/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 A biologist keeps a specimen of ... [FREE SOLUTION] | 91Ó°ÊÓ

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A biologist keeps a specimen of his favorite beetle embedded in a cube of polystyrene plastic. The hapless bug appears to be \(2.0 \mathrm{cm}\) within the plastic. What is the beetle's actual distance beneath the surface?

Short Answer

Expert verified
The actual distance of the beetle beneath the surface is \(3.18 \mathrm{cm}\).

Step by step solution

01

Understand the principles

We use the formula of apparent depth which is defined as the depth that an object seems to be at because of the refraction of light in a transparent medium. The formula is: apparent depth = actual depth / refractive index.
02

Substitute the given values

The apparent depth is given as \(2.0 \mathrm{cm}\) and the refractive index of polystyrene plastic is \(1.59\). So, we substitute these values in the formula and solve for the actual depth.
03

Solve the equation

Rearranging the formula to solve for actual depth gives us: actual depth = apparent depth * refractive index = \(2.0 \mathrm{cm} * 1.59 = 3.18 \mathrm{cm}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Refraction of Light
When we observe objects in water or through a glass window, they sometimes appear distorted or in a different position than where they actually are. This phenomenon is due to the refraction of light, a concept crucial to understanding optics in physics. Refraction occurs when light waves travel from one medium to another with different densities, causing the light to change speed and direction.

For example, consider a straw in a glass of water; it appears to bend at the water's surface. This bending is due to light from the straw entering your eyes after being refracted at the interface between water and air. Refraction is governed by Snell's Law, which provides a mathematical relation between the angles of incidence and refraction and the refractive indices of the two media. This law helps in calculating the apparent shift in position of objects, known as the 'apparent depth', which is crucial in fields like biology, where specimens might be observed under different media.
Refractive Index
In the exercise concerning the biologist's beetle encased in a cube of polystyrene, a key term arises: refractive index. The refractive index (often denoted as 'n') is a dimensionless number that describes how light propagates through a medium. It's defined as the ratio of the speed of light in a vacuum to the speed of light in the medium being considered.

Each material has a characteristic refractive index; for instance, air has a refractive index of approximately 1, while glass, diamonds, and water have higher values. In the given problem, the polystyrene has a refractive index of 1.59, indicating that light travels slower in polystyrene than in air. When solving for the beetle's actual depth, this refractive index plays a critical role as the apparent depth is inversely proportional to it.
Optics in Physics
Optics is a branch of physics that deals with the study of light and its interactions with matter. It encompasses a range of phenomena including reflection, refraction, diffraction, and dispersion. The investigation of optics helps us understand how lenses work, the function of optical instruments like microscopes or telescopes, and even the principles behind sophisticated technologies like fiber optics.

In the context of the biologist's beetle, optics explains why the beetle seems closer to the surface when viewed through the polystyrene. It's the same principle that allows glasses to correct vision and cameras to capture images. Understanding optics is fundamental not just for physicists, but for anyone involved in fields that require manipulation or analysis of light, such as engineering, photography, or even ophthalmology. By mastering concepts such as the refractive index and light refraction, one can better understand and apply the underlying physics in practical situations.

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Most popular questions from this chapter

A 2.0 -cm-tall object is located \(8.0 \mathrm{cm}\) in front of a converging lens with a focal length of \(10 \mathrm{cm}\). Use ray tracing to determine the location and height of the image. Is the image upright or inverted? Is it real or virtual?

A light ray travels inside a horizontal plate of glass, striking its upper surface at an angle of incidence of \(60^{\circ} .\) This ray is totally internally reflected at the glass-air boundary. A liquid is then poured on top of the glass. What is the largest index of refraction that the liquid could have such that the ray is still totally internally reflected?

A converging cosmetic mirror has a focal length of \(40 \mathrm{cm} .\) A \(5-\mathrm{cm}-\mathrm{long}\) mascara brush is held upright \(20 \mathrm{cm}\) from the mirror. Use ray tracing to determine the location and height of its image. Is the image upright or inverted? Is it real or virtual?

The illumination lights in an operating room use a converging mirror to focus an image of a bright lamp onto the surgical site. One such light has a mirror with a focal length of \(15 \mathrm{cm} .\) If the patient is \(1.0 \mathrm{m}\) from the mirror, where should the lamp be placed relative to the mirror?

The sun is \(150,000,000 \mathrm{km}\) from earth; its diameter is \(1,400,000 \mathrm{km}\) For a science project on solar For a science project on solar power, a student uses a 24 -cm-diameter converging mirror with a focal length of \(45 \mathrm{cm}\) to focus sunlight onto an object. This casts an image of the sun on the object. For the most intense heat, the image of the sun should be in focus. a. Where should the object be placed? b. What is the diameter of the image? c. The intensity of the incoming sunlight is \(1050 \mathrm{W} / \mathrm{m}^{2} .\) What is the total power of the light captured by the mirror? d. What is the intensity of sunlight in the projected image? Assume that all of the light captured by the mirror is focused into the image.

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