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A 110 kg linebacker running at \(2.0 \mathrm{m} / \mathrm{s}\) and an \(82 \mathrm{kg}\) quarterback running at \(3.0 \mathrm{m} / \mathrm{s}\) have a head- on collision in midair. The linebacker grabs and holds onto the quarterback. Who ends up moving forward after they hit?

Short Answer

Expert verified
After they hit, the quarterback ends up moving forward.

Step by step solution

01

Understanding momentum

Momentum is a vector quantity given by the product of an object's mass and its velocity. The direction of the momentum is the same as the direction of the velocity. In this problem, we can consider the direction in which the linebacker is running as positive. Hence, momentum of the linebacker = \(110kg * 2.0m/s = 220kgm/s\), momentum of the quarterback = \(82kg * -3.0m/s = -246kgm/s\) (negative because he runs opposite to the linebacker)
02

Calculate the total momentum before the collision

Add the two momenta together. Total momentum = \(220kgm/s - 246kgm/s = -26kgm/s\)
03

Determine the direction of motion after the collision

The sign of the total momentum that is negative indicates that the system will move in the direction of the quarterback since we considered his direction to be negative. Thus, the quarterback ends up moving forward after they hit.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum Conservation
Momentum conservation is a fundamental principle in physics, stating that if no external forces are present, the total momentum of a system remains constant before and after a collision. To comprehend this principle, imagine two ice skaters pushing away from each other: the force of the push causes them to move in opposite directions, but the total momentum of the system is unaltered. In the scenario with the linebacker and the quarterback, their combined momentum before and after the collision remains constant, illustrating the concept of momentum conservation. The solution to the problem hinges on calculating the total momentum before the collision and understanding that the same magnitude of momentum must be present after the collision, albeit possibly in a different direction due to the interaction between the two players.

In practice, when no external forces are acting, the momentum before the collision (\(220 \text{kgm/s} - 246 \text{kgm/s} = -26 \text{kgm/s}\)) must be equal to the momentum after. Assuming the linebacker and the quarterback stay together after the collision, their combined mass will move in the direction of the negative momentum indication, hence moving forward in the quarterback's direction.
Vector Quantity in Physics
Understanding that momentum is a vector quantity is crucial in physics. Unlike scalar quantities, which only have magnitude, a vector quantity also includes direction. This dual nature is essential when analyzing phenomena such as collisions, where the direction of the objects' momenta will affect the outcome. In the given exercise, the direction of each player is indicated by the sign of their momentum values. The linebacker has a positive value (\(220 \text{kgm/s}\)), demonstrating his motion in the chosen positive direction, while the quarterback's momentum is negative (\(-246 \text{kgm/s}\)), indicating movement in the opposite direction.

When dealing with vector quantities, like momentum, it is not just the numerical values that matter but also how they align or oppose each other. This is why the negative sign on the quarterback's momentum is not merely a matter of notation; it represents the real physical direction in which he is moving, contrasting with the linebacker's direction.
Head-on Collision Mechanics
Head-on collision mechanics involve analyzing the interaction between two objects moving directly towards each other. As seen in collisions of athletes, such as the one between the linebacker and the quarterback, these are dynamic events where both momentum and energy play roles. It is important to note that while momentum is conserved in collisions, the kinetic energy is only conserved in perfectly elastic collisions, which is not usually the case in real-life scenarios such as the aforementioned football collision.

In our example, the 'head-on' term indicates that the players collide with their paths aligned along a single straight line and have opposite momentum vectors. The resultant motion post-collision will depend on their combined mass and the net momentum. Here, net momentum is negative; the quarterback, having more negative momentum, will decide the direction post-impact. The players' final motion will be in the direction of the quarterback's initial movement, which is an illustration of how head-on collision mechanics operate under the rule of momentum conservation.

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Most popular questions from this chapter

Disk A, with a mass of \(2.0 \mathrm{kg}\) and a radius of \(40 \mathrm{cm}\), rotates clockwise about a frictionless vertical axle at 30 rev/s. Disk B, also \(2.0 \mathrm{kg}\) but with a radius of \(20 \mathrm{cm},\) rotates counterclockwise about that same axle, but at a greater height than disk A, at 30 rev/s. Disk \(B\) slides down the axle until it lands on top of disk A, after which they rotate together. After the collision, what is their common angular speed (in rev/s) and in which direction do they rotate?

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