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The near point for your myopic uncle is \(10 \mathrm{cm} .\) Your own vision is normal; that is, your near point is \(25 \mathrm{cm} .\) Suppose you and your uncle hold dimes (which are \(1.7 \mathrm{cm}\) in diameter) at your respective near points. a. For you, what is the dime's angular size, in radians? b. For your uncle, what is the dime's angular size, in radians? c. Do these calculations suggest any benefit to nearsightedness?

Short Answer

Expert verified
The angular size of the dime for a person with normal vision is \( 0.068 \) radians, while the angular size of the dime for a person with myopia is \( 0.17 \) radians. Thus, for the myopic person, the dime appears larger, suggesting a potential benefit of nearsightedness in seeing closer objects more prominently.

Step by step solution

01

Calculate Angular Size for Normal Vision

Use the formula for angular size in radians \( \theta = \frac{s}{r} \). Substitute the given: \( s = 1.7 \mathrm{cm} \) and \( r = 25 \mathrm{cm} \). Therefore, \( \theta = \frac{1.7}{25} \). This will give the angular size of the dime for a person with normal vision.
02

Calculate Angular Size for Myopic Vision

Similarly, use the same formula \( \theta = \frac{s}{r} \). In this case, \( s = 1.7 \mathrm{cm} \) and \( r = 10 \mathrm{cm} \). Therefore, \( \theta = \frac{1.7}{10} \). This will give the angular size of the dime for a person with myopic vision.
03

Analyze the Results

Compare the two angular sizes obtained in the previous steps. A larger angular size implies that the dime appears larger. Thus, the one with the larger angular size sees the dime as bigger compared to the other person.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Size Calculation
Understanding the angular size of an object can be quite fascinating. It's all about figuring out just how big that object appears to be to our eyes when we look at it from a particular distance. The magic formula we use is actually quite straight-forward: \( \theta = \frac{s}{r} \), where \( \theta \) is the angular size in radians, \( s \) is the size of the object, and \( r \) is the distance from the object.

Imagine holding a coin at arm's length; the coin doesn't actually get smaller, right? But it certainly looks smaller than when it's right in front of your eyes. This is the idea behind angular size — it's all about the perceived size based on position and distance.

In our exercise, we're playing with a shiny dime to work out its angular size, once at 25 centimeters away – that's about an arm's length for some, and once at just a mere 10 centimeters – much closer! By doing the math with our handy formula, we get a clear picture of how large that dime appears to someone with typical vision and someone with myopic vision.
Myopic Vision
Now, when we talk about myopic vision, we're describing a scenario where things far away start getting a bit blurry, but boy oh boy, do things up close come into crystal clear focus. Myopia is a common eye condition often referred to as nearsightedness. With myopic eyes, looking at the stars might be tricky, but reading the fine print in a book? No sweat!

Our exercise highlights a charming quirk of myopia. When someone like our hypothetical uncle, who has nearsighted vision, holds a dime close up, due to his near point being at 10 centimeters, that dime looks bigger compared to someone with normal sight. This is because his eyes can focus at a closer range, making the angular size of the dime larger for him than it is for someone with normal vision.

Is There a Benefit to Nearsightedness?

While it's no fun squinting to see the movie screen from the back of the theatre, myopic individuals have their own little optical perk. They can enjoy larger-than-life details on objects held close, which can be handy for hobbies that require a keen eye for detail, like collecting stamps or painting miniatures.
Near Point in Optics
Talking about the near point in optics opens up a window to how we all see the world a little differently. The near point is the closest distance at which our eyes can still make an object out sharp and clear. Head to your near point, and you're in focus city; move closer than this, and everything starts to get blurry. Typically, for adults, this point can be anywhere from 10 to 25 centimeters.

For our exercise, we're comparing two near points – a 'normal' one at 25 centimeters, and our uncle's myopic near point at 10 centimeters. This discrepancy in near point distances is why the angular size of the dime appears differently for each person.

The concept of near point influences many aspects of our daily lives, from the ideal distance for reading a book to the way we design everything from phone screens to museum showcases, to ensure clarity and readability. Understanding one's near point is quite fundamental when tailoring tasks and activities to individual visual needs.

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Most popular questions from this chapter

In old Polaroid cameras, the image was projected on film that developed inside the camera. The developed image was then ejected from the camera as a printed photograph. The standard film size for one popular camera was 79 mm square. The film was \(116 \mathrm{mm}\) behind the lens. If you wanted a picture of your \(1.6-\mathrm{m}\) -tall friend to fill half the frame, how far away from you did she need to stand?

Oliver has had a stamp collection since he was a boy. In those days, holding a stamp \(10 \mathrm{cm}\) from his eye gave him a clear image. Now, his near point has receded to \(90 \mathrm{cm},\) so he holds a magnifying lens directly in front of his eye to let him bring stamps closer. To the nearest diopter, what power lens enables him to focus on a stamp \(10 \mathrm{cm}\) away?

Two lightbulbs are \(1.0 \mathrm{m}\) apart. From what distance can these lightbulbs be marginally resolved by a small telescope with a 4.0-cm-diameter objective lens? Assume that the lens is limited only by diffraction and \(\lambda=600 \mathrm{nm}\).

The rod and cone cells in the central part of the retina - the fovea - are packed closer together, giving a more detailed view. This area of increased rod and cone density has a diameter of about \(1.5 \mathrm{mm} .\) When you read a book, you want the image of the text you are reading to fall on the fovea. If you hold a book \(30 \mathrm{cm}\) from your eyes, how wide is the spot on the page whose image just fills the fovea? (Assume that the retina is \(1.7 \mathrm{cm}\) from the lens.)

Your telescope has an objective lens with a focal length of \(1.0 \mathrm{m} .\) You point the telescope at the moon, then realize that the eyepiece is missing. You can still see the real image of the moon formed by the objective lens if you place your eye a little past the image so as to view the rays diverging from the image plane, just as rays would diverge from an object at that location. What is the angular magnification of the moon if you view its real image from \(25 \mathrm{cm}\) away, your near-point distance?

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