/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 A cross-country skier is skiing ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A cross-country skier is skiing along at a zippy \(8.0 \mathrm{m} / \mathrm{s}\). She stops pushing and simply glides along, slowing to a reduced speed of \(6.0 \mathrm{m} / \mathrm{s}\) after gliding for \(5.0 \mathrm{m}\). What is the magnitude of her acceleration as she slows?

Short Answer

Expert verified
The skier's acceleration, as she slows down, is \(-0.8 m/s²\). The negative sign indicates deceleration.

Step by step solution

01

Identifying Given Values

From the exercise, the given values are: \nInitial velocity (\(v_i\)) = 8.0 m/s \nFinal velocity (\(v_f\)) = 6.0 m/s \nDistance (\(d\)) = 5.0 m
02

Use the Kinematic Equation

We use the kinematic equation \(v_f^2 = v_i^2 + 2ad\) where a is acceleration and d is the distance. The goal is to isolate a, the acceleration, so we need to rearrange this equation to: \(a = \frac{v_f^2 - v_i^2}{2d}\)
03

Substitution and Calculation

We substitute our given values into the Equation to solve for a: \(a = \frac{(6.0 m/s)^2 - (8.0 m/s)^2}{2 * (5.0 m)} = -0.8 m/s²\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematic Equations
Kinematic equations play a crucial role in describing the motion of objects under the influence of uniform acceleration. These equations relate various parameters of motion, such as initial velocity, final velocity, acceleration, time, and displacement. In physics problem solving, these kinematic equations are used to predict the final state of motion given some initial conditions.

One of the primary kinematic equations has the form \(v_f^2 = v_i^2 + 2ad\), where \(v_f\) is the final velocity, \(v_i\) is the initial velocity, \(a\) represents the acceleration, and \(d\) stands for the displacement. This equation is especially useful when the time of travel is not known. For example, if a skier glides to a stop, we can use this kinematic relation to determine the acceleration during the glide. Understanding how to manipulate this equation is key to solving many physics problems involving motion along a straight line.
Acceleration
Acceleration is defined as the rate of change of velocity of an object. It is a vector quantity, meaning it has both magnitude and direction. In the context of our skiing problem, the acceleration describes how quickly the skier is slowing down. It can be calculated by rearranging the kinematic equation \(a = \frac{v_f^2 - v_i^2}{2d}\).

The negative sign in the calculated acceleration, \( -0.8 \text{ m/s}^2\), indicates that the skier is decelerating, or slowing down, as opposed to accelerating (speeding up). Thus, when we talk about 'magnitude' of acceleration, we refer to the absolute value, which in this case would be \(0.8 \text{ m/s}^2\) without any regard to the direction of motion.
Initial and Final Velocity
Initial velocity (\(v_i\)) and final velocity (\(v_f\)) are terms that describe the speed and direction of an object at the beginning and at the end of its motion, respectively. In our scenario with the cross-country skier, the initial velocity is the speed at which the skier is moving before she starts to slow down, while the final velocity is her speed after slowing down over a certain distance.

These two values are central to solving kinematics problems as they are often the known variables from which we need to find unknowns like acceleration or displacement. Understanding the relationship between initial and final velocities, along with acceleration, allows us to unravel the details of the skier's motion throughout her journey.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

II Haley is driving down a straight highway at 75 mph. A construction sign warns that the speed limit will drop to \(55 \mathrm{mph}\) in \(0.50 \mathrm{mi} .\) What constant acceleration (in \(\mathrm{m} / \mathrm{s}\) ) will bring Haley to this lower speed in the distance available?

Chameleons catch insects with their tongues, which they can rapidly exlend to great lengths. In a typical strike, the chameleon's tongue accelerates at a remarkable \(250 \mathrm{m} / \mathrm{s}^{2}\) for \(20 \mathrm{ms}\), then travels at constant speed for another \(30 \mathrm{ms}\). During this total time of \(50 \mathrm{ms}, 1 / 20\) of a second, how far does the tongue reach?

In an action movie, the villain is rescued from the ocean by grabbing onto the ladder hanging from a helicopter. He is so intent on gripping the ladder that he lets go of his briefcase of counterfeit money when he is \(130 \mathrm{m}\) above the water. If the briefcase hits the water \(6.0 \mathrm{s}\) later, what was the speed at which the helicopter was ascending?

In a 5000 m race, the athletes run \(12 \frac{1}{2}\) laps; each lap is \(400 \mathrm{m}\). Kara runs the race at a constant pace and finishes in 17.5 min. Hannah runs the race in a blistering \(15.3 \mathrm{min},\) so fast that she actually passes Kara during the race. How many laps has Hannah run when she passes Kara?

A Thomson's gazelle can reach a speed of \(13 \mathrm{m} / \mathrm{s}\) in \(3.0 \mathrm{s}\). A lion can reach a speed of \(9.5 \mathrm{m} / \mathrm{s}\) in \(1.0 \mathrm{s}\). A trout can reach a speed of \(2.8 \mathrm{m} / \mathrm{s}\) in \(0.12 \mathrm{s}\). Which animal has the largest acceleration?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.