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In a car's suspension system, each wheel is connected to a vertical spring; these springs absorb shocks when the car travels on bumpy roads. In one car, each spring has a spring constant of \(5.0 \times 10^{4} \mathrm{N} / \mathrm{m} .\) If this \(1400 \mathrm{kg}\) car is driven at \(25 \mathrm{m} / \mathrm{s}\) through the bottom of a circular dip in the road that has a radius of \(600 \mathrm{m},\) by how much do these springs compress compared to when the car is driven on a flat road?

Short Answer

Expert verified
The springs compress by approximately 57 mm when the car is driven through the dip at 25 m/s.

Step by step solution

01

Identify the Forces

First, identify the forces acting on the car: 1. The gravitational force (or weight), \(F_{g}=mg\), where \(m=1400\) kg is the mass of the car and \(g=9.81\) m/s^2 is the acceleration due to gravity. 2. The spring force, \(F_{s}=kx\), where \(k=5.0 \times 10^{4}\) N/m is the spring constant, and \(x\) is the displacement (compression) of the spring. 3. The net centripetal force, \(F_{net}=mRω^{2}\), where \(R=600\) m is the radius, and \(ω=v/r\) is the angular velocity with \(v=25\) m/s being the speed of the car.
02

Write Down the Force Balance

The net force acting upon the car will be the balance between the gravitational force and the combined spring and centripetal forces. When the car is at the bottom of the dip, the forces must balance with gravity, yielding \(mg=kx+mRω^{2}\). Rearranging gives \(x=(mg-mRω^{2})/k\).
03

Solve for x

Substitute the known values into the equation to solve for \(x\). \(x=(1400\times9.81 - 1400\times600\times(25/600)^{2}) / 5.0\times10^{4}\). Computation gives \(x \approx 0.057\) m or 57 mm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Force
Centripetal force is crucial when dealing with objects moving in a circular path, like a car navigating a curve or dip in the road. This force keeps the object moving in a circle, always acting perpendicular to the movement direction—towards the circle's center.
In the case of a car going through a circular dip, the centripetal force must be balanced with other forces acting on the car to maintain its path:
  • Gravity (weight of the car)
  • Normal force from the road, often absorbed by the car's suspension system
The formula for centripetal force is given by \[ F_{c} = \frac{mv^2}{r} \] where:
  • \( m \) is the mass of the car
  • \( v \) is the velocity
  • \( r \) is the radius of the path
For example, when calculating how much extra force is needed as a car heads through the bottom of a circular dip, the spring forces in the car’s suspension must account for this centripetal force. Besides managing bumps on the road, in this scenario, the springs help maintain the path and stability.
Spring Constant
The spring constant is a measure of a spring's stiffness, symbolized by \( k \). It indicates how much force is needed to compress or extend the spring by a unit of distance (usually a meter). The larger the spring constant, the stiffer the spring is, meaning more force is required for compression or elongation.
This is mathematically expressed as: \[ F_{s} = kx \] where:
  • \( F_{s} \) is the spring force in newtons
  • \( k \) is the spring constant in N/m
  • \( x \) is the displacement from equilibrium position in meters
In our car suspension example, each spring in the suspension has a spring constant of \( 5.0 \times 10^{4} \, \mathrm{N/m} \).
The spring constant plays a vital role in how the car handles roads. A higher spring constant means that less compression happens when forces like weight and centripetal force act on the car, crucial for maintaining comfort and control.
Car Suspension System
A car's suspension system is designed to absorb shocks from the road, ensuring a smooth ride and keeping the car stable. This system typically comprises of springs, shock absorbers, and linkages that connect the vehicle to its wheels.
Here’s how it works:
  • **Springs**: These primarily absorb the energy from road bumps. They compress and elongate, dampening any sudden jolts transferred to the car's body.
  • **Shock Absorbers**: These function to dampen the oscillations of the springs, preventing continuous bouncing.
  • **Linkages**: They maintain the connections between wheels and the car body, ensuring that wheels remain in aligned contact with the road.
In scenarios like driving through a dip, these components work together to provide stability. The springs compress more at the bottom of a dip because they counteract both gravitational forces and the centripetal forces acting on the car. This compression aids in keeping the tires in firm contact with the ground, vital for control and safety.
A robust suspension system not only ensures a smooth ride but is also key for effective car handling, traction, and braking efficiency.

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