Chapter 5: Problem 19
Quantum mechanics 19\. Find the probability that a particle in a box \(L\) wide can be found between \(x=0\) and \(x=L / n\) when it is in the \(n\) th state.
Short Answer
Expert verified
The probability is \(\frac{1}{n}\).
Step by step solution
01
Understand the Particle in a Box Model
In quantum mechanics, the particle in a one-dimensional box of length \(L\) is described by a wave function. For a particle in the \(n\)th energy level or state, the wave function \(\psi_n(x)\) is given by \(\psi_n(x) = \sqrt{\frac{2}{L}} \sin\left(\frac{n\pi x}{L}\right)\). This wave function is valid in the region \(0 \leq x \leq L\) and zero elsewhere.
02
Define the Probability Formula
The probability of finding the particle between positions \(x=a\) and \(x=b\) is calculated using the integral of the square of the wave function \(|\psi_n(x)|^2\) over that interval. Thus, \[ P(0 \leq x \leq \frac{L}{n}) = \int_0^{L/n} |\psi_n(x)|^2 \, dx = \int_0^{L/n} \left(\frac{2}{L}\right) \sin^2\left(\frac{n\pi x}{L}\right) \, dx. \]
03
Use Trigonometric Identity
Since the integrand involves \(\sin^2\) function, it can be simplified using the identity: \[ \sin^2(A) = \frac{1}{2} \left(1 - \cos(2A)\right). \] Therefore, \[ \sin^2\left(\frac{n\pi x}{L}\right) = \frac{1}{2} \left(1 - \cos\left(\frac{2n\pi x}{L}\right)\right). \] Substitute this into the integral.
04
Solve the Integral
The integral becomes: \[ \int_0^{L/n} \left(\frac{2}{L}\right) \frac{1}{2} \left(1 - \cos\left(\frac{2n\pi x}{L}\right)\right) \, dx. \] This simplifies to \[ \frac{1}{L} \int_0^{L/n} \left(1 - \cos\left(\frac{2n\pi x}{L}\right)\right) \, dx. \] Separate this into two integrals: \[ \frac{1}{L}\left( \int_0^{L/n} 1 \, dx - \int_0^{L/n} \cos\left(\frac{2n\pi x}{L}\right) \, dx \right). \] The first integral evaluates to \(\frac{L}{n}\), while the second can be solved by substitution. Integrate to find: \[ \int \cos(kx) \, dx = \frac{1}{k} \sin(kx), \] where \(k = \frac{2n\pi}{L}\).
05
Substitute and Evaluate Boundaries
The second integral becomes \[ \frac{1}{\frac{2n\pi}{L}} \left[ \sin\left(\frac{2n\pi x}{L}\right) \right]_0^{L/n}. \]Evaluate at the boundaries: \[ \left[ \sin\left(\frac{2n\pi x}{L}\right) \right]_0^{L/n} = \sin\left(2\pi\right) - \sin(0) = 0. \] Thus, \[ \frac{1}{\frac{2n\pi}{L}} \times 0 = 0. \] Consequently, the integral that includes cosine evaluates to zero.
06
Calculate the Final Probability
Combine the results from the two integrals:\[ \frac{1}{L} \left( \frac{L}{n} - 0 \right) = \frac{1}{n}. \]The probability that the particle can be found between \(x=0\) and \(x=\frac{L}{n}\) in the \(n\)th state is \(\frac{1}{n}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Particle in a Box
In quantum mechanics, the 'particle in a box' model is an important concept used to describe a system where a particle is constrained to move back and forth within a strictly defined one-dimensional space. Imagine a tiny box with perfectly hard walls that the particle cannot penetrate or pass through. The box has width or length, denoted as \( L \). Within this box, the particle moves freely, but only within the region from \( x=0 \) to \( x=L \). Outside this range, the probability of finding the particle drops to zero because the box effectively traps the particle.
This quantum mechanical system is significant because it provides a simplified model that physicists use to understand the behavior of particles at small scales. In this model, the particle's position is not determined exactly, but rather described by a mathematical function known as a wave function. This wave function reflects the probabilistic nature of quantum mechanics, indicating the likelihood of finding a particle in various positions within the box.
This quantum mechanical system is significant because it provides a simplified model that physicists use to understand the behavior of particles at small scales. In this model, the particle's position is not determined exactly, but rather described by a mathematical function known as a wave function. This wave function reflects the probabilistic nature of quantum mechanics, indicating the likelihood of finding a particle in various positions within the box.
Wave Function
The wave function, denoted by \( \psi_n(x) \), is a crucial concept in quantum mechanics, representing the state of a particle in a system. For a particle confined in a one-dimensional box, the wave function is given by:
The wave function is essential because it allows us to visualize and calculate probabilities related to where the particle might be found within the box. Its squared form, \( |\psi_n(x)|^2 \), provides the probability density—meaning the likelihood of finding the particle at a particular position.
- \( \psi_n(x) = \sqrt{\frac{2}{L}} \sin\left(\frac{n\pi x}{L}\right) \).
The wave function is essential because it allows us to visualize and calculate probabilities related to where the particle might be found within the box. Its squared form, \( |\psi_n(x)|^2 \), provides the probability density—meaning the likelihood of finding the particle at a particular position.
Probability Calculation
In quantum mechanics, understanding the probability of a particle's location is vital. The probability of finding the particle between two points within the box, say, from \( x=0 \) to \( x=\frac{L}{n} \), is calculated using the integral of the squared wave function over that interval. Specifically, it is given by:
This equation explains why the probability decreases as \( n \) increases, reflecting quantum mechanical principles. Lower energy states (smaller \( n \)) result in a greater likelihood of locating the particle close to the box's starting point.
- \( P(0 \leq x \leq \frac{L}{n}) = \int_0^{L/n} |\psi_n(x)|^2 \, dx \).
This equation explains why the probability decreases as \( n \) increases, reflecting quantum mechanical principles. Lower energy states (smaller \( n \)) result in a greater likelihood of locating the particle close to the box's starting point.
Trigonometric Identities
When working with the wave function, simplify the calculations using trigonometric identities. A frequently used identity in quantum mechanics for simplification is:
During the probability calculation, we applied this identity to \( \sin^2\left(\frac{n\pi x}{L}\right) \), which facilitated easier integration. By substituting this identity into the probability integral, the complex trigonometric function reduces, allowing us to compute the probability:
- \( \sin^2(A) = \frac{1}{2} (1 - \cos(2A)) \).
During the probability calculation, we applied this identity to \( \sin^2\left(\frac{n\pi x}{L}\right) \), which facilitated easier integration. By substituting this identity into the probability integral, the complex trigonometric function reduces, allowing us to compute the probability:
- \( \int_0^{L/n} \left(1 - \cos\left(\frac{2n\pi x}{L}\right)\right) \, dx \).