Chapter 1: Problem 7
Taking force, length and time to be the fundamental quantities find the dimensions of (a) density, (b) pressure, (c) momentum and (d) energy.
Short Answer
Expert verified
Density: \( \frac{F}{LT^2} \), Pressure: \( \frac{F}{L^2} \), Momentum: \( \frac{F L}{T} \), Energy: \( FL \).
Step by step solution
01
Understand Dimensional Analysis
In dimensional analysis, we express physical quantities in terms of their fundamental dimensions. Here, the fundamental dimensions are given as force \( [F] \), length \( [L] \), and time \( [T] \). Any other quantity can be expressed in terms of these dimensions.
02
Define the Dimensions of Given Quantities
We know that: - Force \( [F] \) has the dimension \( [F] = [M][L][T]^{-2} \), where \([M]\), \([L]\), and \([T]\) are the dimensions of mass, length, and time respectively. - Length \( [L] = [L] \) and Time \( [T] = [T] \).
03
Dimension of Density
Density is mass per unit volume. The dimension of density \( \rho \) is: \[ \rho = \frac{M}{L^3} \]Using the dimension of force \( F = MLT^{-2} \), we find: \[ M = rac{F L^2}{T^2} \]Thus, \[ [\rho] = \frac{FL^2}{T^2 L^3} = \frac{F}{LT^2} \]
04
Dimension of Pressure
Pressure is force per unit area. The dimension of pressure \( P \) is: \[ P = \frac{F}{A} = \frac{F}{L^2} \]Thus, \[ [P] = \frac{F}{L^2} \]
05
Dimension of Momentum
Momentum is mass times velocity. The dimension of momentum \( p \) is:\[ p = M \cdot v \]Since velocity \( v = \frac{L}{T} \), \[ [p] = M \frac{L}{T} = \frac{F L^2}{T^2} \times \frac{L}{T} = \frac{F L}{T} \]
06
Dimension of Energy
Energy is force times distance, so the dimension of energy \( E \) is: \[ E = F \cdot L \]Thus, \[ [E] = [F][L] = FL \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Density
Density is a crucial concept in physics and refers to the amount of mass contained in a unit volume. Imagine a small box on a shelf – its density tells us how much stuff is packed inside that box, compared to the space it occupies. Mathematically, density (\( \rho \)) is described by the formula \( \rho = \frac{M}{L^3} \), where \( M \) is mass and \( L \) is length. This means density has dimensions of mass per unit volume.
Using dimensional analysis, given the dimensions of force \( [F] = [M][L][T]^{-2} \), we can tweak this to express density in terms of fundamental dimensions like force, length, and time:
Using dimensional analysis, given the dimensions of force \( [F] = [M][L][T]^{-2} \), we can tweak this to express density in terms of fundamental dimensions like force, length, and time:
- Mass \( M = \frac{FL^2}{T^2} \)
- Thus, density would have dimensions \( [\rho] = \frac{FL^2}{T^2 L^3} = \frac{F}{LT^2} \)
Pressure
Pressure is the force exerted per unit area. It's like when you inflate a balloon, you apply force on the balloon’s surface, and this spread-out force is what we call pressure. In physics, we define pressure (\( P \)) as \( P = \frac{F}{A} \), where \( F \) is force and \( A \) is area. This indicates that pressure is the amount of force acting over a specific area.
Dimensional analysis allows us to express pressure in more standard terms. Since area \( A = L^2 \), pressure can be expressed dimensionally as:
Dimensional analysis allows us to express pressure in more standard terms. Since area \( A = L^2 \), pressure can be expressed dimensionally as:
- \( [P] = \frac{F}{L^2} \)
Momentum
Momentum is often considered as the measure of motion. Have you ever tried to stop a moving soccer ball? Momentum is the reason why it doesn’t stop immediately. Defined as the product of mass and velocity, momentum (\( p \)) follows the formula \( p = M \cdot v \). Here, velocity \( v = \frac{L}{T} \) tells us how fast something is moving and in which direction.
Through dimensional analysis and given force dimensions \( F = MLT^{-2} \), momentum is expressed as:
Through dimensional analysis and given force dimensions \( F = MLT^{-2} \), momentum is expressed as:
- \( [p] = M \frac{L}{T} = \frac{F L^2}{T^2} \times \frac{L}{T} = \frac{F L}{T} \)
Energy
Energy is the ability to do work or produce change. Think about how gasoline provides energy to a car, enabling it to travel distances. In terms of physics, energy (\( E \)) is the product of force and distance, expressed as \( E = F \cdot L \). This reveals that energy encapsulates the idea of applying force over a distance.
Dimensional analysis allows us to simplify energy dimensions:
Dimensional analysis allows us to simplify energy dimensions:
- \( [E] = [F][L] = FL \)