/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Wrays with a wavelength of \(0.0... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Wrays with a wavelength of \(0.085 \mathrm{nm}\) diffract from a crystal in which the spacing between atomic planes is \(0.18 \mathrm{nm} .\) How many diffraction orders are observed?

Short Answer

Expert verified
The maximum number of diffraction orders observed is 4.

Step by step solution

01

Decide on Known and Unknown Variables

Here, the wavelength (λ) is given as 0.085 nm and the crystal-plane spacing (d) as 0.18 nm. We need to compute for the order of diffraction, n. Remember, n must be an integer.
02

Apply Bragg's Law

Rearrange Bragg's equation as n = 2d sin θ / λ. However, the maximum possible value for sin θ is 1. Hence, calculate the maximum possible value for n using the formula: n_max = 2d / λ.
03

Calculate

Substitute the given values into the arranged formula and solve for \(n\) to get\(n_{\mathrm{max}}=\frac{2 \times 0.18}{0.085} \approx 4.24.\) However, as we know that the order of diffraction must be an integer, we can only have four diffraction orders.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength of X-rays
The wavelength of an X-ray is a fundamental characteristic that provides insights into its energy level and its ability to penetrate materials. X-rays are a form of electromagnetic radiation, similar to visible light, but with a significantly shorter wavelength, typically ranging from 0.01 to 10 nanometers (nm). The shorter the wavelength of the X-ray, the higher its energy and the greater its ability to pass through solid substances.

In the context of X-ray diffraction, the wavelength is crucial as it interacts with the atoms in a crystal lattice. When X-rays are directed at a crystal, they can be scattered by the electrons within the atoms. This scattering leads to the creation of a diffraction pattern, which is used to determine the structure of the crystal. In the given exercise, the wavelength of the X-rays is defined as 0.085 nm, a typical value for X-ray diffraction experiments.
Crystal Plane Spacing
Crystal plane spacing, denoted by 'd', is the distance between consecutive atomic planes in a crystal structure. It's a critical parameter in the study of crystallography because it determines how X-rays will diffract when they strike the crystal. Each crystal has a unique arrangement of atoms and thus a distinctive set of spacing values between its planes.

The spacing affects the angle at which beams of X-rays are deflected, and it is essential for the application of Bragg's Law. Bragg's Law relates the wavelength of the X-rays to the crystal plane spacing and the angle of diffraction. It predicts the specific angles where constructive interference, leading to diffraction peaks, will occur. In the problem provided, the crystal plane spacing was given as 0.18 nm, playing a key role in solving for the diffraction orders.
Diffraction Orders
Diffraction orders, often symbolized as 'n', refer to the series of maxima obtained when X-rays are diffracted by a crystal. This concept is rooted in the interference pattern of waves. When X-rays strike a crystal, the waves either reinforce or cancel each other to produce peaks and troughs of intensity, known as constructive and destructive interference, respectively.

The 'order' of diffraction is a whole number (an integer) that signifies the sequence of the peaks as they appear at increasing angles of deflection. The first-order diffraction (n=1) is the first peak observed at the smallest angle, and higher orders (n=2, n=3,...) occur at larger angles. Because these orders represent integer multiples of the wavelength involved in the constructive interference condition defined by Bragg's Law, they are fundamental to identifying the crystal structure. The exercise provided requires identifying how many such orders occur, given the X-ray wavelength and crystal spacing, leading to the application of Bragg's Law and the resulting calculation of four observable diffraction orders.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Exposure to a sufficient quantity of ultraviolet light will redden the skin, producing erythema-a sunburn. The amount of exposure necessary to produce this reddening depends on the wavelength. For a \(1.0 \mathrm{cm}^{2}\) patch of skin, \(3.7 \mathrm{mJ}\) of ultraviolet light at a wavelength of 254 nm will produce reddening; at \(300 \mathrm{nm}\) wavelength, \(13 \mathrm{mJ}\) are required. What is the photon energy corresponding to each of these wavelengths? b. How many total photons does each of these exposures correspond to? c. Explain why there is a difference in the number of photons needed to provoke a response in the two cases.

It is stated in the text that special relativity must be used to calculate the de Broglie wavelength of electrons in an electron microscope. Let us discover how much of an effect relativity has. Consider an electron accelerated through a potential difference of \(1.00 \times 10^{5} \mathrm{V}\) a. Using the Newtonian (nonrelativistic) expressions for kinetic energy and momentum, what is the electron's de Broglie wavelength? b. The de Broglie wavelength is \(\lambda=h / p,\) but the momentum of a relativistic particle is not \(m v .\) Using the relativistic expressions for kinetic energy and momentum, what is the electron's de Broglie wavelength?

Investigators have created structures consisting of linear chains of ionized atoms on a smooth surface. Electrons are restricted to travel along the chain. The energy levels of the electrons match the results of the particle-in-a-box model. For a 5.0-nm-long chain, what are the energies (in eV) of the \(f\) " three states?

? Suppose you need to image the structure of a virus with a diameter of \(50 \mathrm{nm} .\) For a sharp image, the wavelength of the probing wave must be \(5.0 \mathrm{nm}\) or less. We have seen that, for imaging such small objects, this short wavelength is obtained by using an electron beam in an electron microscope. Why don't we simply use short-wavelength electromagnetic waves? There's a problem with this approach: As the wavelength gets shorter, the energy of a photon of light gets greater and could damage or destroy the object being studied. Let's compare the energy of a photon and an electron that can provide the same resolution. a. For light of wavelength \(5.0 \mathrm{nm},\) what is the energy (in eV) of a single photon? In what part of the electromagnetic spectrum is this? b. For an electron with a de Broglie wavelength of \(5.0 \mathrm{nm}\) what is the kinetic energy (in eV)?

Your eyes have three different types of cones with maximum absorption at \(437 \mathrm{nm}, 533 \mathrm{nm},\) and \(564 \mathrm{nm} .\) What photon energies correspond to these wavelengths?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.