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A boy is seated in a revolving chair revolving at an angular speed of 120 revolutions per minute. Two heavy balls form part of the revolving system and the boy can pull the balls closer to himself or may push them apart. If by pulling the balls closer, the boy decreases the moment of inertia of the system from \(6 \mathrm{~kg}-\mathrm{m}^{2}\) to \(2 \mathrm{~kg} \cdot \mathrm{m}^{2}\) what will be the new angular speed?

Short Answer

Expert verified
The new angular speed is 360 revolutions per minute.

Step by step solution

01

Understand the Conservation of Angular Momentum

Angular momentum is conserved in a closed system if no external torque is acting on it. Thus, the initial angular momentum of the boy with the balls will be equal to the final angular momentum. Mathematically, it is represented as \( L_i = L_f \), where \( L_i \) is the initial angular momentum and \( L_f \) is the final angular momentum.
02

Calculate Initial Angular Momentum

Angular momentum \( L \) is the product of the moment of inertia \( I \) and the angular speed \( \omega \). The initial moment of inertia \( I_i \) is given as \( 6 \, \text{kg} \, \text{m}^2\) and the initial angular speed \( \omega_i \) is 120 revolutions per minute. Converting this to radians per second, we use the conversion factor: \( 2\pi \) radians equals 1 revolution, and 60 seconds in one minute:\[\omega_i = 120 \times \frac{2\pi}{60} = 4\pi \, \text{rad/s}\]Thus, the initial angular momentum is:\[L_i = I_i \cdot \omega_i = 6 \cdot 4\pi = 24\pi \, \text{kg} \, \text{m}^2/ ext{s}\]
03

Use Conservation of Angular Momentum

Since angular momentum is conserved, set the initial angular momentum equal to the final angular momentum:\[L_f = L_i = 24\pi \, \text{kg} \, \text{m}^2/ ext{s}\]Given that the final moment of inertia \( I_f \) is \( 2 \, \text{kg} \, \text{m}^2 \), we have:\[L_f = I_f \cdot \omega_f = 2 \cdot \omega_f\]
04

Solve for Final Angular Speed

Since \( L_f = 24\pi \, \text{kg} \, \text{m}^2/ ext{s} \) and \( L_f = 2 \cdot \omega_f \), we set the equations equal:\[2 \cdot \omega_f = 24\pi\]Now, solve for \( \omega_f \):\[\omega_f = \frac{24\pi}{2} = 12\pi \, \text{rad/s}\]
05

Convert Final Angular Speed to Revolutions Per Minute

Convert \( \omega_f = 12\pi \, \text{rad/s} \) back to revolutions per minute using the conversion:\[\omega_f = 12\pi \times \frac{60}{2\pi} = 360 \, \text{rev/min}\]Thus, the new angular speed is 360 revolutions per minute.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Speed
Angular speed refers to how quickly an object rotates or revolves around a particular axis. It's a measure of the rate of rotation and is typically expressed in units like radians per second or revolutions per minute.
To visualize, imagine a spinning top. The faster it spins, the higher its angular speed. For mathematical calculations, angular speed is often represented by the Greek letter omega (\(\omega\)).
In the context of the exercise, the boy in a revolving chair initially spins at an angular speed of 120 revolutions per minute. When he pulls the balls closer, the system's moment of inertia changes, affecting its angular speed due to the conservation of angular momentum.

Converting between units is crucial here:
  • From revolutions per minute (rpm) to radians per second (rad/s), use \(1\, \text{revolution} = 2\pi\, \text{radians}\), and there are \(60 \) seconds in a minute.
This way, conversions ensure clarity in calculations, allowing for straightforward interpretation and application of angular velocity in different contexts.
Moment of Inertia
The concept of moment of inertia is pivotal when discussing rotational dynamics. It represents the distribution of mass in relation to an axis of rotation and determines how much torque is needed for a desired angular acceleration.
Simply put, the moment of inertia is to rotational movement what mass is to linear movement. It's a measure of an object's resistance to changes in its rotational speed.
In the given exercise, when the boy changes his arm positions by pulling the balls closer, he alters the system’s moment of inertia. The moment of inertia is symbolized by \(I\) and has units of \(\text{kg} \cdot \text{m}^2\).

Several key points to remember about moment of inertia:
  • It depends on the mass distribution in relation to the axis of rotation. The further away the mass is, the higher the moment of inertia.
  • In this example, reducing the moment of inertia (from \(6\, \text{kg}\, \text{m}^2\) to \(2\, \text{kg}\, \text{m}^2\)) affects the overall rotational dynamics.
Understanding these principles helps explain why and how the angular speed changes in response to adjustments in the moment of inertia.
Angular Momentum
Angular momentum is the quantity of rotation possessed by a body. It's a conserved property in physics, meaning it remains constant in a closed system without external torques.
This concept combines both moment of inertia and angular speed. Using the formula \(L = I \cdot \omega\), where \(L\) represents angular momentum, illustrates that changes in one factor impact the others, highlighting the interplay between moment of inertia and angular speed.
In our exercise with the revolving chair, the conservation of angular momentum dictates that when the boy pulls the balls closer, reducing the moment of inertia, his angular speed must increase to maintain the same angular momentum. This happens because the system's initial angular momentum (\(L_i\)) equals its final angular momentum (\(L_f\)).

Crucial aspects of angular momentum include:
  • Its dependence on both the distribution of mass (moment of inertia) and the rate of rotation (angular speed).
  • Conservation laws, essential for solving systems involving rotational motion, as seen in the calculation of changes in speed due to adjustments in a rotating body.
Solidifying comprehension of angular momentum enables one to solve complex rotational problems, like determining new speeds after moment of inertia changes.

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Most popular questions from this chapter

A boy is standing on a platform which is free to rotate about its axis. The boy holds an open umbrella in his hand. The axis of the umbrella coincides with that of the platform. The moment of inertia of "the platform plus the boy system" is \(3 \cdot 0 \times 10^{-3} \mathrm{~kg}-\mathrm{m}^{2}\) and that of the umbrella is \(2 \cdot 0 \times 10^{-3} \mathrm{~kg}-\mathrm{m}^{2}\). The boy starts spinning the umbrella about the axis at an angular speed of \(2 \cdot 0\) rev/s with respect to himself. Find the angular velocity imparted to the platform.

A block hangs from a string wrapped on a disc of radius \(20 \mathrm{~cm}\) free to rotate about its axis which is fixed in a horizontal position. If the angular speed of the disc is \(10 \mathrm{rad} / \mathrm{s}\) at some instant, with what speed is the block going down at that instant?

A uniform metre stick of mass \(200 \mathrm{~g}\) is suspended from the ceiling through two vertical strings of equal lengths fixed at the ends. A small object of mass \(20 \mathrm{~g}\) is placed on the stick at a distance of \(70 \mathrm{~cm}\) from the left end. Find the tensions in the two strings.

A disc of radius \(10 \mathrm{~cm}\) is rotating about its axis at an angular speed of \(20 \mathrm{rad} / \mathrm{s}\). Find the linear speed of (a) a point on the rim, (b) the middle point of a radius.

A wheel rotating at a speed of \(600 \mathrm{rpm}\) (revolutions per minute) about its axis is brought to rest by applying a constant torque for 10 seconds. Find the angular deceleration and the angular velocity 5 seconds after the application of the torque.

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