/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 A closed organ pipe can vibrate ... [FREE SOLUTION] | 91Ó°ÊÓ

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A closed organ pipe can vibrate at a minimum frequency of \(500 \mathrm{~Hz}\). Find the length of the tube. Speed of sound in air \(=340 \mathrm{~m} \mathrm{~s}^{-1}\).

Short Answer

Expert verified
The length of the tube is 0.17 meters.

Step by step solution

01

Understand the Relationship

In a closed pipe, only odd harmonics are present. The fundamental frequency corresponds to the first harmonic mode, described by the equation: \[ f = \frac{v}{4L} \]where \(f\) is the frequency, \(v\) is the speed of sound, and \(L\) is the length of the pipe.
02

Rearrange the Formula

To find the length \(L\) of the pipe, we rearrange the formula:\[ L = \frac{v}{4f} \]
03

Substitute Values

Substitute the given values into the formula: the speed of sound \(v = 340 \, \text{m/s}\) and the frequency \(f = 500 \, \text{Hz}\):\[ L = \frac{340}{4 \times 500} \]
04

Calculate the Length

Perform the calculation:\[ L = \frac{340}{2000} = 0.17 \, \text{m} \]So, the length of the tube is \(0.17\) meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Harmonics in Pipes
Understanding harmonics in closed organ pipes is crucial for grasping how they produce sound. A closed organ pipe, unlike an open one, only supports certain types of harmonics. Specifically, it allows odd harmonics, such as the first, third, and fifth harmonics. This configuration happens because one end of the pipe is closed, forcing the air to reflect and create a specific pattern of standing waves.
The first harmonic mode, or the fundamental frequency, is the lowest and forms when the air vibrates in one quarter of its wavelength. This means the closed end represents a node (where there is minimal air movement), and the open end is an antinode (where there is maximum air movement).
For practical purposes, remember:
  • Closed pipes only support odd harmonics.
  • The fundamental frequency is the lowest possible sound frequency in the pipe.
  • Each harmonic refers to a multiple of the fundamental frequency but for closed pipes, it skips even multiples.
Fundamental Frequency
The fundamental frequency is at the core of sound production in closed pipes. It is the lowest frequency at which the pipe can naturally resonate. This frequency is determined by the length of the pipe, as well as the speed of sound in the medium filling the pipe - often air in this context. In closed pipes, this fundamental frequency results from the air column vibrating at its simplest mode, characterized by a wavelength four times the length of the pipe.
This relationship can be expressed with the formula:
\[ f = \frac{v}{4L} \]
Where:
- \( f \) is the fundamental frequency
- \( v \) is the speed of sound
- \( L \) is the length of the pipe
By understanding this basic relationship, we can determine how variations in the length or speed of sound affect the frequency. It's a foundational principle that applies to many real-world phenomena, from musical instruments to acoustic engineering.
Speed of Sound
The speed of sound is a pivotal factor in the calculation of frequencies in organ pipes. It is the rate at which sound waves propagate through the air, or any given medium. For air, under normal conditions, the speed of sound is around 340 meters per second. This speed can change based on several factors, including temperature, humidity, and the type of gas molecules in the air.
In the context of a closed organ pipe, the speed of sound affects the frequency of the harmonics generated. The faster the sound travels, the higher the frequency of the sound waves. Therefore, knowing the speed of sound is essential for calculating any pipe's resonant frequencies accurately.
  • Temperature increase leads to an increase in speed of sound.
  • The speed helps to determine how quickly a sound arrives at the ear from its source.
  • Variation in speed affects pitch perception in musical instruments.
By building a solid understanding of the speed of sound, you can better understand its role in the physics of sound and harmonics in musical instruments.

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Most popular questions from this chapter

Find the change in the volume of \(1 \cdot 0\) litre kerosene when it is subjected to an extra pressure of \(2 \cdot 0 \times 10^{5} \mathrm{~N} \mathrm{~m}^{-2}\) from the following data. Density of kerosene \(=800 \mathrm{~kg} \mathrm{~m}^{-3}\) and speed of sound in kerosene \(=1330 \mathrm{~m} \mathrm{~s}^{-1}\).

A tuning fork of frequency \(256 \mathrm{~Hz}\) produces 4 beats per second with a wire of length \(25 \mathrm{~cm}\) vibrating in its fundamental mode. The beat frequency decreases when the length is slightly shortened. What could be the minimum length by which the wire be shortened so that it produces no beats with the tuning fork?

Two sources of sound, \(S_{1}\) and \(S_{2}\), emitting waves of equal wavelength \(20^{\circ} 0 \mathrm{~cm}\), are placed with a separation of \(20 \cdot 0 \mathrm{~cm}\) between them. A detector can be moved on a line parallel to \(S_{1} S_{2}\) and at a distance of \(20 \cdot 0 \mathrm{~cm}\) from it. Initially, the detector is equidistant from the two sources. Assuming that the waves emitted by the sources are in phase, find the minimum distance through which the detector should be shifted to detect a minimum of sound.

Two identical tuning forks vibrating at the same frequency \(256 \mathrm{~Hz}\) are kept fixed at some distance apart. A listener runs between the forks at a speed of \(3 \cdot 0 \mathrm{~m} / \mathrm{s}\) so that he approaches one tuning fork and recedes from the other (figure \(16-\mathrm{E} 10\) ). Find the beat frequency observed by the listener. Speed of sound in air \(=332 \mathrm{~m} / \mathrm{s}\)

A U-tube having unequal arm-lengths has water in it. A tuning fork of frequency \(440 \mathrm{~Hz}\) can set up the air in the shorter arm in its fundamental mode of vibration and the same tuning fork can set up the air in the longer arm in its first overtone vibration. Find the length of the air columns. Neglect any end effect and assume that the speed of sound in air \(=330 \mathrm{~m} \mathrm{~s}^{-1}\).

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