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A diverging mirror, like the passenger-side rearview mirror on a car, has a focal length of \(-2.0 \mathrm{m}\). An object is \(4.0 \mathrm{m}\) from the mirror. Use ray tracing to determine the location of its image. Is the image upright or inverted? Is it real or virtual?

Short Answer

Expert verified
The mirror forms a virtual, upright, and diminished image at a distance of \(-1.33 \mathrm{m}\) from the mirror.

Step by step solution

01

Determine the Focal Length

First, analyze the focal length of the diverging mirror. According the problem, the focal length \(f\) is \(-2.0m\). It's negative because it's diverging and not converging.
02

Determine the Object Distance

Next, the object distance \(u\) needs to be identified. As stated, the object's distance from the mirror is \(4.0m\). Keep in mind this value is positive as the object is in front of the mirror.
03

Applying the Mirror Formula

Now, use the mirror formula to find the image distance \(v\). The mirror formula is \(1/f = 1/v + 1/u\). Substitute the given values into the formula to solve for \(v\): \(1/-2 = 1/v + 1/4\). Simplifying gives \(1/v = -1/2 - 1/4 = -3/4\). Inverting both sides, the image distance \(v\) is \(-4/3m\) or \(-1.33m\).
04

Identify the Image Type and Orientation

The negative value for \(v\) indicates the image is formed on the same side as the object, which means it's a virtual image, formed by the apparent divergence of light rays. Also, the value is less than the object distance, thereby indicating it's diminished. Additionally, diverging mirrors always form upright (right-side up) images. So, in this case, the image is upright.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Focal Length
The focal length of a mirror is a measure of how strongly it converges or diverges light. It is defined as the distance from the mirror to the focal point, which is where parallel rays of light either converge or appear to diverge after reflecting off the mirror surface. For a diverging mirror (also known as a convex mirror), the focal length is considered negative because it causes light rays to spread out, meaning the focal point is behind the mirror. For example, if a diverging mirror has a focal length of (-2.0 m), it indicates the virtual focal point stands 2 meters behind the mirror. This information is crucial for constructing ray diagrams and using the mirror formula to determine the properties of an image.
Object Distance
Object distance, denoted by the symbol (u), is the distance from the object to the mirror along the principal axis. It is always positive if the object is in front of the mirror, the usual scenario. Knowing the object distance is essential when applying the mirror formula to locate an image. It is also an important factor that affects the size of the image produced. A larger object distance in association with a diverging mirror typically results in a smaller, diminished image since the mirror spreads the light rays further apart.
Mirror Formula
The mirror formula is a mathematical equation that relates the focal length (f), object distance (u), and image distance (v) of a spherical mirror. It's expressed as \(\frac{1}{f} = \frac{1}{v} + \frac{1}{u}\). In the case of a diverging mirror, the formula helps to determine where the image will form and its characteristics. Since diverging mirrors always produce virtual images, the solution for the image distance (v) will always turn out negative, indicating the image formation on the same side as the object. This formula is fundamental in optics as it provides quantitative analysis of image formation without the need for constructing ray diagrams.
Virtual Image
A virtual image is a type of image formed when the outgoing rays from a point on an object diverge, and it appears to come from a location in the optical system where light does not really come from. In simpler terms, it's an image that cannot be projected onto a screen because it's formed by light rays that appear to be coming from a common point, but never actually converge. Virtual images are always located behind the mirror and can be seen when looking directly at the mirror, but you can't interact with them like real images. In the context of diverging mirrors, the virtual image formed is upright and diminished compared to the object, making these mirrors useful for applications where a wide field of view is needed, such as the passenger-side rearview mirror on a car.

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Most popular questions from this chapter

A flashlight uses a small lightbulb placed in front of a converging mirror. The light from the bulb should reflect from the mirror and emerge as a tight beam of light-a series of parallel rays. Where should the bulb be placed relative to the mirror?

A dentist uses a curved mirror to view the back side of teeth on the upper jaw. Suppose she wants an erect image with a magnification of 2.0 when the mirror is \(1.2 \mathrm{cm}\) from a tooth. (Treat this problem as though the object and image lie along a straight line.) Use ray tracing to decide whether a converging or diverging mirror is needed, and to estimate its focal length.

A 1.5-cm-tall object is 90 \(\mathrm{cm}\) in front of a diverging lens that has a \(45 \mathrm{cm}\) focal length. Use ray tracing to find the position and height of the image. To do this accurately, use a ruler or paper with a grid. Determine the image distance and image height by making measurements on your diagram.

You slowly back away from a plane mirror at a speed of \(0.10 \mathrm{m} / \mathrm{s} .\) With what speed does your image appear to be moving away from you?

A photographer took this image of himself in a converging mirror. Give some thought to what you are seeing here: One of the hands is his left hand; the other is the image of his left hand. Given the relative sizes and positions of his hand and the image of his hand, how far from the mirror did he place his hand to take this photo? Express your answer in terms of \(f\), the mirror's focal length.

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