/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 A roller coaster car is going ov... [FREE SOLUTION] | 91Ó°ÊÓ

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A roller coaster car is going over the top of a 15 -m-radius circular rise. At the top of the hill, the passengers "feel light," with an apparent weight only \(50 \%\) of their true weight. How fast is the coaster moving?

Short Answer

Expert verified
The roller coaster is moving at a speed of approximately \( \sqrt{73.5} \) m/s which is approximately 8.57 m/s.

Step by step solution

01

Recognize that the Situation Involves Uniform Circular Motion

When an object moves in a circular path at a constant speed, it is said to be in uniform circular motion. The net force acting towards the center of the circle results in an acceleration directed inwards, despite the constant speed.
02

Determine the Apparent and True Weights

The apparent weight is the force felt by the person in motion. In this scenario, we know that passengers feel 'light' with an apparent weight only 50% of their true weight. This means the difference between their true weight and the apparent weight they feel is equal to the centripetal force.
03

Examine the Force Diagram

The true weight is directed downwards, while the normal force (apparent weight) and the required centripetal force for circular motion are directed upwards. Hence, we can equate the true weight \(mg\) and the sum of the apparent weight (\(0.5mg\)) and the centripetal force (\(mv^2/r\)) where \(m\) is mass of the person, \(v\) is velocity of the coaster, and \(r\) is radius of the circular path.
04

Solve for Velocity

By simply rearranging the equation, we can obtain a solution for velocity: \[v = \sqrt{rg(1-0.5)} = \sqrt{15m \times 9.8 m/s^2 \times 0.5} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Apparent Weight in Circular Motion
When discussing physics, the concept of 'apparent weight' is crucial, especially in the context of circular motion. Apparent weight refers to the force of gravity that a person or object 'feels' or experiences as a result of other forces acting on them. In scenarios like a roller coaster ride, this feeling is directly connected to the motion of the ride itself.

Take the provided example: a roller coaster at the top of a circular rise. Passengers feel an apparent weight that is only half of their true weight. This sensation arises because the centripetal force required to keep them in circular motion is acting upwards, reducing the overall force they feel pressing them into their seats, which is what we cognitively associate with weight. Mathematically, if the true weight is represented by \( mg \) where \( m \) is mass and \( g \) is acceleration due to gravity, the apparent weight at the pinnacle point of a coaster loop would be \( 0.5mg \). This effect is a perfect example of how external forces can alter our perception of weight, a topic that is as intriguing as it is fundamental to understanding circular motion physics.
Centripetal Force: The Invisible Hand of Circular Motion
In uniform circular motion, centripetal force plays the starring role. It is the 'invisible hand' that constantly pulls an object towards the center of its circular path, allowing it to maintain its trajectory. This force is not an independent force but rather the resultant of other forces that are in action, like gravity, tension, friction, or a combination of these. For our roller coaster, the difference between the true gravitational force acting on the passengers and the reduced force they feel (apparent weight) is what provides this essential centripetal force.

In mathematical terms, centripetal force is given by the equation \( F_c = \frac{mv^2}{r} \) where \( m \) is the mass, \( v \) is the velocity of the object in motion, and \( r \) is the radius of the circular path. The force is directed towards the center and is essential for any object to perform circular motion. Understanding this force is key to solving many problems related to circular motion in physics.
The Dynamics of Circular Motion Physics
Understanding circular motion is a fundamental aspect of physics that explains the motion of objects along a curved path. In the case of our roller coaster, the car and the passengers are in a state of uniform circular motion. This means that, despite the changing direction of the velocity, the speed of the roller coaster is constant. The force that maintains the objects in this motion is the centripetal force, which is always perpendicular to the motion and directed towards the center of the circular path.

The sensation of lightness felt by the passengers at the top of the loop can be explained by the dynamics of circular motion. All objects in motion will naturally continue to move in a straight line unless acted upon by a force; in circular motion, this force is the centripetal force, which constantly changes the direction of the velocity. Without a sufficient centripetal force, the object would fly off tangentially, following Newton's first law of motion. Hence, the exercise in question demonstrates this principle effectively and provides a practical example of circular motion physics in action.

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Most popular questions from this chapter

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