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A paramecium is covered with motile hairs called cilia that propel it at a speed of \(1 \mathrm{mm} / \mathrm{s}\). If the paramecium has a volume of \(2 \times 10^{-13} \mathrm{m}^{3}\) and a density equal to that of water, what is its de Broglie wavelength when in motion? What fraction of the paramecium's \(150 \mu \mathrm{m}\) length does this wavelength represent?

Short Answer

Expert verified
The de Broglie wavelength of the paramecium is approximately \(3.32 \times 10^{-5} m\) or \(33.2 \mu m\). This represents approximately \(0.022\) of the length of the paramecium.

Step by step solution

01

Calculate the mass of the paramecium

The density of the paramecium is given as equal to that of water. The density of water is \(1 \mathrm{kg}/\mathrm{m}^3\). Using the definition of density (\(\rho = \frac{m}{v}\)), we can rearrange to find mass (\(m = \rho v\)), and substitute the given values to find the mass of the paramecium, \(m = (1 \mathrm{kg}/\mathrm{m}^3)(2 \times 10^{-13} \mathrm{m}^{3}) = 2 \times 10^{-13} \mathrm{kg}\).
02

Calculate the de Broglie wavelength

With Planck's constant being \(h = 6.63 \times 10^{-34} \mathrm{J} \, \mathrm{s}\), the de Broglie wavelength can be calculated using the formula \(\lambda = \frac{h}{mv}\). Substituting the values, we get \(\lambda = \frac{6.63 \times 10^{-34} \mathrm{J} \, \mathrm{s}}{2 \times 10^{-13} \mathrm{kg} \, 1 \mathrm{mm} / \mathrm{s}}\). Simplifying provides the wavelength.
03

Find the length fraction

To find what fraction of the paramecium's length this wavelength represents, divide the wavelength by the length of the paramecium (150 µm), which should be converted to meters to be consistent with the units of the wavelength.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Paramecium Velocity
The paramecium is a small, single-celled organism that moves by using tiny motile hair-like structures called cilia. These cilia beat in a coordinated manner to propel the paramecium through water. The velocity of a paramecium is given as 1 millimeter per second (mm/s). Understanding this velocity is essential as it is critical when calculating other parameters, such as its de Broglie wavelength. The movement speed, though seemingly trivial, showcases the fascinating mechanisms at micro levels that enable mobility for microscopic organisms. This seemingly simple motion is a hallmark trait and is pivotal in helping the paramecium find food, avoid predators, and navigate its aquatic environment.
Mass Calculation
To calculate the mass of the paramecium, we need to know its volume and density. The volume is provided as \(2 \times 10^{-13} \mathrm{m}^3\), and it is stated that the paramecium's density equals that of water. The density of water is 1 kg/m³. Using the formula for density, \(\rho = \frac{m}{v}\), where \(\rho\) is the density, \(m\) is the mass, and \(v\) is the volume, we rearrange to get the mass formula: \(m = \rho v\). By substituting the known values, we find that the mass of the paramecium is \(2 \times 10^{-13} \mathrm{kg}\). Understanding the mass helps in calculations involving kinetic and potential energies and is crucial in further computations of physical properties.
Density of Water
Water's density is a pivotal reference point in physics due to its common usage in calculations. The density of water is widely accepted as 1 kg/m³ under standard conditions. This fact simplifies many calculations involving aquatic organisms, like the paramecium, whose density is equal to that of water. Utilizing water's density allows us to efficiently solve for mass when volume is known. Knowing the density helps ascertain the scaling of various physical properties with fluid dynamics, buoyancy, and equilibrium. Moreover, it is valuable across scientific fields, leveraging the fact that many biological entities have densities similar to water, allowing seamless transitions between laboratory and real-world applications.
Quantum Physics Concepts
Quantum physics opens up a plethora of concepts that are fascinating yet mind-bending. One of these concepts is the de Broglie wavelength, which proposes that every moving particle has a wavelength, denoted by \(\lambda\). This wavelength is calculated using the equation \(\lambda = \frac{h}{mv}\), where \(h\) is Planck's constant \(6.63 \times 10^{-34} \mathrm{J} \cdot \mathrm{s}\), \(m\) is the mass, and \(v\) is the velocity of the particle. Despite the paramecium being a macroscopic organism, applying the de Broglie wavelength shows the ubiquity of quantum concepts across scales. This exploration of quantum physics offers a glimpse into the dual nature of matter and waves. Moreover, it illustrates that the principles of quantum mechanics can apply, providing a more profound understanding of motion and matter.

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Most popular questions from this chapter

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