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In the winter sport of bobsledding, athletes push their sled along a horizontal ice surface and then hop on the sled as it starts to careen down the steeply sloped track. In one event, the sled reaches a top speed of \(9.2 \mathrm{m} / \mathrm{s}\) before starting down the initial part of the track, which is sloped downward at an angle of \(6.0^{\circ}\). What is the sled's speed after it has traveled the first \(100 \mathrm{m} ?\)

Short Answer

Expert verified
The sled's speed after it has traveled the first 100 meters is 17 m/s.

Step by step solution

01

Determine the acceleration due to gravity on a slope

The acceleration due to gravity is always acting downwards, towards the center of the Earth. When an object is on a slope, the acceleration due to gravity that it experiences is less than \(9.81 \, m/s^2\), which is the acceleration due to gravity on a flat surface. That is because the object's weight has a component acting downward along the slope, and a component acting perpendicular to the slope. So the acceleration due to gravity on a \(6.0^\circ\) slope is \(9.81 \, m/s^2 \times sin(6.0^\circ) = 1.02 \, m/s^2\)
02

Apply the kinematic equation

The kinematic equation that connects initial speed, final speed, acceleration and distance is given by: \(v_f^2 = v_i^2 + 2ad\). Here, \(v_i = 9.2 \, m/s\) is the initial speed, \(a = 1.02 \, m/s^2\) is the acceleration due to gravity on a slope from Step 1, and \(d = 100 \, m\) is the distance. Substituting these values into the formula gives \(v_f^2 = (9.2 \, m/s)^2 + 2 \times 1.02 \, m/s^2 \times 100 \, m = 84.64 \, m^2/s^2 + 204 \, m^2/s^2\)
03

Solve for the sled's final speed

From step 2, \(v_f^2 = 288.64 \, m^2/s^2\). Taking the square root of both sides to solve for \(v_f\), we have \(\sqrt{288.64 \, m^2/s^2} = v_f = 17 \, m/s\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration on a Slope
When thinking about physics on a slope, it's important to understand how gravity affects an object. Normally, gravity pulls objects towards the Earth at a constant acceleration of \(9.81 \, \mathrm{m/s^2}\). However, when an object is on a slope, it doesn't experience full gravitational pull in the direction of the slope. Instead, the component of gravity that acts down the slope depends on the angle of the slope.
For a sled on a \(6.0^{\circ}\) slope, this effective acceleration can be calculated using the sine of the angle. The formula is \( \text{acceleration} = g \times \sin(\text{angle}) \). Here, \(g\) is the gravitational acceleration. Substituting in the given values, we calculate:
  • \(g = 9.81 \, \mathrm{m/s^2}\)
  • \(\text{angle} = 6.0^{\circ}\)
  • \(\text{acceleration} = 9.81 \, \mathrm{m/s^2} \times \sin(6.0^{\circ}) \approx 1.02 \, \mathrm{m/s^2}\)
This reduced acceleration is because some of gravity's force supports the weight perpendicular to the slope and doesn't affect the motion along the slope.
Kinematic Equations
To predict the motion of objects, such as a bobsled on a track, we use kinematic equations. These equations relate speed, distance, acceleration, and time. In this exercise, we need the equation without time:
  • \(v_f^2 = v_i^2 + 2ad\)
Where:
  • \(v_f\) is the final speed
  • \(v_i\) is the initial speed
  • \(a\) is the acceleration
  • \(d\) is the distance traveled
Applying this to our bobsled example, the sled first has a horizontal speed of \(9.2 \, \mathrm{m/s}\), then experience an acceleration of \(1.02 \, \mathrm{m/s^2}\) while moving down the \(100 \, \mathrm{m}\) slope.
Substituting these values into the kinematic formula helps us find:
  • \(v_f^2 = (9.2 \, \mathrm{m/s})^2 + 2 \times 1.02 \, \mathrm{m/s^2} \times 100 \, \mathrm{m}\)
  • \(v_f^2 = 288.64 \, \mathrm{m^2/s^2}\)
  • \(v_f = \sqrt{288.64} \approx 17 \, \mathrm{m/s}\)
The sled gains speed due to gravity aiding its motion down the slope.
Bobsledding Physics
Bobsledding is not just a thrilling winter sport but also a fascinating study in physics. Understanding bobsledding requires knowledge of how forces work on icy tracks. At the start, athletes push the sled to gain an initial speed. This initial phase requires lots of strength and coordination.
As they transition to the steep track, gravity becomes the main force, enhancing speed. The unique structure of bobsled tracks allows athletes to exploit both gravity and the track's design to achieve maximum speeds. They experience a rapid increase in speed because the downward sloping track converts gravitational potential energy into kinetic energy. This showcases the interplay between kinetic energy, acceleration, and motion.
Furthermore, the sport underscores real-world use of kinematic principles. Understanding these physics concepts not only helps improve performance but ensures the athletes' safety on fast descents. With precise training and equipment, the physics of bobsledding is managed to bring about exhilarating races.

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Most popular questions from this chapter

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