0 \mathrm{~cm}\) (figure 8-E11). The spring constant is \(100 \mathrm{~N} / \mathrm{m}\). When released, the block moves horizontally till it leaves the spring. Where will it hit the ground \(2 \mathrm{~m}\) below the spring?

A chain of length \(l\) and mass \(m\) lies on the surface of a smooth sphere of radius \(R>l\) with one end tied to the top of the sphere. (a) Find the gravitational potential energy of the chain with reference level at the centre of the sphere. (b) Suppose the chain is released and slides down the sphere. Find the kinetic energy of the chain, when it has slid through an angle \(\theta\). (c) Find the tangential acceleration \(\frac{d v}{d t}\) of the chain when the chain starts sliding down.

A water pump lifts water from a level \(10 \mathrm{~m}\) below the ground. Water is pumped at a rate of \(30 \mathrm{~kg} /\) minute with negligible velocity. Calculate the minimum horsepower the engine should have to do this.

A block weighing \(10 \mathrm{~N}\) travels down a smooth curved track \(A B\) joined to a rough horizontal surface (figure 8-E5). The rough surface has a friction coefficient of 0 - 20 with the block. If the block starts slipping on the track from a point \(1 \cdot 0 \mathrm{~m}\) above the horizontal surface, how far will it move on the rough surface?

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