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A \(60-\mathrm{cm}-\) long heating wire is connected to a \(120 \mathrm{V}\) outlet. If the wire dissipates \(45 \mathrm{W},\) what are (a) the current in and (b) the resistance of the wire?

Short Answer

Expert verified
The current \(I = 0.375 A\) and resistance \(R = 320 \Omega\).

Step by step solution

01

Find the Current

Using the power formula \(P = IV\), we can find the current \(I\) by rearranging as \(I = \frac{P}{V}\). Substituting the given values into the formula, we have: \(I = \frac{45 W}{120 V}\)
02

Calculate the Current

Divide 45 by 120 to find the value of the current. The solution is \(I = 0.375 A\) which is the current flowing in the wire.
03

Find Resistance

Using Ohm’s law formula \(V = IR\), we can find the resistance \(R\) by rearranging as \(R = \frac{V}{I}\). Substituting the calculated current and the given voltage into this formula, we get \(R = \frac{120 V}{0.375 A}\)
04

Calculate Resistance

Divide 120 by 0.375 to find the value of the resistance. The solution is \(R = 320 \Omega\), which is the resistance of the wire.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law
Ohm’s Law is a fundamental principle in electrical circuits, connecting three pivotal variables: voltage (V), current (I), and resistance (R). It's expressed in the formula: \[ V = IR \] where - **V** represents voltage, the electrical potential difference between two points, measured in volts (V). - **I** stands for current, the rate of charge flow through a conductor, measured in amperes (A). - **R** indicates resistance, which refers to how much a material opposes the flow of charge, measured in ohms (Ω).In the context of our exercise, we use Ohm’s Law to solve for the resistance of a wire. After finding the current using the power formula, we rearrange Ohm's Law to: \[ R = \frac{V}{I} \] This transformation allows us to calculate resistance by dividing the given voltage by the current we determined, providing deeper insights into how these core electrical components interact in a system.
Power Formula
The power formula is another essential tool in understanding electrical circuits. Power (P) in a circuit relates to voltage (V) and current (I) through the equation: \[ P = IV \] This equation defines power as the rate at which energy is consumed or transferred within a circuit. In this scenario, power represents how quickly the heating wire converts electrical energy from the outlet into heat, measured in watts (W).When looking to determine the current flowing through the wire, we can manipulate the formula to \[ I = \frac{P}{V} \] This allows us to find out how much charge per second flows through the wire, simply by using the provided power and voltage values. The ability to rearrange the formula showcases the versatility and practical application of the power formula in real-world problems.
Resistance
Resistance is a measure of how much a material prevents the flow of electric current. It depends on the material’s nature, its dimensions, and temperature. It is quantitatively expressed in ohms (Ω). In our exercise, after identifying the voltage and current values, we calculated resistance using the rearranged Ohm’s Law equation: \[ R = \frac{V}{I} \]In this example, substituting the voltage of 120V and the current of 0.375A, we computed a resistance of 320Ω, illustrating that resistance not only helps control the current but also determines how efficiently energy is utilized in electronic devices.Understanding resistance is crucial as it affects how devices function and ensures they are safe and efficient. To design effective circuits, this concept aids in selecting appropriate materials and optimizing them for specific applications.

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Most popular questions from this chapter

A laptop battery has an emf of \(10.8 \mathrm{V}\). The laptop uses \(0.70 \mathrm{A}\) while running. a. How much charge moves through the battery each second? b. By how much does the electric potential energy of this charge increase as it moves through the battery?

As discussed in the chapter, a thermistor is a device whose resistance varies with temperature. At \(20^{\circ} \mathrm{C}\) a thermistor's resistance is \(10.0 \mathrm{k} \Omega .\) When connected to a \(1.2 \mathrm{V}\) battery, the current through the thermistor increases by \(30 \mu \mathrm{A}\) as the temperature increases to \(30^{\circ} \mathrm{C} .\) What is the thermistor's resistance at this higher temperature?

The current in an electric hair dryer is 10 A. How much charge and how many electrons flow through the hair dryer in 5.0 min?

The \(120 \mathrm{V}\) electric heater in a coffee maker has a resistance of \(15 \Omega .\) How long will it take for this heater to raise 5 cups \((1100 \mathrm{g})\) of water from \(20^{\circ} \mathrm{C}\) to the ideal brewing temperature of \(90^{\circ} \mathrm{C} ?\)

For a science experiment you need to electroplate a 100-nm-thick zinc coating onto both sides of a very thin, \(2.0 \mathrm{cm} \times 2.0 \mathrm{cm}\) copper sheet. You know that the charge carriers in the ionic solution are divalent (charge \(2 e\) ) zinc ions. The density of zinc is \(7140 \mathrm{kg} / \mathrm{m}^{3} .\) If the electroplating apparatus operates at \(1.0 \mathrm{mA}\), how long will it take the zinc to reach the desired thickness?

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