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A convex lens of focal length \(20 \mathrm{~cm}\) and a concave lens of focal length \(10 \mathrm{~cm}\) are placed \(10 \mathrm{~cm}\) apart with their principal axes coinciding. A beam of light travelling parallel to the principal axis and having a beam diameter \(5 \cdot 0 \mathrm{~mm}\), is incident on the combination. Show that the emergent beam is parallel to the incident one. Find the beam diameter of the emergent beam.

Short Answer

Expert verified
The emergent beam is parallel to the incident beam with the same beam diameter of 5.0 mm.

Step by step solution

01

Determine Total Focal Length using Lens Combination Formula

To find out if the emergent beam is parallel to the incident beam, we need to determine the total focal length of the lens combination. Use the lens formula for a combination of lenses:\[ \frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2} - \frac{d}{f_1 f_2} \]where \( F \) is the focal length of the combination, \( f_1 = 20 \mathrm{~cm} \) is the focal length of the convex lens, \( f_2 = -10 \mathrm{~cm} \) is the focal length of the concave lens (note that it is negative for concave lenses) and \( d = 10 \mathrm{~cm} \) is the separation between the lenses. Plug in these values:
02

Calculate Combined Focal Length

Substitute the values into the lens combination formula:\[ \frac{1}{F} = \frac{1}{20} + \frac{1}{-10} - \frac{10}{20 \times -10} \]Simplify this equation:\[ \frac{1}{F} = \frac{1}{20} - \frac{1}{10} + \frac{1}{20} \]Now, solve for \( \frac{1}{F} \):\[ \frac{1}{F} = 0 \]Thus, \( F = \infty \). This tells us that the emergent beam is indeed parallel to the incident beam because the combination acts as if it has an infinite focal length.
03

Analyze Beam Diameter after Lens System

Since the emergent beam is parallel to the incident beam, the beam diameter remains unchanged. When a beam of light emerges parallel, the only way its diameter will change is in cases involving converging or diverging actions, which do not occur here.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convex Lens
A convex lens, often called a converging lens, is designed to converge light rays that initially travel parallel to its principal axis. This lens is thicker at the center than at the edges, a shape important for its converging properties. When parallel rays of light pass through a convex lens, they are bent inwards towards a single focal point on the opposite side of the lens. This is because of its convex shape that refracts light. The focal point is the location where light rays meet after passing through the lens and is crucial in determining the lens' focal length. The focal length of a lens is the distance from the center of the lens to its focal point. To summarize, a convex lens is characterized by:
  • Its ability to converge light rays.
  • A thicker center than edges.
  • A positive focal length.
This property makes convex lenses useful in applications like magnifying glasses, cameras, and eyeglasses for farsightedness.
Concave Lens
The concave lens, in contrast to the convex lens, is a diverging lens. It is thinner in the middle and thicker at the edges. This shape causes parallel incoming light rays to diverge or spread apart. When light passes through a concave lens, it is refracted away from the principal axis. Imagine how the lens affects a beam of parallel rays. After passing through, the rays appear to originate from a single focal point on the same side of the lens as the incoming light. This focal point would be the center of the divergence, giving the lens its characteristic negative focal length. Essential characteristics of a concave lens include:
  • Thinner center compared to the edges.
  • Negative focal length due to divergence.
  • Use in applications to address nearsightedness and in various optical devices.
Concave lenses are essential for spreading out light and correcting vision that requires divergence.
Focal Length
Focal length is a central concept in optics, defining the distance from the center of the lens to its focal point. Whether dealing with a convex or concave lens, understanding focal length is crucial for predicting the behavior of light passing through the lens.For a convex lens, the focal length is positive. This positive value indicates that light rays converge after passing through the lens. Conversely, for concave lenses, the focal length is negative, pointing to the divergence of light rays.When combining lenses, the total focal length of the system can be determined using the lens formula:\[\frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2} - \frac{d}{f_1 f_2}\]where \( F \) is the focal length of the lens combination, \( f_1 \) and \( f_2 \) are the focal lengths of the individual lenses, and \( d \) is the distance between them. The formula accounts for how each lens modifies the light path, allowing predictions for the behavior of light through complex lens systems.Grasping focal length helps in understanding how lenses focus light, enabling us to design a variety of optical devices like cameras, glasses, and microscopes.

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Most popular questions from this chapter

A converging lens of focal length \(15 \mathrm{~cm}\) and a converging mirror of focal length \(10 \mathrm{~cm}\) are placed \(50 \mathrm{~cm}\) apart with common principal axis. A point source is placed in between the lens and the mirror at a distance of \(40 \mathrm{~cm}\) from the lens. Find the locations of the two images formed.

One end of a cylindrical glass rod \((\mu=1 \cdot 5)\) of radius \(1 \cdot 0 \mathrm{~cm}\) is rounded in the shape of a hemisphere. The rod is immersed in water \((\mu=4 / 3)\) and an object is placed in the water along the axis of the \(\operatorname{rod}\) at a distance of \(8 \cdot 0 \mathrm{~cm}\) from the rounded edge. Locate the image of the object.

A point object is placed on the principal axis of a convex lens \((f=15 \mathrm{~cm})\) at a distance of \(30 \mathrm{~cm}\) from it. A glass plate \((\mu=1 \cdot 50)\) of thickness \(1 \mathrm{~cm}\) is placed on the other side of the lens perpendicular to the axis. Locate the image of the point object.

A thin lens made of a material of refractive index \(\mu_{2}\) has a medium of refractive index \(\mu_{1}\) on one side and a medium of refractive index \(\mu_{3}\) on the other side. The lens is biconvex and the two radii of curvature have equal magnitude \(R\). A beam of light travelling parallel to the principal axis is incident on the lens. Where will the image be formed if the beam is incident from (a) the medium \(\mu_{1}\) and (b) from the medium \(\mu_{3}\) ?

A particle goes in a circle of radius \(2 \cdot 0 \mathrm{~cm} .\) A concave mirror of focal length \(20 \mathrm{~cm}\) is placed with its principal axis passing through the centre of the circle and perpendicular to its plane. The distance between the pole of the mirror and the centre of the circle is \(30 \mathrm{~cm}\). Calculate the radius of the circle formed by the image.

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