/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 You are using a microscope with ... [FREE SOLUTION] | 91Ó°ÊÓ

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You are using a microscope with a \(10 \times\) eyepiece. What focal length of the objective lens will give a total magnification of \(200 \times ?\) Assume a length \(L=160 \mathrm{mm}\).

Short Answer

Expert verified
The focal length of the objective lens that will give a total magnification of \( 200 \times \) is \( 8 \mathrm{mm} \).

Step by step solution

01

Understand and arrange the formula.

The total magnification is the product of the eyepiece magnification and the objective lens magnification. The main formula to be used is: \( \text{Brightness}(B) = \text{Intensity}(I) * \text{Time}(T) \. Firstly, use the formula to express the objective magnification: \( \text{Objective magnification} = \text{Total magnification} / \text{Eyepiece magnification} \). Then, express the objective magnification as: \( \text{Objective magnification} = \text{Tube Length} / \text{Focal length of the objective} \).
02

Calculate the objective magnification.

Substitute \( \text{Total magnification} = 200 \times \) and \( \text{Eyepiece magnification} = 10 \times \) into the formula: \( \text{Objective magnification} = \text{Total magnification} / \text{Eyepiece magnification} = 200 / 10 = 20 \times \).
03

Determine the focal length.

Substitute \( \text{Tube Length} = 160 \mathrm{mm} \) and \( \text{Objective magnification} = 20 \times \) into the formula: \( \text{Focal length of the objective} = \text{Tube Length} / \text{Objective magnification} = 160 / 20 = 8 \mathrm{mm} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Focal Length Calculation
Calculating the focal length of an objective lens in a microscope is a key foundational concept. This calculation determines how the microscope amplifies the image of the specimen being viewed. In our specific example, with a total magnification requirement of \(200 \times\) and a \(10 \times\) eyepiece, we find the objective magnification first. The formula to determine the magnification from the objective and eyepiece combined is:
  • Objective Magnification = \( \frac{\text{Total Magnification}}{\text{Eyepiece Magnification}} \)
For this case, the calculation is straightforward: \( \frac{200}{10}=20 \times \).
Once we know the objective magnification, we can compute the focal length using:
  • Focal Length of the Objective = \( \frac{\text{Tube Length}}{\text{Objective Magnification}} \)
Substituting the values, \( \frac{160 \text{ mm}}{20} = 8 \text{ mm} \), we find the focal length of the objective is 8 mm.
Objective Lens
The objective lens in a microscope is the lens closest to the specimen. It is critical for image formation and largely determines the microscope's strength. The lens collects light from the specimen and focuses it inside the microscope tube.
Different objective lenses have different focal lengths, which impact their magnification power. The shorter the focal length, the higher the potential magnification.
  • The focal length of the objective influences the field of view and depth of field.
  • In our exercise, an objective focusing at 8 mm provides images magnified 20 times.
Understanding the objective lens's role helps in selecting the right lens for examining specimens at different magnification levels.
Eyepiece Magnification
The eyepiece, or ocular lens, is the lens through which you look into the microscope. Its magnification is typically marked on the eyepiece itself, indicating how much it enlarges the image further after the objective lens.
  • The eyepiece in our example provides a magnification of \(10 \times\).
  • This value is used in calculating the total magnification when combined with the objective's magnification.
The eyepiece's simplicity in multiplying an image allows for the final total magnification of the specimen, combining its effects with the objective to achieve the microscope's full potential.
Total Magnification
Total magnification in microscopy is the product of individual magnification powers of the eyepiece and the objective lens. It defines how much larger the image of your specimen appears compared to its actual size.
  • Given by \( \text{Eyepiece Magnification} \times \text{Objective Magnification} \).
  • In our example, it is \(10 \times 20 = 200 \times\).
This overall magnification dictates the microscope's ability to detail the smallest structures in a specimen and allows for observation at much finer scales. Understanding how this magnification works allows users to accurately select the appropriate lenses for their needs.
Physics Problem Solving
Solving physics problems, such as the one involving microscope magnification, involves understanding the relationship between physical concepts and applying appropriate formulas.
Here's a quick guide to effective problem solving:
  • Identify the quantities involved—such as magnification or focal length.
  • Understand the relationship between these quantities. For instance, how objective and eyepiece magnifications combine.
  • Use equations to link known values and discover unknowns, as seen in calculating total magnification.
  • Check units and scales to ensure results are sensible (e.g., millimeters for focal length).
Practicing these steps helps solidify understanding and hones problem-solving skills critical for studying physics.

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Most popular questions from this chapter

A pinhole camera is made from an \(80-\mathrm{cm}-\) long box with a small hole in one end. If the hole is \(5.0 \mathrm{m}\) from a \(1.8-\mathrm{m}\) -tall person, how tall will the image of the person on the detector be? You are taking a picture of a giraffe that is standing far away from you. The image is just too small, so you swap the \(50-\mathrm{mm}-\) focal-length lens in your camera for a \(600 \mathrm{mm}\) telephoto lens. By what factor does this increase the size of the image?

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A \(1.0-\mathrm{cm}\) -diameter microscope objective has a focal length of \(2.8 \mathrm{mm} .\) It is used with light of wavelength of \(550 \mathrm{nm}\). a. What is the objective's resolving power if used in air? b. What is the resolving power of the objective if it is used in an oil- immersion microscope with \(n_{\text {eal }}=1.45 ?\)

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