/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 A cross-country skier is skiing ... [FREE SOLUTION] | 91Ó°ÊÓ

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A cross-country skier is skiing along at a zippy \(8.0 \mathrm{m} / \mathrm{s}\). She stops pushing and simply glides along, slowing to a reduced speed of \(6.0 \mathrm{m} / \mathrm{s}\) after gliding for \(5.0 \mathrm{m}\). What is the magnitude of her acceleration as she slows?

Short Answer

Expert verified
The skier's acceleration, as she slows down, is \(-0.8 m/s²\). The negative sign indicates deceleration.

Step by step solution

01

Identifying Given Values

From the exercise, the given values are: \nInitial velocity (\(v_i\)) = 8.0 m/s \nFinal velocity (\(v_f\)) = 6.0 m/s \nDistance (\(d\)) = 5.0 m
02

Use the Kinematic Equation

We use the kinematic equation \(v_f^2 = v_i^2 + 2ad\) where a is acceleration and d is the distance. The goal is to isolate a, the acceleration, so we need to rearrange this equation to: \(a = \frac{v_f^2 - v_i^2}{2d}\)
03

Substitution and Calculation

We substitute our given values into the Equation to solve for a: \(a = \frac{(6.0 m/s)^2 - (8.0 m/s)^2}{2 * (5.0 m)} = -0.8 m/s²\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematic Equations
Kinematic equations play a crucial role in describing the motion of objects under the influence of uniform acceleration. These equations relate various parameters of motion, such as initial velocity, final velocity, acceleration, time, and displacement. In physics problem solving, these kinematic equations are used to predict the final state of motion given some initial conditions.

One of the primary kinematic equations has the form \(v_f^2 = v_i^2 + 2ad\), where \(v_f\) is the final velocity, \(v_i\) is the initial velocity, \(a\) represents the acceleration, and \(d\) stands for the displacement. This equation is especially useful when the time of travel is not known. For example, if a skier glides to a stop, we can use this kinematic relation to determine the acceleration during the glide. Understanding how to manipulate this equation is key to solving many physics problems involving motion along a straight line.
Acceleration
Acceleration is defined as the rate of change of velocity of an object. It is a vector quantity, meaning it has both magnitude and direction. In the context of our skiing problem, the acceleration describes how quickly the skier is slowing down. It can be calculated by rearranging the kinematic equation \(a = \frac{v_f^2 - v_i^2}{2d}\).

The negative sign in the calculated acceleration, \( -0.8 \text{ m/s}^2\), indicates that the skier is decelerating, or slowing down, as opposed to accelerating (speeding up). Thus, when we talk about 'magnitude' of acceleration, we refer to the absolute value, which in this case would be \(0.8 \text{ m/s}^2\) without any regard to the direction of motion.
Initial and Final Velocity
Initial velocity (\(v_i\)) and final velocity (\(v_f\)) are terms that describe the speed and direction of an object at the beginning and at the end of its motion, respectively. In our scenario with the cross-country skier, the initial velocity is the speed at which the skier is moving before she starts to slow down, while the final velocity is her speed after slowing down over a certain distance.

These two values are central to solving kinematics problems as they are often the known variables from which we need to find unknowns like acceleration or displacement. Understanding the relationship between initial and final velocities, along with acceleration, allows us to unravel the details of the skier's motion throughout her journey.

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Most popular questions from this chapter

a. What constant acceleration, in SI units, must a car have to go from zero to 60 mph in 10 s? b. What fraction of \(g\) is this? c. How far has the car traveled when it reaches \(60 \mathrm{mph} ?\) Give your answer both in \(\mathrm{SI}\) units and in feet.

Certain insects can achieve seemingly impossible accelerations while jumping. The click beetle accelerates at an astonishing \(400 \mathrm{g}\) over a distance of \(0.60 \mathrm{cm}\) as it rapidly bends its thorax, making the "click" that gives it its name. a. Assuming the beetle jumps straight up, at what speed does it leave the ground? b. How much time is required for the beetle to reach this speed? c. Ignoring air resistance, how high would it go?

A driver has a reaction time of \(0.50 \mathrm{s}\), and the maximum deceleration of her car is \(6.0 \mathrm{m} / \mathrm{s}^{2}\). She is driving at \(20 \mathrm{m} / \mathrm{s}\) when suddenly she sees an obstacle in the road \(50 \mathrm{m}\) in front of her. Can she stop the car in time to avoid a collision?

A simple model for a person running the \(100 \mathrm{m}\) dash is to assume the sprinter runs with constant acceleration until reaching top speed, then maintains that speed through the finish line. If a sprinter reaches his top speed of \(11.2 \mathrm{m} / \mathrm{s}\) in \(2.14 \mathrm{s}\), what will be his total time?

Steelhead trout migrate upriver to spawn. Occasionally they need to leap up small waterfalls to continue their journey. Fortunately, steelhead are remarkable jumpers, capable of leaving the water at a speed of \(8.0 \mathrm{m} / \mathrm{s}\). a. What is the maximum height that a steelhead can jump? b. Leaving the water vertically at \(8.0 \mathrm{m} / \mathrm{s},\) a steelhead lands on the top of a waterfall \(1.8 \mathrm{m}\) high. How long is it in the air?

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