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A student at the top of a building of height \(h\) throws ball \(A\) straight upward with speed \(v_{0}\) and throws ball B straight downward with the same initial speed. a. Compare the balls" accelerations, both direction and magnitude, immediately after they leave her hand. Is one acceleration larger than the other? Or are the magnitudes equal? b. Compare the final speeds of the balls as they reach the ground. Is one larger than the other? Or are they equal?

Short Answer

Expert verified
a) Both balls A and B have the same acceleration magnitude \(g\) downwards right after they leave the hand. b) The final speeds of balls A and B as they reach the ground are the equal.

Step by step solution

01

Analyzing the Acceleration

Immediately after the balls leave the hand, they are both accelerating downwards due to gravity. The magnitudes of these accelerations are equal and typically denoted by \(g\) (approximately \(9.81 m/s^2\) downwards on Earth). There is no air resistance or any other force considered here, only gravity. Therefore, both balls A and B have the same acceleration \(g\) in the downward direction.
02

Computation of Final Speed for Ball A

Ball A is thrown upwards firstly, opposes the gravity and reaches the maximum height. After that it begins fall back due to gravity. The final speed \(v_f\) of ball A can be calculated with the equation \(v_f^2 = v_0^2 + 2g h\), where \(-v_0\) is the initial speed (negative because it's opposite the direction of gravity). Thus, the final speed of ball A as it reaches the ground is \(\sqrt{v_0^2 + 2gh}\).
03

Computation of Final Speed for Ball B

Ball B is thrown downward with an initial speed of \(+v_0\). Again, the same equation is used to compute the final speed except that now the speed is in the direction of gravity. The final speed of ball B as it reaches the ground is \(\sqrt{v_0^2 + 2gh}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Due to Gravity
Gravity is a powerful and constant force that pulls all objects towards the Earth’s center. In the context of the exercise, it's important to notice that any object in free fall is affected by this force. This acceleration is symbolized by the letter 'g'. On Earth, its value is approximately \(9.81 m/s^2\). This means any object falling freely will increase its speed by 9.81 meters per second every second.
  • Gravity acts on all objects equally.
  • (g) is always directed downwards.
In the exercise, both balls A and B are subject to the same acceleration due to gravity once they leave the thrower's hand. Even when ball A is thrown upwards initially, it still experiences the same downward acceleration. This constant acceleration is crucial when analyzing the motion of projectiles.
Initial Speed
The initial speed ( \(v_0\) ) is the speed at which an object, like either ball A or B in the exercise, begins its journey. It's the speed imparted by the student's throw at the exact moment the ball leaves her hand. For ball A, this speed is directed upwards against the pull of gravity, while for ball B, the initial speed is directed downwards with gravity.
  • Initial speed is the starting velocity of the object.
  • Determines how high or how fast the object will initially move.
Understanding initial speed helps inform the behavior of projectiles early in their motion, setting the stage for how they'll interact with gravity and other forces. For both balls, the initial speed provided affects how quickly they reach the ground but does not change the nature of the gravitational acceleration they each experience.
Final Speed
Final speed ( \(v_f\) ) refers to the velocity of an object just before it impacts something—like the ground in this case. As both balls fall back under the relentless pull of gravity, their speeds increase regardless of their initial throw direction.
  • It's the speed of an object at the end of its fall.
  • Calculated using initial speed and acceleration over the distance fallen.
For both balls A and B, the final speed when they hit the ground can be determined by the kinematic equation: \(v_f = \sqrt{v_0^2 + 2gh}\). This formula shows that after considering gravity and initial speed, both balls reach the same final speed before touching the ground.
Kinematic Equations
Kinematic equations are essential tools for analyzing and solving problems involving motion, especially those related to projectile motion. These equations help determine various attributes of a moving object, such as displacement, velocity, and acceleration.
  • Enable calculation of final speed and position overtime.
  • Account for initial speed, acceleration, and time or distance.
For this exercise, the equation \(v_f^2 = v_0^2 + 2g h\) is used. This equation derives the final speed of both balls A and B, indicating that once the effects of gravity and initial speed have played out, they possess identical final speeds regardless of their initial motion direction. Kinematic equations are vital in determining how objects travel over time influenced by constant forces like gravity.

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Most popular questions from this chapter

Here's an interesting challenge you can give to a friend. Hold a $1 (or larger) bill by an upper corner. Have a friend prepare to pinch a lower corner, putting her fingers near but not touching the bill. Tell her to try to catch the bill when you drop it by simply closing her fingers. This seems like it should be easy, but it's not. After she sees that you have released the bill, it will take her about 0.25 s to react and close her fingers-which is not fast enough to catch the bill. How much time does it take for the bill to fall beyond her grasp? The length of a bill is 16 cm.

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A Porsche challenges a Honda to a \(400 \mathrm{m}\) race. Because the Porsche's acceleration of \(3.5 \mathrm{m} / \mathrm{s}^{2}\) is larger than the Honda's \(3.0 \mathrm{m} / \mathrm{s}^{2},\) the Honda gets a \(100-\mathrm{m}\) head start-it is only \(300 \mathrm{m}\) from the finish line. Assume, somewhat unrealistically, that both cars can maintain these accelerations the entire distance. Who wins, and by how much time?

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