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I Two protons are \(2.0 \mathrm{fm}\) apart. \((1 \mathrm{fm}=1\) femtometer \(=\) \(\left.1 \times 10^{-15} \mathrm{m} .\right)\) a. What is the magnitude of the electric force on one proton due to the other proton? b. What is the magnitude of the gravitational force on one proton due to the other proton? c. What is the ratio of the electric force to the gravitational force?

Short Answer

Expert verified
a. The magnitude of the electric force on one proton due to the other proton is approximately \(9.21 * 10^{-26}\) N. b. The magnitude of the gravitational force on one proton due to the other proton is approximately \(1.07 * 10^{-36}\) N. c. The ratio of the electric force to the gravitational force is approximately \(8.59 * 10^{10}\).

Step by step solution

01

Calculate the Electric Force

Utilize Coulomb's Law to calculate the electric force. The formula is \(F_e = k_e * |q1*q2| / r^2\), where \(k_e = 8.99*10^9 N*m^2/C^2\) is Coulomb's constant, \(q1\) and \(q2\) are the charges of the protons and \(r = 2*10^-15 m\) is the distance between the protons.
02

Calculate the Gravitational Force

Use the gravitational force formula \(\(F_g = G * m1*m2 / r^2\)\), where \(G = 6.674*10^-11 N*(m^2/kg^2)\) is the gravitational constant, \(m1\) and \(m2\) are the masses of the protons, and \(r\) is again the distance between the protons.
03

Calculate the Ratio

To find the ratio of the electric force to the gravitational force, use the formula \(Ratio = F_e / F_g\).
04

Perform the Calculations

Having subtituted the values into the formula and completed the calculations, get the answers for a, b and c.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric force calculation
Understanding the electric force calculation involves applying Coulomb's Law, a fundamental principle in physics that quantifies the amount of force between two charged objects. In essence, like charges repel each other, while opposite charges attract, with the force magnitude directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The formula to express this relationship is \( F_e = \frac{k_e \cdot |q1 \cdot q2|}{r^2} \), where \( F_e \) represents the electric force, \( k_e \), known as Coulomb's constant, is \( 8.99 \times 10^9 \text{ Nm}^2/\text{C}^2 \), \( q1 \) and \( q2 \) are the electrical charges of the objects (in this case, protons), and \( r \) is the distance separating them. Protons have a charge of \( +1e \) each, where \( e \) is the elementary charge and equals \( 1.6 \times 10^{-19} \text{C} \). By substituting these known values into the formula, one can calculate the electric force exerted between two protons.
Gravitational force calculation
The concept of gravitational force calculation can be illustrated by Newton's universal law of gravitation. This law states that any two objects with mass will attract each other with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between their centers of mass. This is similar to the concept of electric forces but involves mass instead of charge.

The mathematical formula for gravitational force is \( F_g = \frac{G \cdot m1 \cdot m2}{r^2} \), where \( F_g \) is the gravitational force, \( G \) is the gravitational constant which is \( 6.674 \times 10^{-11} \text{ N} \left(\text{m}^2/\text{kg}^2\right) \) , \( m1 \) and \( m2 \) are the masses of the two objects, and \( r \) remains the distance between the centers of mass of the two objects. By replacing these values with those corresponding to the masses of the protons and the distance between them, you arrive at the gravitational force between them, which is significantly weaker than the electric force.
Forces in Physics
Forces in physics are the agents of change; they can cause objects to accelerate, decelerate, remain in place, or change their state of motion in any way. There are a variety of forces that act in the universe, with gravity and electromagnetism being two of the fundamental interactions. In the context of our problem involving protons, these two forces demonstrate two key principles of physics: electromagnetism through Coulomb's Law and gravity through Newton's Law of Gravitation.

Electric forces result from properties of particles called charges, while gravitational forces are a consequence of their mass. Their respective formulas show how these forces diminish with increasing distance, known as an inverse-square law relationship. Although these forces are omnipresent, their relative strengths can differ dramatically, with electric forces being significantly stronger than gravitational forces at the subatomic scale. This relative strength is critical when analyzing the effects of these forces on matter across different scales and scenarios.

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Most popular questions from this chapter

A housefly walking across a clean surface can accumulate a significant positive or negative charge. In one experiment, the largest positive charge observed was +73 pC. A typical housefly has a mass of 12 mg. What magnitude and direction electric field would be necessary to "levitate" a housefly that has the maximum charge? Could such a field exist in air?

Two equally charged, 1.00 g spheres are placed with \(2.00 \mathrm{cm}\) between their centers. When released, each begins to accelerate at \(225 \mathrm{m} / \mathrm{s}^{2} .\) What is the magnitude of the charge on each sphere?

Two \(2.0-\mathrm{cm}-\) diameter disks face each other, \(1.0 \mathrm{mm}\) apart. They are charged to \(\pm 10 \mathrm{nC}\). a. What is the electric field strength between the disks? b. A proton is shot from the negative disk toward the positive disk. What launch speed must the proton have to just barely reach the positive disk?

A glass rod that has been charged to \(+12.0 \mathrm{nC}\) touches a metal sphere. Afterward, the rod's charge is \(+8.0 \mathrm{nC}\). a. What kind of charged particle was transferred between the rod and the sphere, and in which direction? That is, did it move from the rod to the sphere or from the sphere to the rod? b. How many charged particles were transferred?

A parallel-plate capacitor is constructed of two horizontal 12.0-cm-diameter circular plates. A 1.0 g plastic bead, with a charge of \(-6.0 \mathrm{nC},\) is suspended between the two plates by the force of the electric field between them. Which plate, the upper or the lower, is positively charged? b. What is the charge on the positive plate?

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