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A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is \(1.2 \mathrm{T}\). a. What is the diameter of the largest orbit, just before the protons exit the cyclotron? b. A proton exits the cyclotron \(1.0 \mathrm{ms}\) after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this \(1.0 \mathrm{ms} ?\)

Short Answer

Expert verified
The diameter of the largest orbit is approximately \(1 m\) and the proton completes around 14 million orbits in 1 ms.

Step by step solution

01

Equation for cyclotron radius

The radius of the cyclotron can be calculated by using the cyclotron principle equation, \(r = \frac{mv}{qB}\), where \(m\) is the mass of the proton, \(v\) is the velocity, \(q\) is the charge of the proton and \(B\) is the magnetic field. The velocity can be determined from the kinetic energy of the proton given as 6.5 MeV (Mega electron volts). Use \(E= \frac{1}{2} mv^2\) to isolate \(v = \sqrt{\frac{2E}{m}}\). Converting 6.5 MeV to joules, \(E = 6.5\ MeV * 1.6*10^{-13} J/MeV = 1.04*10^{-12} J\), and the mass of a proton is \(1.67*10^{-27} kg\). After substituting for \(v\) in the cyclotron’s radius equation above we have \(r = \frac{\sqrt{\frac{2E}{m}}}{qB}\).
02

Determining the radius

First calculate the velocity then substitute into the equation for \(r\). The value for the charge of a proton, \(q\), is \(1.6*10^{-19} C\) and the magnetic field, \(B = 1.2\ T\), must be substituted into the equation to solve for \(r\). The result for \(r\) will give the radius of the largest orbit in the cyclotron. The diameter is then calculated by \(D = 2*r\).
03

Determining the period

The time period, which is the time taken for one complete orbit, is given by the equation \(T = \frac{2Ï€r}{v}\). Get the values for \(r\) and \(v\) from step 1 and 2, from this the frequency can be calculated as the inverse of the time period, \( f = 1/T\).
04

Determining the number of complete orbits

For the proton to complete full orbits, we'll use the total time given as 1 ms or \(1*10^{-3} s\). The number of complete orbits is the total time divided by the time for each orbit, \(n = \frac{Total\ Time}{T}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proton acceleration
In a cyclotron, protons are accelerated to reach high energies. This acceleration is crucial for many applications, including the production of medical isotopes. Protons start at the center of the cyclotron and spiral outward as they gain speed. Their acceleration stems from an alternating electric field within the device.
When protons pass through the gap between the two "D"-shaped electrodes, the electric field gives them a push, increasing their kinetic energy. - **Electric Field:** The alternating nature of the field ensures protons continuously gain energy during each circuit. - **Original kinetic energy:** In the provided exercise, protons are accelerated to a kinetic energy of 6.5 MeV, a significant amount for medical applications. The process allows protons to reach velocities necessary to produce medically useful isotopes when they collide with target nuclei outside the cyclotron.
Magnetic field
A magnetic field is a critical element in a cyclotron's operation. It provides the force needed to keep the protons moving in circular paths. In our example, the magnetic field strength is given as 1.2 Tesla. - **Lorentz Force:** Protons in motion within a magnetic field experience a force perpendicular to both their velocity and the magnetic field direction. This force is responsible for the circular trajectory. - **Magnetic Field Strength:** The strength of the field, denoted by "B," affects the curvature of the protons' path. A stronger magnetic field leads to tighter spirals. Hence, the given 1.2 T field works effectively to keep protons within the cyclotron before they reach their maximum energy. The magnetic field is essential, allowing protons to make many laps and accumulate energy efficiently before being extracted.
Cyclotron radius
The radius of the cyclotron orbit increases as protons gain energy. The relationship between the radius, the protons' mass and charge, and the magnetic field is given by the formula:\[ r = \frac{mv}{qB}\]Here, "r" is the radius, "m" is the proton mass, "v" is velocity, "q" is the charge of the proton, and "B" is the magnetic field.- **Velocity and Mass Influence:** As protons accelerate and their velocity "v" increases, the radius "r" becomes larger. The constant mass of the proton remains at approximately \(1.67 \times 10^{-27} \text{kg}\).- **Exercise Example:** Upon reaching 6.5 MeV, a proton's orbit can expand maximally to a diameter based on the values substituted into this equation.Solving this radius equation allows us to understand how wide the proton's path can stretch before extracting it for further use.
Kinetic energy conversion
In the cyclotron, energy is continuously converted from electrical to kinetic form. As protons move through the device, the alternating electric field lifts their kinetic energy step by step.- **Energy Calculation:** We convert the 6.5 MeV into joules to use in kinetic energy equations, as MeV is a common unit in particle physics. The conversion goes as follows: \(E = 6.5 \text{ MeV} \times 1.6 \times 10^{-13} \text{ J/MeV} = 1.04 \times 10^{-12} \text{ J}\).- **Velocity Derivation:** With energy values known, the velocity "v" is derived from the kinetic energy equation \(E = \frac{1}{2} mv^2\), leading us to recalibrate the particle's path.This precise conversion allows scientists and engineers to calculate crucial parameters of the cyclotron function, adapting the energy exchange at various operational phases.

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Most popular questions from this chapter

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