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A flying hummingbird picks up charge as it moves through the air. This creates a potential near the bird. What is the "voltage of a hummingbird"? Assume that the bird acquires a charge of \(+200 \mathrm{pC}\), a typical value, and model the bird as a sphere of radius \(3 \mathrm{cm}\).

Short Answer

Expert verified
The potential difference or voltage of the hummingbird is approximately \(60 \, MV\).

Step by step solution

01

Identify and Arrange the Given Information

From the problem, we have Charge \(Q=+200 \mathrm{pC}\) (we will need to convert this into coulombs, the SI unit for charge) and Radius \(r=3 \mathrm{cm}\) (again, we'll need to convert this into meters, the SI unit for distance). The formula for potential difference or Voltage, \(V\), due to a point charge is given by \(V=\frac{kQ}{r}\), where \(k\) is the Coulomb's constant, which is approximately \(8.99 \times 10^9 \, N.m^2/C^2\).
02

Convert Units of Given Measurements

Before we can substitute our numbers into the formula, we need to convert them into the correct units.\n\Charge in coulombs: \(200 \, pC = 200 \times 10^{-12} \, C = 2 \times 10^{-10} C\)\n\Radius in meters: \(3 \, cm = 3 \times 10^{-2} m = 0.03 m\)
03

Substitute the Values into the Formula

We can now substitute \(k=8.99 \times 10^9 \, N.m^2/C^2\), \(Q=2 \times 10^{-10} \, C\), and \(r=0.03 \, m\) into the formula to calculate the potential difference.
04

Simplify and Solve for the Voltage

Performing the substitution gives \(V=\frac{8.99 \times 10^9 \times 2 \times 10^{-10}}{0.03} \). Simplifying this calculation gives \(V= 5.9933 \times 10^7 \, V\). Since voltages are typically reported in a smaller unit, we can say that the voltage is approximately \(60 \, MV\) (Mega Volts)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Electric forces in nature arise due to charges interacting with each other. The fundamental principle that describes this behavior is Coulomb's Law. According to this law, the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. The formula representing this is:
  • F = \( \frac{k \cdot q_1 \cdot q_2}{r^2} \)
where F is the force, \( q_1 \) and \( q_2 \) are the charges, \( r \) is the distance separating the charges, and \( k \) is the Coulomb’s constant (\(8.99 \times 10^9 \, N \cdot m^2/C^2\)).This law is similar to Newton’s Law of Gravitation but applies to electrical charges. It is essential in understanding how electric fields influence particles and, consequently, the concept of electric potential.
SI Units
To understand and perform calculations in physics, it's essential to know the International System of Units (SI Units). These units standardize measurements worldwide.
  • Electric Charge: Measured in coulombs (C). For instance, picoCoulombs (pC) used in the problem are a trillionth of a coulomb: 1 pC = \(10^{-12} C\).
  • Distance: Measured in meters (m). Converting centimeters to meters involves multiplying by \(10^{-2}\).
Using consistent units reduces errors in calculations. Always convert to SI units before starting calculations, especially when working with forces or electric fields. This practice ensures accurate results without mismatches in units.
Voltage Calculation
Voltage is the potential difference between two points. It's the work needed to move a charge between these two points through an electric field. The voltage due to a point charge is given by the formula:
  • V = \( \frac{k \cdot Q}{r} \)
where \( V \) is the voltage, \( k \) is Coulomb’s constant, \( Q \) is the electric charge, and \( r \) is the distance (or radius in the context of a sphere) from the charge.In the given problem, substituting the known values leads to a final calculation of approximately \(60 \, MV\). This means the electric potential around this hummingbird is extremely high due to its charging effect. Understanding voltage helps in grasping how systematic energy transfer happens in electrical systems.
Electric Charge
An electric charge is a fundamental property of matter that causes it to experience a force when placed in an electromagnetic field. There are two types of charges: positive and negative.
  • Like charges repel, while unlike charges attract.
  • Electric field lines emerge from positive charges and terminate on negative charges.
The hummingbird, in this problem, carries a charge: \(+200\, \text{pC}\). Electrically charged objects create fields that exert force on other charges, contributing to the concept of electric potential and potential differences that measure voltage levels, such as in this scenario.
Sphere Model
In physics, approximating objects as simple geometrical shapes like spheres eases complex calculations. The Sphere Model suggests treating an object as if its charge is concentrated at a single point in its center. This simplification applies specifically well in electrostatics where the distributions of charge are uniform across the surface.For instance, in the exercise, modeling the hummingbird as a sphere allows use of the formula:
  • V = \( \frac{k \cdot Q}{r} \)
where r is the radius of the sphere. This model serves to simplify real-world problems into solvable physics problems and allows the calculation of electric potential, which measures how energy disperses around a charged object. Using a sphere ensures the distance measurement remains constant in every direction, making the mathematics more accessible.

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Most popular questions from this chapter

The dielectric in a capacitor serves two purposes. It increases the capacitance, compared to an otherwise identical capacitor with an air gap, and it increases the maximum potential difference the capacitor can support. If the electric field in a material is sufficiently strong, the material will suddenly become able to conduct, creating a spark. The critical field strength, at which breakdown occurs, is \(3.0 \mathrm{MV} / \mathrm{m}\) for air, but \(60 \mathrm{MV} / \mathrm{m}\) for Teflon. a. A parallel-plate capacitor consists of two square plates, \(15 \mathrm{cm}\) on a side, spaced \(0.50 \mathrm{mm}\) apart with only air between them. What is the maximum energy that can be stored by the capacitor? b. What is the maximum energy that can be stored if the plates are separated by a 0.50-mm-thick Teflon sheet?

An electron with an initial speed of \(500,000 \mathrm{m} / \mathrm{s}\) is brought to rest by an electric field. a. Did the electron move into a region of higher potential or lower potential? b. What was the potential difference that stopped the electron? c. What was the initial kinetic energy of the electron, in electron volts?

At one point in space, the electric potential energy of a \(15 \mathrm{nC}\) charge is \(45 \mu \mathrm{J}\) a. What is the electric potential at this point? b. If a \(25 \mathrm{nC}\) charge were placed at this point, what would its electric potential energy be?

Guiana dolphins are one of the few mammals able to detect electric fields. In a test of sensitivity, a dolphin was exposed to the variable electric field from a pair of charged electrodes. The magnitude of the electric field near the sensory organs was measured by detecting the potential difference between two measurement electrodes located \(1.0 \mathrm{cm}\) apart along the field lines. The dolphin could reliably detect a field that produced a potential difference of \(0.50 \mathrm{mV}\) between these two electrodes. What is the corresponding electric field strength?

A Na' ion moves from inside a cell, where the electric potential is \(-70 \mathrm{mV},\) to outside the cell, where the potential is \(0 \mathrm{V}\). What is the change in the ion's electric potential energy as it moves from inside to outside the cell? Does its energy increase or decrease?

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