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Two identical metal spheres A and B are connected by a plastic rod. Both are initially neutral. \(1.0 \times 10^{12}\) electrons are added to sphere \(A,\) then the connecting rod is removed. Afterward, what are the charge of \(\mathrm{A}\) and the charge of \(\mathrm{B} ?\)

Short Answer

Expert verified
The charge of sphere A is \(-1.6 \times 10^{-7} C\) and the charge of sphere B is \(0 C\).

Step by step solution

01

Calculate the charge on sphere A

In this step, calculate the total charge of sphere A. Since each electron carries a charge of \(-1.6 \times 10^{-19} C\), the total charge added to sphere A equals the number of electrons multiplied by the charge of each electron. Namely, \(-1.6 \times 10^{-19} C / electron \times 1.0 \times 10^{12} electrons = -1.6 \times 10^{-7} C\).
02

Determine the charge on sphere B

Sphere B was not subjected to any changes; no electrons were added or removed, thus it remained neutral. The net charge of a neutral object is 0; hence the charge on sphere B is \(0 C\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is fundamental to understanding the behavior of electric charges at rest. It describes the force between two point charges as directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The equation can be expressed as

\[ F = k \frac{|q_1 \cdot q_2|}{r^2} \]
where \(F\) is the force between the charges, \(k\) is the Coulomb's constant (9.898 \times 10^9 \frac{Nm^2}{C^2}), \(q_1\) and \(q_2\) are the amount of the charges, and \(r\) is the distance between the centers of the two charges.
This principle helps explain the interaction in our example where the two metal spheres A and B influence each other through their charges, with sphere A acquiring negative charges while sphere B remains neutral. The force they exert on each other would depend on the amount of charge transferred and the distance between them, prior to the removal of the connecting plastic rod.
Electron Charge
The electron charge, often denoted as \(e\), is a fundamental property of an electron, and it carries a constant charge of approximately \(-1.6 \times 10^{-19} \) Coulombs. This value is the basic unit of electric charge in the SI system of units, and it's essential for calculating the total charge when a certain amount of electrons are transferred or removed from an object, as illustrated in our problem.

Since the atom's neutrality is disrupted by adding or removing electrons, it acquires either a positive or negative charge. In our example, sphere A's total charge, after adding \(1.0 \times 10^{12}\) electrons, results in the total negative charge of \(-1.6 \times 10^{-7} C\), derived from the formula of charge \(Q = n \cdot e\), where \(n\) is the number of electrons. It's crucial to recognize each electron has an identical charge, which is why we can use this equation to compute the charge on sphere A.
Conductors and Insulators
In the exercise, knowing the difference between conductors and insulators helps us to understand the outcome. Conductors are materials that allow electrons to flow freely, thanks to the mobility of their valence electrons. Examples include metals like copper and aluminum. Insulators, on the other hand, do not easily allow the movement of electrons within them because their electrons are tightly bound to their atoms. Plastic, glass, and rubber are common insulators.

In the context of the scenario provided, when electrons are added to sphere A, it becomes negatively charged, while sphere B remains neutral as no electrons were added or removed. The connecting rod, made of insulating material (plastic), prevents any charge transfer between the spheres. So when the rod is removed, the charge on sphere A does not change, while sphere B remains neutral. This distinction is fundamental when analyzing static electricity problems and how charges distribute themselves among objects.

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Most popular questions from this chapter

II A parallel-plate capacitor is formed from two \(4.0 \mathrm{cm} \times 4.0 \mathrm{cm}\) electrodes spaced \(2.0 \mathrm{mm}\) apart. The electric field strength inside the capacitor is \(1.0 \times 10^{6} \mathrm{N} / \mathrm{C} .\) What is the charge (in \(\mathrm{nC}\) ) on each electrode?

A small metal sphere has a mass of 0.15 g and a charge of \(-23.0 \mathrm{nC} .\) It is \(10.0 \mathrm{cm}\) directly above an identical sphere that \(\mathrm{t}\) has the same charge. This lower sphere is fixed and cannot move. If the upper sphere is released, it will begin to fall. What is the magnitude of its initial acceleration?

The electron gun in a television tube uses a uniform electric field to accelerate electrons from rest to \(5.0 \times 10^{7} \mathrm{m} / \mathrm{s}\) in a distance of \(1.2 \mathrm{cm} .\) What is the electric field strength?

A protein molecule in an electrophoresis gel has a negative charge. The exact charge depends on the \(\mathrm{pH}\) of the solution, but 30 excess electrons is typical. What is the magnitude of the electric force on a protein with this charge in a \(1500 \mathrm{N} / \mathrm{C}\) electric field?

Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular aluminum plates, each \(20 \mathrm{cm}\) in diameter, separated by \(1.0 \mathrm{cm}\). How much charge can be added to each of the plates before a spark jumps between the two plates? For such flat electrodes, the field that causes a spark is at the high end of the range presented in the chapter; assume a value of \(3 \times 10^{6} \mathrm{N} / \mathrm{C}\).

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