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The first overtone frequency of a closed organ pipe \(P_{1}\) is equal to the fundamental frequency of an open organ pipe \(P_{2}\). If the length of the pipe \(P_{1}\) is \(30 \mathrm{~cm}\), what will be the length of \(P_{2}\) ?

Short Answer

Expert verified
The length of the open pipe \( P_2 \) will be 20 cm.

Step by step solution

01

Understanding the Problem

In this problem, we have a closed organ pipe \( P_1 \) and an open organ pipe \( P_2 \). We need to find the length of \( P_2 \) such that the first overtone frequency of the closed pipe is equal to the fundamental frequency of the open pipe.
02

Identifying the Formulas

For a closed organ pipe, the first overtone frequency is the third harmonic, which is given by \( f_{1} = \frac{3v}{4L_1} \), where \( L_1 \) is the length of the closed pipe and \( v \) is the speed of sound. For an open pipe, the fundamental frequency is \( f_{2} = \frac{v}{2L_2} \), where \( L_2 \) is the length of the open pipe.
03

Setting the Frequencies Equal

Equate the first overtone of the closed pipe to the fundamental frequency of the open pipe: \( \frac{3v}{4L_1} = \frac{v}{2L_2} \).
04

Simplifying the Equation

Cancel out the speed of sound \( v \) from both sides of the equation to get: \( \frac{3}{4L_1} = \frac{1}{2L_2} \).
05

Solving for \( L_2 \)

Rearrange the equation to solve for \( L_2 \): \( L_2 = \frac{2L_1}{3} \).
06

Substituting the Given Length

Substitute \( L_1 = 0.3 \) meters (since 30 cm = 0.3 meters) into the equation: \( L_2 = \frac{2 \times 0.3}{3} = 0.2 \) meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Harmonics in Physics
Harmonics are fundamental concepts in physics connected to the vibrations of physical objects. When a system like a pipe or string vibrates, it tends to produce a series of frequencies. These frequencies are known as the harmonics. The lowest frequency is the fundamental frequency, and the higher ones are called overtones. In the context of organ pipes, these vibrations are what create different sounds or pitches.

An important aspect of harmonics is their pattern. In a closed pipe, only odd harmonics are present. This means that if the fundamental frequency is the first harmonic, the "first overtone" is actually the third harmonic, producing a frequency three times the fundamental. In contrast, open pipes support both even and odd harmonics. The overtone series can have all whole number multiples of the fundamental frequency. This distinction is key in understanding how pipes produce sound and why they sound different from one another.
Speed of Sound
The speed of sound is a crucial factor in determining the frequencies of sound waves in different media. This speed is the rate at which sound waves travel through a medium. In air, the speed of sound is approximately 343 meters per second at room temperature. This speed can vary with temperature and pressure, which can affect how sound waves are perceived.

When calculating the frequencies of harmonics, the speed of sound ( v ) is a vital variable. In formulas for harmonics in pipes, such as for closed or open pipes, the speed of sound plays a role in computing the frequency of sound waves produced. Understanding this allows us to calculate how long or short a pipe needs to be to produce a specific pitch when played.
Closed vs Open Pipes
Closed and open pipes function differently and produce unique sets of harmonics. A closed pipe is closed at one end and open at the other, whereas an open pipe is open at both ends. These structural differences lead to different patterns of standing waves and thus different harmonic series.

In closed pipes, the boundary condition allows for only odd harmonics. Therefore, if you were to measure the sound frequencies, you wouldn't find the second harmonic, only the first, third, and so on. Open pipes, however, can generate both even and odd harmonics. This means they can produce a wider range of tones.

In practical terms, these differences explain why certain musical instruments produce specific sounds and how instrument makers design them to create desired pitches and tones. Understanding the physics behind closed and open pipes is critical for anyone studying acoustics or working with sound.

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Most popular questions from this chapter

Two point sources of sound are kept at a separation of \(10 \mathrm{~cm} .\) They vibrate in phase to produce waves of wavelength \(5 \cdot 0 \mathrm{~cm} .\) What would be the phase difference between the two waves arriving at a point \(20 \mathrm{~cm}\) from one source (a) on the line joining the sources and (b) on the perpendicular bisector of the line joining the sources?

In Quincke's experiment the sound detected is changed from a maximum to a minimum when the sliding tube is moved through a distance of \(2 \cdot 50 \mathrm{~cm}\). Find the frequency of sound if the speed of sound in air is \(340 \mathrm{~m} \mathrm{~s}^{-1}\).

If the sound level in a room is increased from \(50 \mathrm{~dB}\) to \(60 \mathrm{~dB}\), by what factor is the pressure amplitude increased?

A U-tube having unequal arm-lengths has water in it. A tuning fork of frequency \(440 \mathrm{~Hz}\) can set up the air in the shorter arm in its fundamental mode of vibration and the same tuning fork can set up the air in the longer arm in its first overtone vibration. Find the length of the air columns. Neglect any end effect and assume that the speed of sound in air \(=330 \mathrm{~m} \mathrm{~s}^{-1}\).

A source of sound operates at \(2 \cdot 0 \mathrm{kHz}, 20 \mathrm{~W}\) emitting sound uniformly in all directions. The speed of sound in air is \(340 \mathrm{~m} \mathrm{~s}^{-1}\) and the density of air is \(1 \cdot 2 \mathrm{~kg} \mathrm{~m}^{-3}\). (a) What is the intensity at a distance of \(6 \cdot 0 \mathrm{~m}\) from the source? (b) What will be the pressure amplitude at this point? (c) What will be the displacement amplitude at this point?

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