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A concave mirror forms an image of \(20 \mathrm{~cm}\) high object on a screen placed \(5 \cdot 0 \mathrm{~m}\) away from the mirror. The height of the image is \(50 \mathrm{~cm}\). Find the focal length of the mirror and the distance between the mirror and the object.

Short Answer

Expert verified
Focal length is approximately -333.33 cm and object distance is 200 cm.

Step by step solution

01

Understanding the Given Information

We have a concave mirror with an object height of 20 cm and an image height of 50 cm. The image distance from the mirror is 5 meters, which we convert to centimeters for consistency: 5 meters = 500 cm. We need to find the focal length of the mirror and the object distance.
02

Use the Magnification Formula

The magnification formula for mirrors is defined by the equation \( m = \frac{h_i}{h_o} = \frac{-v}{u} \), where \( h_i \) is the image height, \( h_o \) is the object height, \( v \) is the image distance, and \( u \) is the object distance. Plugging in the known values: \( m = \frac{50}{20} = \frac{-500}{u} \).
03

Solve for Object Distance

Simplifying the magnification equation, we get \( \frac{5}{2} = \frac{-500}{u} \). Solving for \( u \) gives \( u = \frac{-500 \times 2}{5} \). Calculate this to find \( u = -200 \) cm. The object distance is 200 cm.
04

Use Mirror Formula to Find Focal Length

The mirror formula is \( \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \). We know \( v = 500 \) cm and \( u = -200 \) cm. Substitute these into the mirror formula: \( \frac{1}{f} = \frac{1}{500} + \frac{1}{-200} \).
05

Simplify and Solve for Focal Length

Compute the right-hand side: \( \frac{1}{500} + \frac{1}{-200} = \frac{1}{500} - \frac{1}{200} = \frac{1}{500} - \frac{5}{1000} = \frac{1 - 2.5}{500} = \frac{-1.5}{500} = \frac{-3}{1000} \). Calculate \( f \): \( f = -\frac{1000}{3} \), which results in \( f \approx -333.33 \) cm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnification Formula
The magnification formula is a crucial concept when dealing with mirrors, especially concave mirrors. In essence, it helps us understand the relationship between the size of the image and the object. The formula is:\[ m = \frac{h_i}{h_o} = \frac{-v}{u} \]Here,
  • \( m \) is the magnification, indicating how much larger or smaller the image is compared to the object.
  • \( h_i \) is the height of the image, while \( h_o \) is the height of the object.
  • \( v \) is the distance from the mirror to the image and \( u \) is the distance from the mirror to the object.

The negative sign in the formula \( \left(-\frac{v}{u}\right) \) comes from the convention used in optics, which defines the distances in a particular way for mirrors. When solving problems, always check if the values are consistent, like using the same units. This formula lets us find one unknown if we know the others, as we did for the object distance in the original problem.
Mirror Formula
The mirror formula is another fundamental principle when studying mirrors. It relates the object and image distances with the focal length of the mirror. The formula is:\[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \]In this equation,
  • \( f \) represents the focal length of the mirror, a critical property that defines how the mirror focuses light.
  • \( v \) is the image distance from the mirror.
  • \( u \) is the object distance from the mirror.

The process involves substituting the known values into the formula, solving for the unknown. In this exercise, we applied known values of \( v = 500 \) cm and \( u = -200 \) cm to determine the focal length. Understanding how to manipulate this formula is essential in optics, allowing you to transition between these distances easily.
Focal Length Calculation
Calculating the focal length of a mirror is often a key step in solving optics problems involving mirrors. The focal length \( f \) is a measure of how a concave mirror converges light to a focal point. In our exercise, we used the mirror formula:\[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \]By substituting the known values:
  • \( \frac{1}{v} = \frac{1}{500} \)
  • \( \frac{1}{u} = \frac{1}{-200} \)

The right-hand side of the equation simplifies to:\[ \frac{1}{500} - \frac{1}{200} = \frac{-3}{1000} \]From this, we solve for \( f \) by inverting the result:\[ f = -\frac{1000}{3} \approx -333.33 \text{ cm} \]This negative value indicates that the focal point is on the same side of the mirror as the object, which is typical for concave mirrors. Understanding focal length calculation is vital in determining how mirrors affect the path of light.

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Most popular questions from this chapter

A container contains water up to a height of \(20 \mathrm{~cm}\) and there is a point source at the centre of the bottom of the container. \(A\) rubber ring of radius \(r\) floats centrally on the water. The ceiling of the room is \(2 \cdot 0 \mathrm{~m}\) above the water surface. (a) Find the radius of the shadow of the ring formed on the ceiling if \(r=15 \mathrm{~cm} .\) (b) Find the maximum value of \(r\) for which the shadow of the ring is formed on the ceiling. Refractive index of water \(=4 / 3\)

A narrow pencil of parallel light is incident normally on a solid transparent sphere of radius \(r\). What should be the refractive index if the pencil is to be focussed (a) at the surface of the sphere, (b) at the centre of the sphere.

A convex lens has a focal length of \(10 \mathrm{~cm}\). Find the location and nature of the image if a point object is placed on the principal axis at a distance of (a) \(9 \cdot 8 \mathrm{~cm}\), (b) \(10 \cdot 2 \mathrm{~cm}\) from the lens.

A gun of mass \(M\) fires a bullet of mass \(m\) with a horizontal speed \(V\). The gun is fitted with a concave mirror of focal length \(f\) facing towards the receding bullet. Find the speed of separation of the bullet and the image just after the gun was fired.

A particle is moving at a constant speed \(V\) from a large distance towards a concave mirror of radius \(R\) along its principal axis. Find the speed of the image formed by the mirror as a function of the distance \(x\) of the particle from the mirror.

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